The following question references the novel Jane Eyre by Charlotte Bronte.How does Jane gain financial independence?
a. Her uncle leaves her 20 thousand pounds
c. She write a book that is published
b. Parent's from the school reward her for her work
Please select the best answer from the choices provided

Answers

Answer 1

Answer: The answer is:

A: Her uncle leaves her 20,000 pounds

Answer 2

Answer:
Her uncle leaves her 20 thousand pounds yet she gives 15 thousand pounds to her cousins the Rivers.

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Find the mean, median, and interquartile for the data set below. Round your answer to the nearest tenth. 27,16,8,5,19,14,22,31,13,5,23,16,8

Answers

Answer:

Hence,

Mean=15.9

Median=16

Interquartile=14.5

Step-by-step explanation:

On arranging our data in the increasing order we get the data set as:

5 5 8 8 13 14 16 16 19 22 23 27 31

Now we find the mean as:

$Mean=(5+5+8+8+13+14+16+16+19+22+23+27+31)/(13)\n\nMean=(207)/(13)\n\nMean=15.92$

Now, we know that the median is the central tendency of the data and lie in the middle of the data.

Hence, by looking at the data we see that the middle value of the data is 16.

Hence, Median=16.

Now, the lower set of data is:

5 5 8 8 13 14

Now, the lower quartile is calculated as:

The middle value of the lower set of data is:

8 8

Hence, the lower quartile $]Q_1$ is middle of 8,8.

i.e. $(8+8)/(2)=8$

similarly the upper set of data is:

16 19 22 23 27 31.

Similarly the upper quartile is calculated as:

$Q_3=(22+23)/(2)=22.5$

Hence, interquartile range (IQR) is calculated as:

$Q_3-Q_1=22.5-8=14.5$

Hence,

Mean=15.9

Median=16

Interquartile=14.5

The mean is 15.92, the median is 16, and the interquartile range is 14.5

Determine the remainder when (5x3 + 49x2 + 74x + 6) is divided by (x + 8).

Answers

Determine the remainder when (5x3 + 49x2 + 74x + 6) is divided by (x + 8)

-103?

Need help. 35-(-55)=?

Answers

the answer is 90.Remember that whenever you see two - signs right next to eachother it turns into an addition sign

Remember that subtracting a negative number is the same as adding a positive number.(two negatives equals a positive) For example:

35-(-55)=35+55

They are both equivalent. Now we can solve..

35+55=90

Answer=90

buatlah matriks yang terdiri atas 5 baris dan 3 kolom dengan entrinya adalah 15 bilangan prima yang pertama

Answers

$A = \left[\begin{array}{ccccc}2&3&5\n7&11&13\n17&19&23\n29&31&37\n41&43&47\end{array}\right] \n \n \n \n A^T = \left[\begin{array}{ccccc}2&7&17&29&41\n3&11&19&31&43\n5&13&23&37&47\end{array}\right]$

Prove that the recurring decimal 0.39 = 13/33

Answers

$x=0.\overline{39}\n100x=39.\overline{39}\n 100x-x=39.\overline{39}-0.\overline{39}\n 99x=39\n x=(39)/(99)=(13)/(33)$

Please explain how you got your answers! (: Solve the problem by using the counting principle. A. Drapery is sold in 4 different fabrics. Each fabric comes in 13 different patterns. Each pattern is offered in 9 different colors. How many fabric-pattern-color combinations are there?

B. A shelf hold 3 novels, 2 biographies, and 1 history book. Two students in turn choose a book at random. What is the probability that the student choose the following?
both novels

A. 1/4
B. 1/2
C. 1/5
D. 1/3

A shelf hold 3 novels, 2 biographies, and 1 history book. Two students in turn choose a book at random. What is the probability that the student choose the following?

both biographies

A. 1/15
B. 1/20
C. 1/5
D. 1/3

A shelf hold 3 novels, 2 biographies, and 1 history book. Two students in turn choose a book at random. What is the probability that the student choose the following?

a history, then a novel

A. 1/2
B. 1/5
C. 1/10
D. 1/15

Answers

A. The number of fabric-pattern-color combinations is 4 * 13 * 9 = 468

B. P(1st choice) = no of novels / total books = 3/6 = 1/2
    P(2nd choice) = no of remaining novels/ total remaining books = 2/5
    P(both novels) = 1/2 * 2/5 = 1/5 (without replacement assumed)

C. P(1st choice) = no of biographies / total books = 2/6 = 1/3
    P(2nd choice) = no of remaining biographies/ total remaining books = 1/5
    P(both biographies) = 1/3 * 1/5 = 1/15 (without replacement assumed)

D. P(1st choice) = no of history books / total books = 1/6
    P(2nd choice) = no of novels/ total remaining books = 3/5
    P(a history, then a novel) = 1/6 * 3/5 = 1/10 (without replacement assumed)

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