PHYSICS HIGH SCHOOL

Astronomy can best be described as a/an A. study of objects pertaining to the interior part of the Earth.
B. study of objects beyond the Earth's atmosphere.
C. Air Force pilot on a naval carrier.
D. daily horoscope.

Answers

Answer 1
Answer: Quite simply, astronomy is related to studying objects such as planets, stars and galaxies in space.

So the answer to the question would have to be B.

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Atoms form two types of bonds. Which describes these bonds? A.
In a covalent bond, valence electrons are shared; in an ionic bond, valence electrons are transferred.

B.
In a covalent bond, valence electrons are transferred; in an ionic bond, valence electrons are shared.

C.
In a covalent bond, outer electron orbitals are shared; in an ionic bond, outer electron orbitals are transferred.

D.
In a covalent bond, outer electron orbitals are transferred; in an ionic bond, outer electron orbitals are shared.

Answers

Atoms form two types of bonds: ionic bond and covalent bond. In a covalent bond, valence electrons are shared; in an ionic bond, valence electrons are transferred. The answer is letter A.

Answer:

Atoms form two types of bonds: ionic bond and covalent bond. In a covalent bond, valence electrons are shared; in an ionic bond, valence electrons are transferred.

Explanation:

Therefore, the answer is A

How is 1 hectoliter different from 1 kiloliter?

Answers

For this case the main unit is liter.

The first thing you should know is that the liter is a unit of volume.

The difference then between hectoliter and kiloliter is the conversion factor.

For hectoliter we have:

1 hectoliter = 100 liters

For kiloliter we have:

1 kiloliter = 1000 liters

Answer:

The difference between both is the conversion factor:

1 hectoliter = 100 liters

1 kiloliter = 1000 liters
a kiloliter is smaller than hectoliter

A helicopter flying west begins experiencing an acceleration of 3m/s2 east. Will the magnitude of its velocity increase or decrease?

Answers

The acceleration measures the change in velocity.

Since the acceleration is in the direction opposite to the speed, the velocity eastwards will decrease : its magnitude will first decrease, then it reach 0 m/s, then finally it will increase again.

Calculate the resistance of a lamp that draw 0.75 A current when connected to 4.5 V.​

Answers

Calculate the resistance using the equation:

V=IR

In the question, the following values are given:

V = 4.5
I = 0.75

Substitute the values into the equation to find R, the resistance:

V = IR

4.5 = 0.75R

R = 4.5 / 0.75

R = 6 ohms

a bullet of mass m is fired into a block of mass m that is at rest. the block, with the bullet embedded, slides distance d across a horizontal surface. the coefficient of kinetic friction is μk.

Answers

The expression for the bullet's speed vbullet is v=\sqrt{(2\mu_k (m+M)gd)/(m)} and  the speed of a 9.0 g bullet is v=16.8 m/s

Explanation:

A  bullet of mass m is fired into a block of mass m that is at rest. the block, with the bullet embedded, slides distance d across a horizontal surface. the coefficient of kinetic friction is μk.

The initial kinetic energy of the bullet is given by

K_i = (1)/(2)mv^2

where

m is the mass of the bullet  

v is the initial speed of the bullet

The expression for the bullet's speed vbullet is

F=\mu_k (m+M) g

where

\mu_k is the coefficient of kinetic friction

g is the acceleration of gravity

The work done by the force of friction is

W=-Fd = -\mu_k (m+M)g d

where d is the displacement of the block+bullet.

Because the final kinetic energy is zero (the bullet with the block comes at rest), we can write:

W=K_f - K_i = -K_i

And so

-\mu_k (m+M) g d = -(1)/(2)mv^2

By solving for v, the solution for the bullet speed:

-\mu_k (m+M) g d = -(1)/(2)mv^2\nv=\sqrt{(2\mu_k (m+M)gd)/(m)}

The speed of a 9.0 g bullet that, when fired into a 12 kg stationary wood block causes the block to slide 5.4 cm across a wood table. Assume that k=0.20.

We have:

the mass of the bullet, m = 9.0 g = 0.009 kg

the mass of the block, M = 12 kg

the distance covered by the block+bullet, d = 5.4 cm = 0.054 m

the coefficient of friction, \mu_k = 0.20

the acceleration of gravity, g = 9.8 m/s^2

By substituting, we got

v=\sqrt{(2 (0.20) (0.009 kg+12 kg)(9.8 m/s^2)(0.054 m))/(0.009 kg)}=16.8 m/s

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uk=2m*the normal force
the distance d is needed only if you were asked about work

Assume it takes 7.00 minutes to fill a 30.0 gal gas tank. (a) Calculate the rate at which the tank is filled in gallons per second. (b) Determine the rate at which the tank is filled in cubic meters per second. (c) Determine the time interval, in hours, required to fill a 1.00 m^3 volume at the same rate. ( 1 US gal = 231 in.^3)

Answers

a)
R1 = 30/(7*60)
We are multiplying 7 with 60 because there are 60 seconds in 1 minute.
R1 = 30/420 = 0.0714 gallons/second

b) For this we need to express gallons to cubic meters.
1 gallon = 0.003785 m^3
R2 = 0.0714*0.003785 = 0.00027 m^3/s

c) V = R2*t    where V is volume of some tank.
which means that
t=V/R2    
t =  3698.8s   or 
t = 1.0274 hours
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