Sqrt(2−7x) -sqrt(x 3) =3

Answers

Answer 1

Answer: $(a+b)^2=a^2+2ab+b^2 \n \n √(2-7x) - √(x+3) =3 \n (√(2-7x))^2 =(3 + √(x+3))^2\n2-7x=9+6√(x+3)+x+3 \n 2-7x-9-x-3=6√(x+3) \n (-8x-10)^2=(6√(x+3))^2 \n64x^2+160x+100=36(x+3) \n 64x^2+160x+100=36x+108\n 64x^2+160x-36x+100-108=0 \n 64x^2+`124x-8=0 \n 4( 16x^(2) +31x-2)=0 \n$
$16x^(2) +31x-2=0 \n(x-2)(16x-1)=0 \n x+2=0 \n x=-2 \n 16x-1=0 \n x= (1)/(16)$

$\sqrt{2-7 \cdot(1)/(16) } - \sqrt{(1)/(16) +3} \neq 3 \n x=-2$

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When i was 4 years Old my sister was half my age now i am 100 how old is she?

Answers

Half of 4 is 2. She is 2 years younger than you. 100-2=98. She is 98.

32 is 40 percent of what number?

Answers

'is' in mathematics means equal
'of' in mathematics means multiplication

percent means over 100

32 = 40% * x

32 = 40/100 * x

32 = 4/10 * x

Multiply 10/4 on both sides, so we can isolate 'x'

32 * 10/4 = x

x = 8 * 10

x = 80

32 is 40 percent of 80.

∡1 and ∡2 are vertical angles. If m∡1 = 64°, find m∡2

Answers

Answer:

m∡2 = 64°

Step-by-step explanation:

By definition of vertical angles, the angles opposite of each other are equal each other.

∴ IF ∡1 and ∡2 are vertical angles, AND m∡1 = 64°, THEN m∡2 = 64°. (CPCTC - Definition of Vertical Angles).

Final answer:

Vertical angles are equal. Therefore, if ∡1 is 64°, then ∡2 is also 64°.

Explanation:

In mathematics, vertical angles are a pair of non-adjacent angles formed when two lines intersect. By definition, vertical angles are equal in measure.

Therefore, when angle 1 (∡1 ) and angle 2 ( ∡2 ) are vertical angles, if the measure of angle 1 ( m∡1 ) equals 64° as per the question, then the measure of angle 2 (m∡2) will also equal 64°.

So, m∡2 = 64°.

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Angle θ is in standard position. If (8, -15) is on the terminal ray of angle θ, find the values of the trigonometric functions.sin(θ) =

cos(θ) =

tan(θ) =

csc(θ) =

sec(θ) =

cot(θ) =

Answers

Answer:

Step-by-step explanation:

Alright, lets get started.

Please refer the diagram I have attached.

The point (8, -15) shows it is in 4th quadrant.

side X is 8 and side Y is -15.

We can find side R with help of Pythagorean theorem.

$R^2=8^2+(-15)^(2)=289$

Taking square root,

$R = 17$

sinΘ= $(Y)/(R)=(-15)/(17)$

cosΘ= $(X)/(R)=(8)/(17)$

tanΘ= $(X)/(Y)=(-15)/(8)$

cscΘ= $(R)/(X)=(17)/(-15)=-(17)/(15)$

secΘ= $(R)/(X)=(17)/(8)$

cotΘ= $(X)/(Y)=(8)/(-15)=-(8)/(15)$

Answer

Hope it will help :)

If the tournament is 195 miles away, how many gallons of gas will she have to purchase?g=2d/26

Answers

good question put a b c or d or else i cant help you

Determine whether the two lines are parallel, perpendicular, coinciding, or only intersecting.y = - 3x + 8
6x + 2y =1
Choose the correct answer below.
parallel
only intersecting
perpendicular
coinciding

Answers

Answer:

The lines are parallel

Final answer:

The two lines, y = -3x + 8 and 6x + 2y = 1, are parallel because they both have the same slope of -3.

Explanation:

To determine whether the two lines are parallel, perpendicular, coinciding, or only intersecting, one must look at their slopes. The slope of a line in the form y = mx + b is given by 'm'.

If two lines have the same slope, they are parallel. If the product of their slopes is -1, they are perpendicular. If the lines have the same slope and same y-intercept, they coincide.

{p}The first line given is y = -3x + 8, so its slope is -3.

The second line, 6x + 2y = 1, needs to be rearranged into the form y = mx + b. If you subtract 6x from both sides and divide by 2, you get y = -3x + 0.5. Thus, the slope of the second line is -3 as well.

Since both lines have the same slope of -3, they are parallel.

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