Why is the equation incorrect? Mg₃ + N₂ → Mg₃N₂(A) Some of the subscripts are incorrectly used.
(B) The equation is not balanced.
(C) The valence of the nitride ion is incorrect.
(D) The valance of the magnesium ion is incorrect.
(E) The coefficient of N₂ is incorrect.
Can someone explain this one?
Answers
Related Questions
What year did tin got discovers and by whom tin is a element please help
What is a chemical bond? A. The attraction of two atoms that holds the atoms together B. A substance that's composed of atoms C. A representation of chemical properties D. The force that holds together the elements in a compound
For a cell whose potential is -0.46 v with 3 moles of electrons exchanged, what is DG?DG = -nFE°cella.) -133 kJb.) +133 kJc.) +133,170 kJd.) -6.65 x 10^-3
A chemist places a flask containing the reactants in an ice bath. This will _____ the rate of the reaction. increase decrease
-sodium
-phosphorus
-potassium
-oxygen
-iodine
-cesium
-bromine
-sulfur
-magnesium
Please answer!! Its really important..
Answers
Answer : Lending makes the element as cation (positively charged species) and borrowing makes the element as anion (negatively charged species).
Usually all the metal species donates the electrons and non-metals accepts (borrows) the electrons.
Sodium (Na) donates 1 electron and becomes .
Phosphorus (P) accepts 3 electrons and becomes an anion of phosphorus .
Potassium (K) donates its one electron and gets converted to .
Oxygen (O) accepts 2 electrons and turns as .
Iodine (I) accepts one electron and gets converted into .
Cesium (Cs) donates 1 electron and turns to .
Bromine (Br) accepts 1 electron and turns as .
Sulfur (S) accepts 2 electrons and becomes.
Magnesium (Mg) donates its 2 electrons and gets converted as .
Phosphorus borrows 3 electrons.
Potassium lends one electron.
Oxygen borrows 2 electrons.
Iodine borrows one electron.
Cesium lends 1 electron.
Bromine borrows 1 electron.
Sulfur borrows 2 electrons.
And magnesium lends 2 electrons.
Answers
Answer:We can use the formula for the volume of a rectangular solid, V = lwh, where l, w, and h represent the length, width, and height of the solid, respectively. In this case, we are looking for the thickness of the aluminum sheet, so we can use h to represent the thickness.
Given:
l = 52.5 cm
w = 23.2 cm
V = 2.95 cm^3
We need to solve for h:
V = lwh
2.95 cm^3 = (52.5 cm)(23.2 cm)(h)
Divide both sides by (52.5 cm)(23.2 cm):
h = 2.95 cm^3 / (52.5 cm)(23.2 cm)
h = 0.00252 cm or 0.0252 mm (rounded to four decimal places)
Therefore, the thickness of the aluminum sheet is approximately 0.0025 cm or 0.0252 mm.
Explanation:I'm just built different
Answers
Final answer:
Silver and gold are two elements which have properties similar to copper. These common properties include sheen, malleability, ductility, and their ability to conduct heat and electricity, attributable to their similar atomic structures.
Explanation:
Two elements that have properties similar to copper, which is a metal, include silver (Ag) and gold (Au). All these elements fit into the same category - metals, that demonstrate certain characteristics:
- They appear shiny, and have the ability to be formed into different shapes (malleable) and drawn into wires (ductile).
- They act as good conductors of heat and electricity.
These properties stem from their similar atomic structures, placed in the same group on the periodic table.
Learn more about Similar Elements to Copper here:
#SPJ3
brief it
Answers
Answer:
scientific approach
Explanation:
Method of investigation in which a problems is First identified and observations, experiment are done
Answers
we know that the heat supplied to decompose the compound.In the result the product H2O is assumed to be in the vapor state so that is gas.
hope it helps
Final answer:
The decomposition of Nickel(II) hydroxide produces Nickel(II) oxide and water. The chemical equation is: Ni(OH)2 (s) → NiO (s) + H2O (l).
Explanation:
The decomposition reaction of Nickel(II) hydroxide into Nickel(II) oxide and water can be written as follows: Ni(OH)2 (s) → NiO (s) + H2O (l) . In this reaction, solid Nickel(II) hydroxide decomposes into solid Nickel(II) oxide and liquid water. It’s important to remember that in these reactions, a single, complex reactant breaks down into multiple, simpler products.
Learn more about Decomposition Reaction here:
#SPJ11
Answers
anode reaction: Ag(s)+HCl(aq)⇒H⁺+AgCl(s)+e⁻
which means that H⁺ is the oxidizing agent
cathode reaction: 2H⁺(aq)+2e⁻⇒H₂(g)
and the cell reaction is the combination of the anode and cathode reactions.
cell reaction: 2Ag(s)+2HCl(aq)⇒2AgCl(s)+H₂(g)