As a moving object's velocity decreases, its momentum decreases.Please select the best answer from the choices provided
T
F

Answers

Answer 1

Answer:

Explanation :

The momentum of an object is defined as the product of its mass and the velocity with which it is moving. It is denoted as p.

Mathematically, it is written as :

$p=mv$

m is the mass of an object

v is the velocity

So, it is clear that the momentum of an object is directly proportional to its velocity.

The statement "as a moving object's velocity decreases, its momentum decreases" is absolutely true.

Answer 2

Answer: From the choices provided, the better answer is 'T'. The other one does not apply.

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What if two planets collided with each other but their gravitational force kept them together? Could this be a new form of the Big Bang where they become one and life can still be formed?

Edwin Hubble categorized galaxies according to theirA. shapes.
B. colors.
C. food supplies.
D. inhabitants.

Answers

Your answer would be that Hubble categorized galaxies by their shape.

Car A has a mass of 1,200 kg and is traveling at a rate of 22 km/hr. It collides with car B. Car B has a mass of 1,900 kg and is traveling in the same direction at 25 km/hr. Which of the following statements is true?A) The momentum before the collision is equal to the momentum after the collision.

B) The momentum before the collision is greater than the momentum after the collision.

C) The momentum before the collision is less than the momentum after the collision.

Answers

The car A has a mass of 1200 kg.

The car B has the mass of 1900 kg.

It is given that velocity of car A is given as 22 Km/hr

The car B has the velocity of 25 Km/hr.

Let the mass of two bodies are denoted as $m_(1) \ and\ m_(2)$

Let the velocity of cars A and B are denoted as $v_(1) \ and\ v_(2)$

The momentum before collision is-

$p_(i) =m_(1) v_(1) +m_(2) v_(2)$

[Here p stand for momentum.]

We are asked to calculate the final momentum of the system after collision.

The answer of the question is based law of conservation of linear momentum.

As per law of conservation of linear momentum the sum total linear momentum for an isolated system is always constant.Hence irrespective of the type of collision[elastic and inelastic],the momentum of the system is always constant which is a universal truth.

Let after the collision the velocity of A and B are $v'_(1) \ and\ v'_(2)$

Hence the final momentum of the system is-

$p_(f) = m_(1) v'_(1) +m_(2) v'_(2)$

As per the law of conservation of linear momentum, the initial and final momentum must be equal i.e

$p_(i) =p_(f)$

$m_(1) v_(1) +m_(2)v_(2) =m_(1) v'_(1) +m_(2) v'_(2)$

Hence the option A is right.

A
This principle is known as the law of conservation of momentum.

The diagram below shows a 1.5 kilogram kitten jumping from the top of a 1.80 meter high refrigerator to a 0.90 meter highcounter.
Refrigerator
Counter
CO
The kitten's gravitational potential energy on top of the refrigerator is greater, but what is the kitten's gravitational
potential energy on top of the counter? Assume gravity as 10, if needed.

Answers

Answer:

E = 27 J

Explanation:

It is given that,

Mass of a kitten is 1.5 kg

Initially, it was at a height of 1.8 m refrigerator and finally jumps to a 0.9 m height counter.

We need to find the kitten's gravitational potential energy on top of the counter. Potential energy is possessed due to the position of an object. It can be given by :

$E=mgh$

g is acceleration due to gravity

$E=1.5\ kg* 10\ m/s^2* 1.8\ m\nE=27\ J$

So, the kitten's gravitational potential energy on top of the counter is 27 J.

The power expended when a 10 N barbell is raised 2. 0 m in 2s is

Answers

Work done = (force) x (distance)
   = (10 N) x (2 m) = 20 joules .

Power = (work done) / (time to do the work)
   =       (20 J) / (2 sec)
   = 10 joules/sec = 10 watts .

If you push on a wall with a force of 200n with what force does the wall push back

Answers

According to Newtons law, every action has an equal and opposite reaction. So if a student is pushing a wall with a force of 200n, then the wall is pushing the student with 200n

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