Which fraction is larger 1/3, 2/5, 8/15, 13/30. and how do i solve this

Answers

Answer 1

Answer: $(1)/(3);\ (2)/(5);\ (8)/(15);\ (13)/(30)\n\nDenominators:3;\ 5;\ 15;\ 30\n\nLCD(3;\ 5;\ 15;\ 30)=30\n\n(1)/(3)=(1\cdot10)/(3\cdot10)=(10)/(30)\n\n(2)/(5)=(2\cdot6)/(5\cdot6)=(12)/(30)\n\n(8)/(15)=(8\cdot2)/(15\cdot2)=(16)/(30)\n\n(13)/(30)\n\n(10)/(30) < (12)/(30) < (13)/(30) < (16)/(30)\Rightarrow(1)/(3) < (2)/(5) < (13)/(30) < (8)/(15)$

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The expression 8a+5c can be used to find the cost of an all you can eat buffet lunch for a adults c for children what is the cost of the lunch for 2 adults and 4 children

Answers

The cost is $36.
Hope this helps

Solve the following systems of equations:
- 7x + y = 4
8x - 3y = 1
X=
y =

Answers

Answer:

x=-1 y=-3

............

Answer:

(−1,−3) or x=−1,y=−3

Step-by-step explanation:

Solve for the first variable in one of the equations, then substitute the result into the other equation.

A DVD store charges $4.70 for each day, a DVD is rented. The store also gives you a dollar off if the DVD is returned before 5 days. a.Write a rule to represent the rental charges. b. How much will you pay if you return the DVD after 4 days? 7 days?

Answers

Answer:

For four days it would be $19.8. For seven days it would be $24.9

Step-by-step explanation:

4 days:

$4.70 x 4 + 1= 19.8

7 days:

$4.70 x 7 = $24.9

I took away 1 from the 4 day equation because the question said you get a dollar off if you return the dvd before 5 days.

Hope this helps!

~Starr

Two joggers, one averaging 7 mph and one averaging 5 mph, start from a designated initial point. The slower jogger arrives at the end of the run 45 minutes after the other jogger. Find fhe distance of the run.

Answers

22.5 miles long

basically all you have to do is count out the factors until you reach two number of 45 apart

  DIFFERENCE
7MPH 5MPH BETWEEN THEM

7 5 2
14 10 4
21 15   6
28 20 8
35 25 10
42 30 12
49 35 14
56 40 16
63 45 18
70 50   20
77 55   22
84 60   24
91 65 26
98    70 28
105    75 30
112    80 32
119 85 34
126 90 36
133 95 38
140    100 40
147 105 42
154 110 44
161 115 46

considering the differences are even it means it has to fall in the middle. if you count from the top it is 22.5 numbers down giving you the number of miles.
I'm sure there is an easier way but this is how i would solve it. :)

Final answer:

The distance of the run is 13.125 miles. The total time for the slower jogger was found to be 2.625 hours. Thus, both joggers ran the same distance, but at different speeds resulting in different finish times.

Explanation:

The problem deals with the concept of relative speed in mathematics. To find the distance of the run, we first need to figure out the time it took for each jogger to finish the run. We know that the slower jogger finished 45 minutes after the faster one. Since the speed equivalence is expressed in miles per hour (mph), let's convert 45 minutes into hours by dividing 45 by 60, giving us 0.75 hours.

Given that the slower jogger runs at 5 mph, and they took 0.75 hours longer than the faster one, we know they ran for a certain time 't', so we can represent this as t = total time of slower jogger's run.

The faster jogger ran at 7 mph. Since the jogger was 0.75 hours ahead of the slower one, the time would be represented by t - 0.75 hours = total time of faster jogger's run. The distance travelled by each jogger is 'speed x time'.

Following this, we equal these distances because it's the same course: 5t = 7(t - 0.75).

Solving this equation gives us t = 2.625 hours (total time for slower jogger). To find the run's distance, we can now substitute total time into either jogger's speed x time calculation. We'll use the slower jogger here: Distance = 5t = 5*2.625 = 13.125 miles.

Learn more about Relative Speed here:

brainly.com/question/14362959

#SPJ3

Help please I need this done like right now

Answers

Answer:

$\left(\begin{array}{c}-24\n20\end{array}\right)$

Step-by-step explanation:

Given vectors:

$\textbf{a}=\left(\begin{array}{c}-9\n7\end{array}\right)\n\n\n \textbf{b}=\left(\begin{array}{c}12\n-20\end{array}\right)\n\n\n\textbf{c}=\left(\begin{array}{c}0\n-16\end{array}\right)$

$\textsf{To calculate}\;\;3\textbf{a}-(1)/(4)(\textbf{c}-\textbf{b}),\;\;\textsf{substitute the given vectors into the expression:}$

$3\left(\begin{array}{c}-9\n7\end{array}\right)-(1)/(4)\left(\begin{array}{ccc}0&-&12\n-16&-&(-20)\end{array}\right)$

When subtracting vectors, we subtract the elements in the same position from one vector from the elements in the same position of the other vector. Therefore, subtracting vector b from vector c gives:

$3\left(\begin{array}{c}-9\n7\end{array}\right)-(1)/(4)\left(\begin{array}{c}-12\n4\end{array}\right)$

When multiplying a vector by a constant, we multiply each component of the vector by that constant. Therefore, multiplying vector a by 3 gives:

$\left(\begin{array}{c}3\cdot(-9)\n3\cdot 7\end{array}\right)-(1)/(4)\left(\begin{array}{c}-12\n4\end{array}\right)$

$\left(\begin{array}{c}-27\n21\end{array}\right)-(1)/(4)\left(\begin{array}{c}-12\n4\end{array}\right)$

Multiply (c - b) by 1/4:

$\left(\begin{array}{c}-27\n21\end{array}\right)-\left(\begin{array}{c}-12\cdot (1)/(4)\n4\cdot (1)/(4)\end{array}\right)$

$\left(\begin{array}{c}-27\n21\end{array}\right)-\left(\begin{array}{c}-3\n1\end{array}\right)$

Finally, subtract the vectors:

$\left(\begin{array}{ccc}-27&-&(-3)\n21&-&1\end{array}\right)$

$\left(\begin{array}{c}-24\n20\end{array}\right)$

$\textsf{So,}\;\;3\textbf{a}-(1)/(4)(\textbf{c}-\textbf{b})\;\;\textsf{is equal to}\;\;\left(\begin{array}{c}-24\n20\end{array}\right).$

What type of number is - v 81?

Answers

Answer:

rational

Step-by-step explanation:

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