Name two elements that have properties similar to copper

Answers

Answer 1

Answer: Nickel and iron . Tin and zinc. Gold and silver. They all have properties similar to copper

Answer 2

Answer:

Final answer:

Silver and gold are two elements which have properties similar to copper. These common properties include sheen, malleability, ductility, and their ability to conduct heat and electricity, attributable to their similar atomic structures.

Explanation:

Two elements that have properties similar to copper, which is a metal, include silver (Ag) and gold (Au). All these elements fit into the same category - metals, that demonstrate certain characteristics:

They appear shiny, and have the ability to be formed into different shapes (malleable) and drawn into wires (ductile).
They act as good conductors of heat and electricity.

These properties stem from their similar atomic structures, placed in the same group on the periodic table.

Learn more about Similar Elements to Copper here:

brainly.com/question/703689

#SPJ3

Related Questions

The standard enthalpy of ________ is the enthalpy change of reaction to form one mole of a substance from its elements under standard conditions of temperature and pressure.
What ion is most closely associated with bases?
in a collosion 15 kg object moving with a velocity of 3 m.s transfers all of its momentum to a 5 kg object. what would be the velocity of the 5 kg object after the collosion
.Which of these halogens is the least reactiveon the Period Table?1) I 2) Br 3) CI 4) F
Density is an example of what type of property? Intensive Extensive Chemical Biological

Assuming constant pressure and temperature, how many moles of gas have been added to the initial 3 moles of gas when the volume increases from 2.0 to 4.0 liters?1.5 moles

2 moles

3 moles

6 moles

Answers

Answer:

Moles of gas added = 3 moles

Explanation:

Given:

Initial volume of gas, V1 = 2.0 L

Initial moles of gas, n1 = 3 moles

Final volume, V2 = 4.0 L

To determine:

The moles of gas added to bring the final volume to 4.0 L

Explanation:

Based on the ideal gas equation

$PV = nRT$

where P = pressure, V = volume ; n = moles of gas

R = gas constant, T = temperature

At constant P and T, the above equation becomes:

V/n = constant

This is the Avogadro's law

Therefore:

$(V1)/(n1) = (V2)/(n2) \n\nn2 = (V2)/(V1) * n1 = (4.0 L)/(2.0L) * 3 = 6 moles$

The final number of moles of gas = 6

Thus, moles added = Final - Initial = n2 - n1 = 6-3 = 3 moles

We first assume that the gas is ideal which is a safe assumption to approximate the answer to the problem. Then we need to know the ideal gas equation and that is:

PV=nRT
where
P- pressure
V- volume
n-number of moles-
R- ideal gas constant
T-temperature.

Since we know that P, T and V are constant, rearranging the equation would lead to:

P/TR = n/V or the ratio of the moles of gas and volume is constant.

(3moles)/2L = (3+x)/4L
where
x is the additional moles.

Solving for x = 3 moles.

HELP!!!! The freezing of methane is an exothermic change. What best describes the temperature conditions that are likely to make this a spontaneous change? Any temperature, because entropy increases during freezing. Any temperature, because entropy decreases during freezing. Low temperature only, because entropy decreases during freezing. High temperature only, because entropy increases during freezing.

Answers

Answer: The correct statement is low temperature only, because entropy decreases during freezing.

Explanation:

The relationship between Gibb's free energy, enthalpy, entropy and temperature is given by the equation:

$\Delta G=\Delta H-T\Delta S$

Where,

$\Delta G$ = change in Gibb's free energy

$\Delta H$ = change in enthalpy

T = temperature

$\Delta S$ = change in entropy

It is given that freezing of methane is taking place, which means that entropy is decreasing and $Delta S$ is becoming negative. It is also given that the reaction is an exothermic reaction, this means that the $\Delta H$ is also negative.

For a reaction to be spontaneous, $\Delta G$ must be negative.

$-ve=-ve-[T(-ve)]\n\n-ve=-ve+T$

From above equations, it is visible that $\Delta G$ will be negative only when the temperature will be low.

Hence, the correct statement is low temperature only, because entropy decreases during freezing.

Answer:

Low temperature only, because entropy decreases during freezing.

Explanation:

A crucible contains 6.4 g of copper, Cu. How many moles does this amount contain? [Given: Cu=64]

Answers

Use this formula:
Mass = moles x RFM

(RFM = Relative Formula Mass, or the total mass of a substance or element for example Cu=64)

Rearrange the formula to find the number of moles
Moles = mass/RFM
=6.4/64
= 0.1

1) Write the word and symbol equation to show what happens when water is added to Calcium Oxide.2) Write word and symbol equations for the thermal decomposition of limestone.

Answers

2. caco3 -> cao + co2
limestone -> calcium oxide + carbon dioxide

Explain how do the octect forms in cations and anions

Answers

Answer:

Explanation:

-Octet forms when the valence electrons are gained, lost or shared.

-In order to become stable, which has 8 valence electrons (octet), nonmetal groups such as group 17, needs to gain 1 more electron to become 8/ octet.

When gaining that 1 electron, group 17 elements become negative ion or anions

-For metal groups such as group 1, they need to lose that 1 electron to become stable. When they lose that 1 electron, they become positive ion which is cation.

Hope this helps

Which of the following molecules has a bent structure?A. O2
B. CO2
C. H2O
D. CH4

Answers

Answer : The correct option is, (C) $H_2O$

Explanation :

Formula used:

$\text{Number of electrons}=(1)/(2)[V+N-C+A]$

where,

V = number of valence electrons present in central atom

N = number of monovalent atoms bonded to central atom

C = charge of cation

A = charge of anion

First we have to determine the hybridization of the following molecules.

(a) $O_2$

This is diatomic molecule and diatomic molecules always form linear shape.

(b) $CO_2$

$\text{Number of electrons}=(1)/(2)* [4]=2$

The number of electrons is 2 that means the hybridization will be $sp$ and the electronic geometry of the molecule will be linear.

(c) $H_2O$

$\text{Number of electrons}=(1)/(2)* [6+2]=4$

The number of electrons is 4 that means the hybridization will be $sp^3$ and the electronic geometry of the molecule will be tetrahedral.

But as there are two atoms around the central oxygen atom, the third and fourth position will be occupied by lone pair of electrons. The repulsion between lone and bond pair of electrons is more and hence the molecular geometry will be bent.

(d) $CH_4$

$\text{Number of electrons}=(1)/(2)* [4+4]=4$

The number of electrons is 4 that means the hybridization will be $sp^3$ and the electronic geometry of the molecule will be tetrahedral.

Hence, the molecule has bent structure will be, $H_2O$

H2O has a bent structure. The oxygen atom is in the center, and the hydrogen atoms are attached but pointing downward. It's not linear because there are two unshared pairs of electrons on oxygen that take up their own spaces.

Other Questions

The hardest known mineral is _____. topaz talc diamond graphite

Consider this equilibrium:CO2(g) + 2H2O(g) CH4(g) + 2O2(g). What indicates that the reactants are favored? Keq is zero. Keq is very large. Keq is slightly less than 1. Keq is slightly greater than 1.

Which compound is an exception to the octet rule

What is the rroooooooooooooooo