In the equation Q – 12 = 89, what is the value of Q

Answers

Answer 1

Answer: The answer is 101 because you add 89 and 12

Answer 2

Answer: Q-12=89 if you add 12 to 89 you get 101 and you cant divide 101 by Q because Q=1Q and you would just get 101 so i guess this is right

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Consider the function y = 1.065(4), which represents thegrowth of capital in a bank account.

The annual interest is

___%, and the bank compounds the interest_____

The balance of the account will

grow____

Answers

The annual interest rate is 6.5%, and the bank compounds the interest annually. The balance of the account will grow exponentially over time.

The given function y = 1.065(4) represents the growth of capital in a bank account, where the initial balance is 4 and the growth rate is 6.5% per year. To calculate the annual interest rate, we can use the formula A = P(1 + r/n)^(nt), where A is the final amount, P is the initial principal, r is the annual interest rate, n is the number of times interest is compounded per year, and t is the time in years.

In this case, the final amount after one year is 4 * 1.065 = 4.26. Substituting the values in the formula, we get 4.26 = 4(1 + r/1)^(1), which simplifies to 1 + r = 1.065. Solving for r, we get r = 0.065 or 6.5%.

The bank compounds the interest annually, which means that the interest is added to the account balance at the end of each year. As the balance grows, the interest earned in the subsequent years will be higher. This results in exponential growth of the account balance over time. After n years, the account balance will be B = P(1 + r)^n, where P is the initial balance, r is the annual interest rate, and n is the number of years.

For example, after 5 years, the account balance will be B = 4(1 + 0.065)^5 = 5.39. After 10 years, the account balance will be B = 4(1 + 0.065)^10 = 7.27. As we can see, the account balance grows significantly over time due to the effect of compounding interest.

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What is the volume of the trapezoidal right prism 20 m 2 m 8 ma. 98 m3
b.196 m3
c. 70 m3
d.392 m3

Answers

I think it's d. 392 m3

What percent of 17 is 20.4

Answers

If you would like to know what percent of 17 is 20.4, you can calculate this using the following steps:

x% of 17 is 20.4
x% * 17 = 20.4
x/100 * 17 = 20.4
x = 20.4 * 100 / 17
x = 120%

Result: 120% of 17 is 20.4.

20.4 is 120 percent (120%) of 17.

A value or ratio that may be stated as a fraction of 100 is referred to as a percentage in mathematics. If we need to compute a percentage of a number, we should divide it by its whole and then multiply it by 100. The proportion therefore refers to a component per hundred.

So, in order to find the percent of a number we need to multiply it by the percent value and then divide it by hundred. That means if we need to find the x% of a number, we should multiply the number with x/100.

So,

17 × x/100 = 20.4

17x = 20.4 ×100

17x = 2040

Therefore,

x = 2040/17

x = 120

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What is the expression of 2+32times5

Answers

Answer:

2+32×5

If you want the answer:

2+160

162

Step-by-step explanation:

Answer:

2+5^32

Step-by-step explanation:

You drive 6.0 km at 50 km/h and then another 6.0 km at 90 km/h. Your average speed over the 12 km drive will be _________

Answers

Answer:

$64.29\ (km)/(h)$

Step-by-step explanation:

hello

the speed is the relation between a distance traveled and the time used for it and it is given by the equation

$v =(displacement)/(time)\n (1)v=(d)/(t)$

Now, the average speed will be

$v_(average) =(displacement\ total)/(total\ time)\n (1)v=(d)/(t) \n(2)v_(average)=(d_(t) )/(t_(t) )$

Step 1

I drive 6.0 km at 50 km/h

from (1) it is possible to isolate t

$(1)v=(d)/(t)\nt=(d)/(v)$

Let

$v=50 (km)/(h) \nd=6.0 km\nt=(d)/(v) \nt=(6.0 km)/(50 (km)/(h))\nt_(1)=0.12\ hours\n$

Step 2

then I drive 6.0 km at 90 km/h

$v=90 (km)/(h) \nd=6.0 km\nt=(d)/(v) \nt=(6.0 km)/(90 (km)/(h))\nt_(2)=0.067\ hours\n$

Step 3

FInd total time and total displacement

$Total\ time=t_(1) +t_(2) \nt_(t) =0.12\ hours +0.067\ hours =0.187\ hours\n\ntotal\ distance\ =d_(1) +d_(2)=6.0\ km +6.0\ km= 12\ km\n$

step 4

finally, put these values into the equation(2)

$v_(average)=(d_(t) )/(t_(t) )\nv_(average)=(12\ km )/(0.187\ h )\nv_(average)=64.29\ (km)/(h)$

V=64.29 km/h

Have a good day

Answer:

64.2857 km/h

Step-by-step explanation:

Time taken to drive the first 6.0 km in hours = 6/50

Time take to drive another 6.0 km in hours = 6/90

Total time taken to drive 12 km in hours = (6/50) + (6/90)

= 6(50+90)/50x90

= 6x140/50x90

= 840/4500

The average speed over the 12 km is therefore 12 divided by 840/4500

= (12 x4500)/840

= 64.2857 km/h

The scatter plot below shows the number of prom tickets sold over a period of 7 days. The line of best fit drawn on the plot shown is used to predict the number of tickets sold on a certain day. Use the two points shown on the line of best fit to calculate its slope to the nearest tenth.