Find the quotient of negative 21 divided by negative 3
Answers
Answer 1
Answer:
The answer is 7
The answer is 7
Related Questions
Write the following series in sigma notation.7+11+15+19+23
If u(x) = x5 – x4 + x2 and v(x) = –x2, which expression is equivalent to (U/V) (x)?a) x3 – x2b)–x3 + x2c)–x3 + x2 – 1d)x3 – x2 + 1
What is the solution to the equation?2 - z/3 =12A.z = –42B.z = –34C.z = –30D.z = 42
Can someone please help
Jen bought 5 CDs for $57.50 What was the unit price ?
If u(x) = x5 – x4 + x2 and v(x) = –x2, which expression is equivalent to (U/V) (x)?a) x3 – x2b)–x3 + x2c)–x3 + x2 – 1d)x3 – x2 + 1
What is the solution to the equation?2 - z/3 =12A.z = –42B.z = –34C.z = –30D.z = 42
Can someone please help
Jen bought 5 CDs for $57.50 What was the unit price ?
Answers
Answer:
25
Step-by-step explanation:
2x-8=x+17
2x-x=17+8
x=25
Answers
assume the numbers are x , y
x+y =-53
x*y =-24
from equation 1 we get y = -53-x
sub in eqn.2
x* (-53 -x ) = -24
then x^2 + 53x -24 =0
and by solving the equation and substitute we get
the two numbers are
0.449 & -53.452
x+y =-53
x*y =-24
from equation 1 we get y = -53-x
sub in eqn.2
x* (-53 -x ) = -24
then x^2 + 53x -24 =0
and by solving the equation and substitute we get
the two numbers are
0.449 & -53.452
Answers
0.2 = 
So,
So,
Answers
Given,
(k × m) ÷ (-7) = n
Cross multiplying all the terms on the left hand side to the ones on the right hand side,
k = (-7n) ÷ m
Note: Is this what you are looking for? If not, please give more details. Thank you
(k × m) ÷ (-7) = n
Cross multiplying all the terms on the left hand side to the ones on the right hand side,
k = (-7n) ÷ m
Note: Is this what you are looking for? If not, please give more details. Thank you
(5, −19)
(−3, 141)
(3, −39) ((my answer))
Answers
you are correct
And if you plug them in they wouldn't give you the correct y except your answer
And if you plug them in they wouldn't give you the correct y except your answer
Answer:
(3, −39)
Step-by-step explanation:
What is the answer?
Answers
Answer:
1100
Step-by-step explanation:
hope it helped