CHEMISTRY HIGH SCHOOL

A reaction that occurs when the reactants are simply put together isA. automatic.
B. exothermic.
C. spontaneous.
D. endothermic.

Answers

Answer 1
Answer: The answer is C. spontaneous. Spontaneous reactions occur without being driven by an outside force.
Hope that helped you.
Answer 2
Answer: C. spontaneous would be ur answer!

Hope I helped:P

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The melting points of canola oil, corn oil, sunflower oil, and peanut oil are 10° C, -11° C, -17° C, and -2° C, If you cool a mixture of these oils to 5°C, which one can you separate easily?a. corn oil
b. canola oil
c. peanut oil
d. sunflower oil

Answers

Answer:

            Canola Oil

Explanation:

The data given is as;

     Oil                                             Melting Point / Freezing Point

Canola Oil                                                            10 °C

Corn Oil                                                                -11 °C

Sunflower Oil                                                       -17 °C

Peanut Oil                                                           -2 °C

When the mixture of these oils is cooled to 5 °C only the Canola oil will solidify because it has a melting point of 10 °C and exists in solid state below 10 °C (Freezing Point). Therefore, it can easily be separated from remaining mixture which is present in liquid state.

Which of these phrases best describes an atom?(1) a positive nucleus surrounded by a hard negative shell(2) a positive nucleus surrounded by a cloud of negative charges
(3) a hard sphere with positive particles uniformly embedded
(4) a hard sphere with negative particles uniformly embedded

Answers

number two because of yall study this in sciwnce class yall will get it

Which is a correct set of values of m for one of the subshells of n = 2? –1, 0, 1 –1, –2, 0, 1, 2 –1, –2, –3, 0, 1, 2, 3 –1, –2, –3, –4, 0, 1, 2, 3, 4

Answers

For the principal quantum number, n, its corresponding sets of magnetic quantum, m, values depend on the angular quantum values, l. For n=2, the values of l are from 0 to (n-1), which are 0 and 1. For each value of l, the m value that corresponds to it is given by m = -l, ..., 0, ..., +l. This gives a set of m values equial to m = -1, 0, 1.

Answer:

a

Explanation:

Which of the following is an example of a Brønsted-Lowry base?​

Answers

Final answer:

A Brønsted-Lowry base is a species that accepts a proton (hydrogen ion) from another species. NH3, OH-, and even water itself are examples of Brønsted-Lowry bases, denoting they accept protons.

Explanation:

A Brønsted-Lowry base is a species that can accept a proton (a hydrogen ion) from another species. For instance, in a reaction between water and ammonia, NH3 is the Brønsted-Lowry base because it accepts a proton from water. This means that any species capable of accepting a proton, such as hydroxide ion (OH-), ammonia (NH3), or water itself can be considered a Brønsted-Lowry base.

For example, think about the dissociation of water:
H2O + H2O ⇌ H3O+ + OH-
In this reaction, water is acting as both a Brønsted-Lowry acid and a Brønsted-Lowry base. One water molecule donates a proton and becomes a hydroxide ion (the conjugate base), while the other accepts a proton to become hydronium (the conjugate acid).

Another example would be the ionization of ammonia in water:
NH3 + H2O ⇌ NH4+ + OH-
Here, ammonia (NH3) is the Brønsted-Lowry base as it accepts a proton from water to become ammonium (NH4+).

Learn more about Brønsted-Lowry Base here:

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Which factor is generally responsible for high melting points?

Answers

Strong intermolecular ion-ion forces are responsible for high melting points. Thus the solid state requires close proximity and high order to have high melting point. Hope this answer helps. Good luck!

Answer;

Intermolecular forces.

Explanation;

  • Melting point is the temperature at which a solid melts or a solid changes to a liquid.  In liquids melting point is similar to the freezing point.
  • Melting point of a substance depends on the molecular composition, force of attraction between molecules and also the presence of impurities.
  • A strong force of attraction between molecules results in a higher melting point. Such that stronger intermolecular forces results to a higher melting point.
  • For example, the melting point of ionic compounds is higher due to the strong electrostatic forces joining ions.

What is the freezing point of an aqueous solution that boils at 105.0 ∘C? Express your answer using two significant figures.

Answers

The boiling point of standard water is 100 degree Celsius, with the addition of solute the boiling point is elevated. The freezing point of the solution will be -18.04 degree Celsius.

What is boiling point?

The boiling point is the temperature at which the liquid is converted to vapor. The change in boiling point of the aqueous solution gives the molality of the solution as:

\rm \Delta T=ebuliloscopic constant\;*\;molality\;*\;von't\;hoff\;factor\n105^\circ C-100^\circ C=0.512^\circ C.kg/mol\;*\;1\;*\;m\n9.7\;mol/kg=m

The depression in freezing point from molality is given as;

\rm \Delta T=K_f\;*\;molality\;*\;i\n\Delta\;T=1.86\;^\circ C/m\;*\;9.7\;*\;1\n\Delta T=18.04\;^\circ C\n

The freezing point of aqueous water is zero degree Celsius. The freezing point of the solution will be:

\rm \Delta T=0^\circ\;C-New\;freezing\;point\n18.04^\circ\;C=0-New\;freezing\;point\nNew\;freezing\;point=-18.04^\circ C

The freezing point of the solution is -18.04 degree Celsius.

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Answer:

T°fussion of solution is -18°C

Explanation:

We have to involve two colligative properties to solve this. Let's imagine that the solute is non electrolytic, so i = 1

First of all, we apply boiling point elevation

ΔT = Kb . m . i

ΔT = Boiling T° of solution - Boiling T° of pure solvent

Kb =  ebuliloscopic constant

105°C - 100° = 0.512 °C kg/mol  . m . 1

5°C / 0.512 °C mol/kg = m

9.7 mol/kg = m

Now that we have the molality we can apply, the Freezing point depression.

ΔT = Kf . m . i

Kf =  cryoscopic constant

0° - (T°fussion of solution) = 1.86 °C/m  . 9.76 m . 1

- (1.86°C /m . 9.7 m) = T°fussion of solution

- 18°C = T°fussion of solution
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