What are 2 ways to solve 20=-5(-3+x)

Answers

Answer 1
Answer: 1) First way:

-5(-3+x) = 20

=> 15 - 5x = 20

=> -5x = 20 -15

=> -5x = 5

=> 
x = 5/-5

=> 
x = -1


2) Second way:

-5(-3+x)=20

=> 
-3+x = 20/-5

=> 
- 3 + x = -4

=> 
x = -4 + 3

=> 
x = -1


Answer 2
Answer: 1) 20 = -5(-3+x)
20/-5 = -3 + x 
-4 = -3 + x
-4 + 3 = x
x = -1
2)20 = -5(-3 + x)
20 = 15 - 5x
20 - 15 = - 5x
5 = -5x
5/-5 = x
x = -1

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the length of a rectangle is 5cm greater than the width. the area of the rectangle is 84cm squared. find the length and width

Answers

Answer:

Therefore,

Length=12\ cm

Width= 7\ cm

Step-by-step explanation:

Let the Width of rectangle be 'x' cm.

Then the length of a rectangle will be (x + 5) cm.

Area of rectangle given is 84 cm squared.

To Find:

Length = (x+5) = ?

Width = x = ?

Solution:

We have area of rectangle given as

\textrm{Area of Rectangle}=Length* Width

Substituting the given values we get

84=(x+5)x\nx^(2) +5x-84=0\n

On factorizing we get

x^(2) +12x-7x-84=0\nx(x+12)-7(x+12)=0\n(x+12)(x-7)=0\n(x+12)=0\ or\ (x-7)=0\nx=-12\ or\ x=7\n\therefore x =7\ cm\ \textrm{As x cannot be negative}

Therefore,

Length=x+5=7+5=12\ cm

Therefore,

Length=12\ cm

Width= 7\ cm

On Monday John had $500 . Over the weekend he went out to eat for $ 112and used his debit card for movie tickets that cost $28 . How much money did John have on Tuesday?

Answers

This question is a little ambiguously worded, however I assume the answer would simply be:
$500 - $112 - $28 = the amount he has left.
Hope this helped :))

In spite of the of his presentation, manypeople were with the speaker’s concepts
and ideas.
(A) interest…enthralled
(B) power…taken
(C) intensity…shocked
(D) greatness…gratified
(E) strength…bored

Answers

E strength/bored

In spite of the STRENGTH of his presentation, many
people were BORED with the speaker’s concepts
and ideas.


I need help with 6-8

Answers

Answer:

6. y² = 169x

7. y² = 12x

8. y^(2) = (1)/(2)x

Step-by-step explanation:

The equation of a quadratic function in vertex form is given by  

(y - α)² = 4a(x - β)

Where, (α,β) is the vertex of the function and a is the distance from vertex to its focus.

6. Here, (α,β) ≡ (0,0) and a point on the equation is (1,13)

So, the equation will be y² = 4ax

⇒ 13² = 4a(1)  

⇒ 4a = 169

Therefore, the original equation will be y² = 169x  (Answer)

7. Here also the vertex is (0,0) and a point on the equation is (3,-6),

So, (-6)² = 4a(3)  

⇒ 4a = 12

So, the equation is y² = 12x (Answer)

8. Here also the vertex is (0,0) and a point on the equation is ((1)/(2),(1)/(2)),

So, ((1)/(2))^(2) = 4a((1)/(2))

4a = (1)/(2)

So, the equation is y^(2) = (1)/(2)x (Answer)

Is a 78 degree angle a right,straight,obtuse or acute angle

Answers

Acute. 90 degrees is a right angle, 180 degrees is a straight angle, obtuse angles are greater than 90 degrees, while acute are less than 90 degrees.
Acute because it is less than 90o which is a right angle and obtuse is larger than 90o so there for it is acute angle which is less than 90o

7.2 cw homework help

Answers

Answer:

31. Yes (Y)

WXYZ ~ DABC

S.F.=4


32. Yes (Y)

GHIJ ~ KLMN

S.F.=2/3


33. Missing length: 16


34. Missing length: 30


35. x=7


36. x=10


Step-by-step explanation:

31. The polygons are similar if:

WX/DA=XY/AB

Then:

WX/DA=24/6→WX/DA=4

XY/AB=16/4→XY/AB=4

Like WX/DA=4=XY/AB, the polygons WXYZ and DABC are similar

Scale Factor: S.F.=XY/DA=XY/AB→S.F.=4


32. The polygons are similar if:

GH/KL=HI/LM=IJ/MN=GJ/KN

Then:

GH/KL=6/9=(6/3)/(9/3)→GH/KL=2/3

HI/LM=4/6=(4/2)/(6/2)→HI/LM=2/3

IJ/MN=4/6=(4/2)/(6/2)→IJ/MN=2/3

GJ/KN=4/6=(4/2)/(6/2)→GJ/KN=2/3

Like GH/KL=HI/LM=IJ/MN=GJ/KN=4, the polygons GHIJ and KLMN are similar

Scale Factor: S.F.=GH/KL=HI/LM=IJ/MN=GJ/KN→S.F.=2/3


33. If the polygons are similar, their sides must be proportional, then:

x/24=10/15

Simplifying the fraction on the right sides of the equation, dividing the numerator ans denominator by 5:

x/24=(10/5)/(15/5)

Dividing:

x/24=2/3

Solving for x: Multiplying both sides of the equation by 24:

24(x/24)=24(2/3)

Multiplying:

x=8(2)

x=16


34. If the polygons are similar, their sides must be proportional, then:

54/63=(54/9)/(63/9)→54/63=6/7

48/56=(48/8)/(56/8)→48/56=6/7

x/35=6/7

Solving for x: Multiplying both sides of the equation by 35:

35(x/35)=35(6/7)

Multiplying:

x=5(6)

x=30


36. (8x-2)/63=42/49

Simplifying the fraction on the right sides of the equation, dividing the numerator ans denominator by 7:

(8x-2)/63=(42/7)/(49/7)

Dividing:

(8x-2)/63=6/7

Solving for x: Multiplying both sides of the equation by 63:

63(8x-2)63=63(6/7)

Multiplying:

8x-2=9(6)

8x-2=54

Adding 2 both sides of the equation:

8x-2+2=54+2

Adding:

8x=56

Dividing both sides of the equation by 8:

8x/8=56/8

Dividing:

x=7


37. (6x-6)/63=42/49=30/35

Simplifying the fractions

(6x-6)/63=(42/7)/(49/7)=(30/5)/(35/5)

Dividing:

(6x-6)/63=6/7

Solving for x: Multiplying both sides of the equation by 63:

63(6x-6)63=63(6/7)

Multiplying:

6x-6=9(6)

6x-6=54

Adding 6 both sides of the equation:

6x-6+6=54+6

Adding:

6x=60

Dividing both sides of the equation by 6:

6x/6=60/6

Dividing:

x=10