Hess's law ____. A) makes it possible to calculate ΔH for complicated chemical reactions B) states that when you reverse a chemical equation, the sign of ΔH does not change. C) determines the way a calorimeter works D) describes the vaporization of solids

Answers

Answer 1

Answer: A.) makes it possible to calculate ΔH for complicated chemical reactions

Hess’s Law makes it possible to calculate ΔH for complicated chemical reactions. Moreover, the principle claims that the entire amount of “enthalpy” when the development or progression of a chemical reaction is complete whether the reactions are created in a single or numerous processes, it still changes. This law is now described as the principle of conservation of energy, and part of the thermodynamics law as the first.

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which statement describes all chemical changes but not all physical changes a bubbles are produced b a new substance forms c phase changes occur D a color change occurs

Match each of the following forms of sugar to its best description?

Answers

The chemical processing breaks…. corn starch,a disaccharide characterized… to sucrose,a simple, six-carbon cycloalkane…corn syrup,a homopoloymer of glucose is corn starch, chemical processing of corn syrup… high fructose corn syrup.

What is glucose ?

A basic sugar, glucose has the chemical formula C6H12O6. The most prevalent monosaccharide, a type of carbohydrate, is glucose.

The primary form of sugar in the blood, glucose serves as the body's cells' main source of energy. Glucose can be produced by the body from other chemicals, or it can be obtained from the meals we eat. The bloodstream carries glucose to the cells. Insulin is one of many hormones that regulate blood glucose levels.

The brain is the most energy-hungry organ in the body and uses half of the body's sugar energy due to its abundance of nerve cells, or neurons. Thinking, memory, and learning are all tightly correlated with blood glucose levels and how effectively the brain uses this substance.

Thus, a homopoloymer of glucose is corn starch.

To learn more about glucose, follow the link;

brainly.com/question/2396657

#SPJ12

Sucrose, a sweet, white crystalline substance, C12 H22 O11, OBTAINED CHIEFLY FROM THE JUICE OF THE SUGAR CANE AND SUGAR BEET, BUT ALSO PRESENT IN SORGHUM, THE sugar maple, some palms, and various other plants, and having extensive nutritional, pharmaceutical, and industrial uses; any of the class of carbohydrates to which this substance belongs, as glucose, levulose, and lactose.

How doesthe pressure inside a rigid container change if the
absolute temperature of the gas inside is quadrupled?

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Answer:It quadruples

Explanation:

How much of a 5.0 g sample of strontium-90 will remain after 87 years?

Answers

Since radioacitive decay fallows first order kinetics you can use the equation lnA(t)=-kt+lnA₀.
A₀=the initial amount of sample
A(t)=the amount of sample after t years
t=time
k=rate constant

First you need to solve for the rate constant (k) to get the equation
-((lnA(t)-lnA(0))/t=k which can simplify into k=-ln(A(t)/A₀)/t which can then be simplified further to ln(A₀/A(t))/t=k. I think the half life of strontium-90 is 28.8 years which means that when t=28.8 years, A(t) is going to equal 1/2 of A₀ and you can make the equation k=ln2/28.8 to get k=0.02408.

Now you need to solve for A(t) in the equation ln(A(t))=-kt+lnA₀ to get A(t)=e^(-kt+lnA₀) which simplifies to A(t)=A₀e^-kt. When you plug t=87, A₀=5g, and k=0.02408 into that equation you should get 0.616g.

Therefore after 87 years you will have 0.616g of strontium-90 if you started with a 5g sample.

I hope this helps. Let me know in the comments if anything is unclear.

Can you provide an example for both fission and fusion

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fission energy is gained by splitting apart heavy atoms fusion is combining light atoms

The average atomic mass of oxygen is 15.9994 amu. The atomic masses of its three isotopes are as follows: O-16: 15.995 amu; O-17: 16.999 amu; O-18: 17.999 amu Which isotope is most likely to have the greatest abundance in nature?

Answers

Answer:

O-16 isotope is most likely to have the greatest abundance in nature.

Explanation:

Atomic mass of an isotopes of oxygen elements:

O-16: 15.995 amu
O-17: 16.999 amu
O-18: 17.999 amu

Average atomic mass of an oxygen atom = 15.994 amu

Isotope with the value of atomic mass closest to the average atomic mass of the oxygen atom will have the greatest abundance in nature. As it will be found in much more greater extent in nature.

Where as isotope which is least close to the average atomic mass will have less abundance in nature.

O-16 isotope is most likely to have the greatest abundance in nature.

15.995 amu ≈ 15.994 amu

Which subatomic particle is not found in the nucleus of an atom

Answers

Only subatomic particle NOT found in the nucleus

would be Electrons

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