How does an acid–base indicator react when placed in an acidic solution?It changes color.
It dissolves.
It increases the pH of the solution.
It releases hydroxide ions.

Answers

Answer 1

Answer:

Answer: Option (a) is the correct answer.

Explanation:

An acid-base indicator is an indicator which changes color according to the pH of solution in which it is placed.

For example, phenolphthalein is an acid-base indicator.

Thus, we can conclude that out of the given options, an acid–base indicator react by changing color when placed in an acidic solution, is the correct option.

Answer 2

Answer: an indicator changes color when placed in an acidic solution

Answer: Convection

Explanation: apex 1/10/2020

If the pressure P applied to a gas is increased while the gas is held at a constant temperature, then the volume V of the gas will decrease. The rate of change of the volume of gas with respect to the pressure is proportional to the reciprocal of the square of the pressure. Which of the following is a differential equation that could describe this relationship?

Answers

The differential relationship has been $\rm \bold{(dV)/(dP)\;=\;(C)/(P^2)}$ .

The gas has been termed to be the ideal gas. For an ideal gas at a constant temperature, the relationship of the change in pressure and volume can be given as constant. The relationship has been given with the application of Boyle's law.

The product of the pressure and volume has been a constant quantity for a reaction.

Pressure $*$ Volume = Constant

PV = C

V = $\rm (C)/(P)$

Differentiating the equation:

$\rm (dV)/(dt)\;=\;(C)/(P^2)\;(dP)/(dt)$

$\rm (dV)/(dt)\;*\;(dt)/(dP)\;=\;(C)/(P^2)$

$\rm (dV)/(dP)\;=\;(C)/(P^2)$

The differential relationship has been $\rm \bold{(dV)/(dP)\;=\;(C)/(P^2)}$ .

For more information about pressure at a constant temperature, refer to the link:

brainly.com/question/12152879?

Answer:

A differential equation that could describe the relationship of the rate of change of the volume of gas with respect to the pressure is;

V' = $-(C)/(P^2)$ .

Explanation:

Boyle's law states that at constant temperature, the pressure of a given mass of gas is inversely proportional to its volume.

That is;

P₁×V₁ = P₂×V₂ or

P×V = Constant, C

That is V = $(C)/(P)$

Therefore, the rate of change of volume of a gas is given as

$(dV)/(dt) = -(C)/(P^2) (dP)/(dt)$ which gives

$(dV)/(dt) * (dt)/(dP)= (dV)/(dP) = -(C)/(P^2)$

That is the rate of change of the volume of gas with respect to the pressure is proportional to the reciprocal of the square of the pressure.

$(dV)/(dP) = -(C)/(P^2)$ .

V' = $-(C)/(P^2)$ .

In the following reaction, how many grams of NaBr will react with 311 grams of Pb(NO3)2?pb(no3)2(aq)+2NaBr(g) -> PbBr2(s) + 2NaNO3(aq)
The molar mass of NaBr is 102.9 grams and that of Pb(NO3)2 is 331.21 grams.

Answers

Answer: 193.4 grams

Explanation: According to avogadro's law, 1 mole of every substance weighs equal to the molecular mass and contains avogadro's number $6.023* 10^(23)$ of particles.