Given the volume of a cube is 8 cubic meters, findthe distance from any vertex to the center point
inside the cube.
(A) 1 m
(B) √2 m
(C) 2√2 m
(D) 2√3 m
(E) √3 m

Answers

Answer 1

Answer: $V=8m^3\n\nV=a^3\n\na^3=8m^3\to a=\sqrt[3]{8m^3}=2m\n\ndiagonal\ of\ a\ cube:D=a\sqrt3\n\nD=2\sqrt3m\n\nDistance\ from\ any\ vertex\ to\ the\ center\ point\ inside\ the\ cube\nis\ a\ half\ of\ a\ diagonal:\n2\sqrt3:2=\sqrt3\ (m)\n\nAnswer:E$

BELOW

Step-by-step explanation:

$\mathrm{Slope}=(y_2-y_1)/(x_2-x_1)\n\n\left(x_1,\:y_1\right)=\left(-8,\:-11\right),\:\left(x_2,\:y_2\right)=\left(17,\:4\right)\n\nm=(4-\left(-11\right))/(17-\left(-8\right))\n\nm = (4+11)/(17+8)= (15)/(25) \n\mathrm{Refine}\n\nm=(3)/(5)$

$\mathrm{Slope}=(y_2-y_1)/(x_2-x_1)\n\n\left(x_1,\:y_1\right)=\left(10,\:-15\right),\:\left(x_2,\:y_2\right)=\left(13,\:-17\right)\n\nm=(-17-\left(-15\right))/(13-10)\n\nm = (-17+15)/(13-10)\n \nm = (-2)/(3)\n \nSimplify\nm=-(2)/(3)$

$\mathrm{Slope}=(y_2-y_1)/(x_2-x_1)\n\n\left(x_1,\:y_1\right)=\left(-6,\:-7\right),\:\left(x_2,\:y_2\right)=\left(5,\:-7\right)\n\nm=(-7-\left(-7\right))/(5-\left(-6\right))\n\nm = (-7+7)/(5+6)\n \nm = (0)/(11)\n \nSimplify\nm=0$

10.

$\mathrm{Slope}=(y_2-y_1)/(x_2-x_1)\n\n\left(x_1,\:y_1\right)=\left(-4,\:-3\right),\:\left(x_2,\:y_2\right)=\left(2,\:-9\right)\n\nm=(-9-\left(-3\right))/(2-\left(-4\right))\n\nm = (-9+3)/(2+4)\n \nm = (-6)/(6) \n\nSimplify\nm =-1$

11.

$\mathrm{Slope}=(y_2-y_1)/(x_2-x_1)\n\n\mathrm{When\:}y_1\ne \:y_2\mathrm{\:and\:}\:x_1=x_2\mathrm{\:the\:slope\:is\:}\infty \n\nm = \infty$

12.

$\mathrm{Slope}=(y_2-y_1)/(x_2-x_1)\n\n\left(x_1,\:y_1\right)=\left(-5,\:3\right),\:\left(x_2,\:y_2\right)=\left(19,\:-6\right)\n\nm=(-6-3)/(19-\left(-5\right))\n\nm = (-6-3)/(19+5)\n \nm = (-9)/(24)\n \nSimplify\nm=-(3)/(8)$

13.

$\mathrm{Slope}=(y_2-y_1)/(x_2-x_1)\n\n\left(x_1,\:y_1\right)=\left(-7,\:-12\right),\:\left(x_2,\:y_2\right)=\left(1,\:-16\right)\n\nm=(-16-\left(-12\right))/(1-\left(-7\right))\n\nm = (-16+12)/(1+7) \n\nm = (-4)/(8) \n\nSimplify\nm=-(1)/(2)$

14.

$\mathrm{Slope}=(y_2-y_1)/(x_2-x_1)\n\n\left(x_1,\:y_1\right)=\left(-18,\:0\right),\:\left(x_2,\:y_2\right)=\left(-13,\:1\right)\n\nm=(1-0)/(-13-\left(-18\right))\n\nm = (1-0)/(-13+18)\n \nm = (1)/(5) \n$

15.

$\mathrm{Slope}=(y_2-y_1)/(x_2-x_1)\n\n\left(x_1,\:y_1\right)=\left(1,\:-11\right),\:\left(x_2,\:y_2\right)=\left(-2,\:-4\right)\n\nm=(-4-\left(-11\right))/(-2-1)\n\nm = (-4+11)/(-2-1)\n \nm = (7)/(-3) \n\nSimplify\nm=-(7)/(3)$

What type of slope does (-7,8) and (-7,0) have?

Answers

Answer:

Undefined slope

Step-by-step explanation:

any number divided by 0 is undefined

-8/0

Answer: m=12/7

Step-by-step explanation:

I looked it up for you bro

The original price p of an item less a discount of 40%

Answers

Answer:

find 40 percent of the original price and subtract it from the the original price to find the new price.

An equation _____ has one solution.
always
sometimes
never

Answers

I think the correct answer from the choices listed above is the second option. An equation sometimes has one solution. A system of equation can have one solution when the equations intersect at one point. Equations can also have two or more number of solutions.

Answer:

Sometimes

Step-by-step explanation:

hope this helps u my friend

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