A chemist mixes two liquids together. The reaction produces a gas and a solid. According to the law of conservation of mass, what should the chemist observe when she compares the total masses of the substances before and after the reaction? A.The masses are equal. B.The masses are inconsistent. C.The mass of the substances before the reaction is greater than the mass of the substances after the reaction. D.The mass of the substances before the reaction is less than the mass of the substances after the reaction.

Answers

Answer 1

Answer: A is the answer. Because the masses are equal.

Answer 2

Answer: The answer is (A.) The masses are equal. (The law of conservation of mass says that mass cannot be created (added) or destroyed. So the total mass must be the same before and after. Hopefully, this helps)

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What is the total number of moles of solute in 250 milliliters of a 1.0 M solution of NaCl

Answers

First, the Molarity equation is M = mol/L. However, the problem is looking for the TOTAL NUMBER OF MOLES in which will have you to reposition the said equation: mol = M/L. Observe that you need L not mL, so you need to convert 250 mL to L that will results to .25 L. Then, substitute the value of the units to the formula and you should be able to get 4 moles.

Answer:

0.25

Explanation:

Use the periodic table to identify the element represented by each of the following electron configurations. [He]2s2: ?

Answers

Answer:

Be. Beryllium

Explanation:

According to VSEPR theory, what causes water molecules to have a bent shape? A. the unusual location of the free electrons. . B. repulsive forces between specific lone pairs of electrons. . C. attraction between the fixed orbitals of the unshared pairs of oxygen electrons. . D. ionic attraction and repulsion

Answers

According to VSEPR theory, what causes water molecules to have a bent shape?

Answer: Out of all the options presented above the one that best represents what causes water molecules to have a bent shape according to VSEPR theory is answer choice B) repulsive forces between specific lone pairs of electrons. the bond angle in a water molecule is bent.

I hope it helps, Regards.

The correct answer is $\boxed{{\text{option }}\left( {\text{B}} \right)}$ that is repulsive forces between specific lone pairs of electrons.

Further Explanation:

The total number of valence electrons of ${{\text{H}}_2}{\text{O}}$ is calculated as,

Total valence electrons (TVE) = [(1) (Valence electrons of O) + (2) (Valence electrons of H)]

$\begin{aligned}{\text{Total valence electrons}}\left( {{\text{TVE}}}\right)&=\left[{\left({\text{1}}\right)\left({\text{6}}\right)+\left({\text{2}}\right)\left({\text{1}}\right)}\right]\n&=8\n\end{aligned}$

In ${{\text{H}}_2}{\text{O}}$ , the total number of valence electrons is 8. Here, oxygen forms single bond with the hydrogen atom and therefore, 2 pair of electrons are used in the formation of two single bonds with hydrogen atom. Remaining 2 pair of electrons are used to complete the octet of oxygen atom. Therefore, ${{\mathbf{H}}_{\mathbf{2}}}{\mathbf{O}}$ contains two bond pairs and two lone pairs (refer to the image attached).

According to the VSEPR theory, central atom oxygen has two bond pair with two lone pair, therefore, ${{\text{H}}_2}{\text{O}}$ has an ${\text{A}}{{\text{B}}_2}{{\text{E}}_2}$ arrangement. Therefore, these four pairs of electrons spread out as tetrahedral arrangement to minimize lone pair-lone pair and bond pair-bond pair repulsion. Since lone pairs are not considered in the shape of the molecule and therefore, the final shape of water molecule is bent-shape.

Learn more:

1. Molecular shape around the central atom in the amino acid glycine: brainly.com/question/4341225

2. Balanced chemical equation: brainly.com/question/1405182

Answer details:

Grade: Senior School

Subject: Chemistry

Chapter: Covalent bonding and molecular structure

Keywords: hybridization, water, geometry, sp3, steric number, 3, p orbital, s orbital, Lewis structure, hybridization of water, central atom, carbon, hydrogen, oxygen, shape, double bond, h2o.

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