Answer:
0, 1, 4, 5, 6, and 9 can be the last digits of the squares of natural numbers.
Step-by-step explanation:
When looking at a list of the perfect squares, the last digits continuously follow this pattern: 1, 4, 9, 6, 5, 6, 9, 4, 1, 0. After this it repeats. This means that these are the only numbers that can be the last digits. When you take out the repeated numbers you get: 1, 4, 5, 6, 9, 0 which when written in order is:
0, 1, 4, 5, 6, and 9
-x - 7y
12x – 10y
7x – 7y
Answer:
-x - 7y
Step-by-step explanation:
(3x – 2y) – (4x + 5y).
= 3x - 2y - 4x - 5y
= -x - 7y
Answer:
-1x-7y
Step-by-step explanation:
3x-4x= -1x
-2y-5y= -7y