There are 10 vehicles in a parking lot: 3 SUVs and 7 trucks. What is the probability that any 7 randomly chosen parking spots have 2 SUVs and 5 trucks OR 3 SUVs and 4 trucks?

Answers

Answer 1
Answer: We have to calculate the probability that any randomly choosen parking spots have 2 SUVs and 5 trucks or 3 SUVs and 4 trucks. We will use the formula with combinations: P = ( 3C2 * 7C5 ) / ( 10C7) + ( 3C3 * 4C7) / ( 10C7). For example: 10C7 = 10! / 7!*(10-7)! = 10!/7!*3!= 10*9*8/3*2*1 = 120, etc. P = ( 3 * 21 ) / 120 + ( 1 * 35 ) / 120 = 63 / 120 + 35 / 120 = 98 / 120 = 0.8166. Answer: The probability is 0.8166 or 81.66%.

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Solve for X
126°
3x

Vertical angles

Answers

Answer:

42

Step-by-step explanation:

simply divide 126 by 3

3x = 126
X = 42

Vertical angles are congruent :)

A credit card issuer charges an APR of 15.77%, and its billing cycle is 30 days long. What is it periodic interest rate?

Answers

Given:
Billing cycle = 30 days long
APR = 15.77%

There is 365 days in a year.

365 / 30 = 12.17

15.77% / 12.17 = 1.2958% or 1.30%

The periodic interest rate is 1.30%.

Answer:

1.30%

Step-by-step explanation:

I just answered it

Which number is equivalent to 3⁴÷3² This problem comes straight from a standardized test given in New York in 2014.

Answers

Answer:

9

Step-by-step explanation:

3^4 / 3^2 = 3^(4 - 2)

= 3^2
= 9

A quadratic equation is shown below:x2 − 8x + 13 = 0

Which of the following is the first correct step to write the above equation in the form (x − p)2 = q, where p and q are integers?
Subtract 5 from both sides of the equation

Add 3 to both sides of the equation

Add 5 to both sides of the equation

Subtract 3 from both sides of the equation

Answers

The given quadratic equation can be represented in the form (x-p)^2 = q

by adding 3 to both sides of the equation.

What is a quadratic equation?

The polynomial equation whose highest degree is two is called a quadratic equation. The equation is given by

ax^2 + bx + c = 0

where a\neq 0.

The given quadratic equation is

x^2 - 8x + 13 = 0

Case 1: Subtract 5 from both sides of the equation

i.e.  x^2 - 8x + 13 - 5 = 0 - 5

⇒   x^2 - 8x + 8 = -5

The LHS of the above equation can not be expressed in (x-p)^2 form. Hence, it is not the correct step.

Case 2: Add 3 to both sides of the equation.

i.e. x^2 - 8x + 13 +3 = 0 + 3

⇒  x^2 - 8x + 16 = 3

⇒  x^2 - 2* x * 4 + (4)^2 =3

⇒  (x - 4)^2 = 3

The above equation is expressed in (x-p)^2 = q form where p = 4 and q = 3.

Case 3: Add 5 to both sides of the equation

i.e. x^2 - 8x + 13 + 5 = 0+5

⇒   x^2 - 8x + 18 = 5

The LHS of the above equation can not be expressed in the (x-p)^2. Hence, it is not the correct step.

Case 4: Subtract 3 from both sides of the equation

i.e. x^2 - 8x + 13 - 3 = 0-3

⇒   x^2 - 8x + 10 = -3

The LHS of the above equation can not be expressed in the (x-p)^2. Hence, it is not the correct step.

Hence, "Add 3 to both sides of the equation" is the correct step.

Learn more about quadratic equations here:

brainly.com/question/2263981?referrer=searchResults

#SPJ2

Add 3 to both sides, so you will have

x^2 - 8x + 13 + 3 = 3
x^2 -8x + 16 = 3

And now the left side is a perfect square trinolmial: (x-4)^2.

abbie spent 5/8 of her money and saved the rest. if she spent 45,how much money did she have at first?

