A sports arena covers 710,430 square feet of ground. A newspaper reported that the arena covers about 700,000 square feet of ground. To what place value was the number rounded?

Answers

Answer 1

Answer:

Answer:

Required place value is hundred thousand place.

Step-by-step explanation:

Given : A sports arena covers 710,430 square feet of ground. A newspaper reported that the arena covers about 700,000 square feet of ground.

To find : To what place value was the number rounded?

Solution :

Rule of rounding number :

1) When the rounded place value after digit is less than 5 then the number remain same.

2) If the rounded place value after digit is 5 or greater than 5 then the number round by 1.

710,430 is rounded to 700,000.

It is clear that number is rounded to the hundred thousand place.

As before 7 there is 1<5 so rest rounded to zero and 7 remain same.

Therefore, Required place value is hundred thousand place.

Answer 2

Answer: 710, 430 ft² was rounded to the hundreds place: 700,000 ft²

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At discount copy,12 copies cost $0.66. Melissa needs 56 copies . How much should they cost ? ....show work

Answers

Cost of 12 copies that Melissa needs to pay = $0.66
Then
Cost of 1 copy that Melissa needs to pay = (66/12) dollars
   = 11/2 dollars
Now
The cost of 56 copies that Melissa has to pay =(11/2) * 56
      = 11 * 28 dollars
      = 308 dollars
So Melissa needs to pay $308 for 56 copies.I hope the procedure is clear enough for you tounderstand. In future you can use this procedure to solve similar problems in future.

56 copies* ($0.66/ 12 copies)= $3.08
(Note that the unit cancels out so you get the answer)

The final answer is $3.08~

$\sqrt{125 + √(36 + 64) }$

Answers

Answer:

$\sqrt{125 + √(36 + 64) } \n \n \sqrt{125 + √(100) } \n \n √(125 + 10) \n √(135) \n √(9 * 15) \n 3 √(15)$

There are 23 classes in Holly's school.Each class has the same number of students.
What is the total number of students in Holly@s school?

Answers

This question cant be solved, i dont think theres enough information

How do I solve 1/2 x s for s = 3/10

Answers

Answer:

Given: $(1)/(2)* s$ and value of $s=(3)/(10)$

Step 1: To solve this First Put value of s in given expression

$(1)/(2)* s$

$\implies(1)/(2)*(3)/(10)$

Step 2: To multiply 2 fraction, we multiply numerator by numerator and denominator by denominator

$\implies(1*3)/(2*10)$

$\implies(3)/(20)$

Therefore, It is solved in just 2 steps.

Also it is in lowest form or simplest form.

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Answers

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One example is the least common multiple of 2 and 3 is 6, which is their product.

But the product isn't always the answer because (example 2:) the least common multiple of 6 and 10 is 30 because 6*5=30 and 3*10=30, however 6*10 is 60.

Ergo, it is only sometimes true.

Jonathan is making his favorite pasta dish. He serves his mom 1/12 of the pot of pasta and his brother 1/6 of the pot. How much of the pot is left over?