Pistachios were priced at 3 pounds for $ 6.99. (a) what were the price per pound? (b) how much would 10 pounds of pistachios cost?

Answers

Answer 1

Answer: just do 6.99 divided by 3
(a)$2.33

times your answer in (a) by 10
(b)$23.3

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What is the value of x in the equation below?-3-(-8)-(-2) = X
O -13
O-9
O 3
07

Answers

The value of x in the equation -3-(-8)-(-2) = x is 7.

The correct option is 07.

What is PEMDAS?

When resolving expressions containing several operations, the procedure to follow is denoted by the acronym PEMDAS. "Parenthesis," "exponents," "multiplication," "division," "addition," and "subtraction" are all represented by the letters P through E.

Given information:

The given equation is described as -3-(-8)-(-2) = x.

To solve the equation as per the PEMDAS rule:

First, we need to simplify the terms within the parentheses: -(-8) is the same as +8, and -(-2) is the same as +2. Therefore, the equation becomes:

-3 + 8 + 2 = x

Next, we can simplify the addition and subtraction from left to right:

-3 + 8 = 5

5 + 2 = 7

Therefore, the value of x is 7.

To learn more about the PEMDAS;

brainly.com/question/36185

#SPJ7

Answer:

Step-by-step explanation:

16 17 18Select True or False for each statement.
Point A(5,-5) is to the right of the y-axis and below the x-axis.
7
Point B(-3, 2) is to the left of the y-axis and below the x-axis.
7
Point C(2, 2) is to the right of the y-axis and above the x-axis.
?
V
Point D(-4, 4) is to the left of the y-axis and below the x-axis.
?

Answers

Answer:

true, false, true, false

I am confused on this , I’ve tried twice and got it wrong.

Answers

Answer:

$f^-^1(x)=-x^2+6x-5 \ \text{for the domain}\ [3, \infty)$

Step-by-step explanation:

Consider the function $f(x)=√(4-x)+3$ for the domain $(- \infty, 4]$ .

Find $f^-^1(x)$ , where f^(-1) is the inverse of f.

Also state the domain of f^(-1) in interval notation.

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We can start solving this problem by finding the inverse of f(x). This is done by switching the x- and y- variables, and solving for y.

$y=√(4-x)+3 \rightarrow x=√(4-y)+3$
$x=√(4-y)+3$

We can start solving for y by subtracting 3 from both sides of the equation.

$x-3=√(4-y)$

Get rid of the radical by squaring both sides of the equation.

$(x-3)^2=(√(4-y))^2$
$(x-3)(x-3)=4-y$

Use FOIL to multiply the binomial (x-3) together.

$x^2-3x-3x+9=4-y$

Combine like terms.

$x^2-6x+9=4-y$

Subtract 4 from both sides of the equation.

$x^2-6x+5=-y$

Divide both sides of the equation by -1.

$-x^2+6x-5=y$
$f^-^1(x)=-x^2+6x-5$

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The domain and range of a function are flipped for its inverse, meaning that to find the domain of the inverse function, you can find the range of the original function f(x), and that will be your inverse function's domain.

The range of $f(x)=√(4-x) +3$ is $y \geq 3$ , since the vertical shift of the graph is at k = 3. You can also graph this function on a calculator to see that the graph does indeed start at y = 3.