Answers

$72

Further explanation

Given:

Abbie spent ⁵/₈ of her money and saved the rest.

She spent $45.

Question:

How much money did she have at first?

The Process:

The meaning of "Abbie spent ⁵/₈ of her money" is that she has spent 5 of the 8 parts of the money she had at first.

Let us make a pattern of 8 units for the amount of money that Abbie had at first.

\boxed{\cdot}\boxed{\cdot}\boxed{\cdot}\boxed{\cdot}\boxed{\cdot}\boxed{\cdot}\boxed{\cdot}\boxed{\cdot}

Since Abbie spent ⁵/₈ of her money, then we create a pattern of 5 units containing $9 each. Recall that \boxed{\$ 45 / 5 = \$ 9}

\boxed{\$ 9}\boxed{\$ 9}\boxed{\$ 9}\boxed{\$ 9}\boxed{\$ 9} = \$ 45

From the pattern above, we can see that \boxed{ \ 1 \ unit = \$ 9 \ }.

Let us calculate how much money Abbie had at first.

\boxed{ \ 1 \ unit = \$ 9 \ }

\boxed{ \ 8 \ unit = \ ? \ }

\boxed{ \ 8 * \$ 9 = \$ 72 \ }

Thus, the money Abbie had at first is $72.

The complete pattern of Abbie's initial money is as follows:

\boxed{\$ 9}\boxed{\$ 9}\boxed{\$ 9}\boxed{\$ 9}\boxed{\$ 9}\boxed{\$ 9}\boxed{\$ 9}\boxed{\$ 9} = \$ 72

- - - - - - - - - -

Quick Steps:

Let M as Abbie's initial money.

\boxed{ \ (5)/(8) * M = \$ 45 \ }

Both sides are multiplied by ⁸/₅ so that M is the subject alone on the left side.

\boxed{ \ M = (8)/(5) * \$ 45 \ }

We crossed out 5 and 45.

\boxed{ \ M = 8 * \$ 9 \ }

\boxed{ \ M = \$ 72 \ }

Thus, the money Abbie had at first is $72.

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Keywords: Abbie, spent 5/8 of her money, saved the rest, $45, $72, how much money, she have at first, the pattern

Note that 5/8 is equivalent to $45

1/8 is equivalent to $45 ÷ 5 = 9

8/8 (aal) is equivalent to 8 x 9 = 72

She had $72

Divide (15x^2+x-8)/(3x-1)

Answers

Simplifying -15x2 + -2x + 8 = 0
 Reorder the terms: 8 + -2x + -15x2 = 0 Solving 8 + -2x + -15x2 = 0 Solving for variable 'x'.
 Factor a trinomial. (2 + -3x)(4 + 5x) = 0 Subproblem 1Set the factor '(2 + -3x)' equal to zero and attempt to solve:
 Simplifying 2 + -3x = 0 Solving 2 + -3x = 0
 Move all terms containing x to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + -2 + -3x = 0 + -2
 Combine like terms: 2 + -2 = 0 0 + -3x = 0 + -2 -3x = 0 + -2
 Combine like terms: 0 + -2 = -2 -3x = -2
 Divide each side by '-3'. x = 0.6666666667
 Simplifying x = 0.6666666667
Subproblem 2
Set the factor '(4 + 5x)' equal to zero and attempt to solve:
 Simplifying 4 + 5x = 0
 Solving 4 + 5x = 0
 Move all terms containing x to the left, all other terms to the right.
 Add '-4' to each side of the equation. 4 + -4 + 5x = 0 + -4
 Combine like terms: 4 + -4 = 0 0 + 5x = 0 + -4 5x = 0 + -4
 Combine like terms: 0 + -4 = -4 5x = -4
 Divide each side by '5'. x = -0.8 Simplifying x = -0.8
Solutionx = {0.6666666667, -0.8}