How does biodiversity help sustain a population in an area

Answer:

Noble Gases

Explanation:

They all have complete outer shells. They're also on column 18 :)

Both are the unit of mass.

1 short ton = 2000 pounds

1 short ton = 907.18474 kg

Thus, 3.72 short ton =

= 3,374.727 kg

Now, convert kg to mg:

1 kg = 10,00,000 mg

Therefore,

3.72 short tons =

=

Hence, 3.72 short tons =

CrI₃ (aq) + 3 KOH (aq) → Cr(OH)₃ (s) + 3 KI (aq)

Explanation:

The chemical reaction between chromium (III) iodide (CrI₃) and potassium hydroxide (KOH):

CrI₃ (aq) + 3 KOH (aq) → Cr(OH)₃ (s) + 3 KI (aq)

where:

(aq) - aqueous

(s) - solid

The reaction will produce solid chromium(III) hydroxide (Cr(OH)₃) and KI aqueous potassium (KI).

Learn more about:

problems with chromium(III) salts

brainly.com/question/9821533

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A pure substance is a substance which cannot be separated physically or chemically. It is the same wherever found on earth. For example, pure gold is a pure substance. It will be the same whether it is found where you live or on another country. A mixture can be either homogeneous or heterogeneous. A homogeneous mixture is a mixture that looks the same throughout but is made of more than one element. An example of this would be salt and water mixture.  A heterogeneous mixture is a mixture in which you can easily identify the different parts which make it up. An example of this would be pizza. Both these mixtures can be broken into different parts either physically or chemically.

Hope it helps :)

Answer:

1) The dilution scheme will result in a 200μM solution.

2) The dilution scheme will not result in a 200μM solution.

3) The dilution scheme will not result in a 200μM solution.

4) The dilution scheme will result in a 200μM solution.

5) The dilution scheme will result in a 200μM solution.

Explanation:

Convert the given original molarity to molar as follows.

Consider the following serial dilutions.

1)

Dilute 5.00 mL of the stock solution upto 500 mL . Then dilute 10.00 mL of the resulting solution upto 250.0 mL.

Molarity of 500 mL solution:

10 mL of this solution is diluted to 250 ml

Convert μM :

Therefore, The dilution scheme will result in a 200μM solution.

2)

Dilute 5.00 mL of the stock solution upto 100 mL . Then dilute 10.00 mL of the resulting solution upto 1000 mL.

Molarity of 100 mL solution:

10 mL of this solution is diluted to 1000 ml

Convert μM :

Therefore, The dilution scheme will not result in a 200μM solution.

3)

Dilute 10.00 mL of the stock solution upto 100 mL . Then dilute 5 mL of the resulting solution upto 100 mL.

Molarity of 100 mL solution:

5 mL of this solution is diluted to 1000 ml

Convert μM :

Therefore, The dilution scheme will not result in a 200μM solution.

4)

Dilute 5 mL of the stock solution upto 250 mL . Then dilute 10 mL of the resulting solution upto 500 mL.

Molarity of 250 mL solution:

10 mL of this solution is diluted to 500 ml

Convert μM :

Therefore, The dilution scheme will result in a 200μM solution.

5)

Dilute 10  mL of the stock solution upto 250 mL . Then dilute 10 mL of the resulting solution upto 1000 mL.

Molarity of 250 mL solution:

10 mL of this solution is diluted to 1000 ml

Convert μM :

Therefore, The dilution scheme will result in a 200μM solution.