If I was 14 stone what would my gravity be on venus

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Answer 1

Answer: The acceleration of gravity on the surface of Venus (8.87 m/s^2) is 90.4% (rounded) of its value on Earth's surface (9.807 m/s^2). So if your weight on Earth is exactly 14 stone, then you would weigh 12st 9.2lb (rounded) on Venus.

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Integrated circuits are manufactured on chips made of the element.

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The "substrate" of the integrated circuit is super-pure silicon.

Integrated circuits are manufactured on chips made of the element ⇒ silicon.

kyle is holding a nag of 250 jelly beans. when mark takes out two jellybeans, kyle is not able to tell a difference. this illustrates

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This illustrates Kyle's inability to accurately sense the weight of the nag.

b.) absolute threshold

Name a characteristic physical property?

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Land, housing, business.

Different velocity-time graph lines are shown, displaying the behavior of multiple race carts along a linear track.Which description correctly identifies cart C?

A) Has a positive acceleration and is speeding up.
B) Moving with zero acceleration.
C) Moving at a constant acceleration.
D) Has a negative acceleration and is slowing down.

Answers

B) Moving with zero acceleration.

Explanation:

Acceleration is defined as the rate of change of the velocity per unit time:

$a=(\Delta v)/(\Delta t)$

In a velocity-time graph, this ratio corresponds to the slope of the curve. In fact:

$\Delta v$ (change in velocity) corresponds to the increase in the y-axis

$\Delta t$ (change in time) corresponds to the increase in the x-axis

So, acceleration corresponds to the slope of the curve in a velocity-time graph. For cart C, the slope is zero, therefore the acceleration is also zero.

Answer:

B) Moving with zero acceleration.

Explanation:

As we can see the graph for Cart C that its velocity is constant and not changing its magnitude as well as its sign

So here the magnitude and direction is constant so we can say that velocity will remain constant always.

Where we can define the acceleration as

$a = (dv)/(dt)$