Which phase change in the Atmosphere forms clouds?.

Answers

Answer 1

Answer:

The phase is frequently used to describe transitions between the three fundamental states of matter. Condensation is the phase change in the atmosphere forms clouds.

What is phase transition?

The physical process of changing a medium's state from one to another is known as a phase transition in the domains of chemistry, thermodynamics, as well as other related sciences. The phase is frequently used to describe transitions between the fundamental states of matter.

The physical characteristics of a phase of such a thermodynamic system as well as the states of matter are constant. Some properties of a particular medium change throughout a phase transition as a result of a change in the environment, including such temperature or pressure. Condensation is the phase change in the atmosphere forms clouds.

Therefore, condensation is the phase change in the atmosphere forms clouds.

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Answer 2

Answer: Condensation of the evaporated water

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List 15 different energy sources

Answers

Outlit
Solar pannels stuff like that if thats what your looking for

An artificial satellite circling the Earth completes each orbit in 129 min(a) Find the altitude of the satellite.

(b) What is the value of g at the location of this satellite?

Answers

(a) $2.09\cdot 10^6 m$ above Earth's surface

The orbital speed of a satellite orbiting the Earth can be found using the equation

$v=\sqrt{(GM)/(r)}$

where

G is the gravitational constant

$M=5.98\cdot 10^(24) kg$ is the Earth's mass

r is the radius of the satellite's orbit

The orbital speed can also be rewritten as the ratio between the circumference of the orbit and the orbital period, T:

$(2\pi r)/(T)$

where

T = 129 min = 7740 s is the period

Combining the two equations,

$(2\pi r)/(T)=\sqrt{(GM)/(r)}$

And solving for r,

$((2\pi)^2 r^2)/(T^2)=(GM)/(r)\nr=\sqrt[3]{(GMT^2)/((2\pi)^2)}=\sqrt[3]{((6.67\cdot 10^(-11))(5.98\cdot 10^(24))(7740)^2)/((2\pi)^2)}=8.46\cdot 10^6 m$

This is, however, the orbital radius: this means we have to subtract the Earth's radius to find the altitude of the satellite, which is

$R=6.37\cdot 10^6 m$

therefore, the altitude of the satellite is

$h=r-R=8.46\cdot 10^6 - 6.37\cdot 10^6 =2.09\cdot 10^6 m$

b) $5.57 m/s^2$

The value of g at the location of the satellite is given by

$g=(GM)/(r^2)$

where:

G is the gravitational constant

$M=5.98\cdot 10^(24) kg$ is the Earth's mass

$r=8.46 \cdot 10^6 m$ is the radius of the satellite's orbit

Substituting into the equation, we find

$g=((6.67\cdot 10^(-11))(5.98\cdot 10^(24)))/((8.46\cdot 10^6)^2)=5.57 m/s^2$

Final answer:

The satellite orbits at an altitude of approximately 800 km. The gravitational constant, 'g', at this location is approximately 8.66 m/s^2.

Explanation:

The orbital period of an artificial satellite can be used to calculate the altitude at which it orbits. For a satellite that completes each orbit in 129 min (or approximately 2.15 hr), we can apply Kepler's third law which states that the square of the period of a satellite is proportional to the cube of its semi-major axis (distance from the center of the Earth to the satellite).

The formula for the altitude is given by: h = [(GMT^2)/(4π^2)]^(1/3) - R, where G is the gravitational constant, M the mass of Earth, T the orbital period, and R the Earth's radius. With the values G=6.67 x 10^-11 N(m/kg)^2, M=5.98 x 10^24 kg, T=2.15 hr = 7740s, and R=6.371 x 10^6 m, we get h approximately equals 800 km.

The value of 'g' at the satellite's location is given by g = GM/(R+h)^2. Substituting the aforementioned values, we get g to be approximately 8.66 m/s^2. This is less than the 9.81 m/s^2 at Earth's surface due to the increased distance from the Earth's center.

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Identify three devices that use Convex lenses. Please help.
(and no it doesn't give any options, it can be any device you can think of that uses a Convex lense)

Answers

Answer:

Explanation:

Convex lens is the lens which is used to converge the rays of light after refraction.

When the rays of light are coming parallel to the principal axis then after refraction they goes from the focus.

It is used as rear view mirror in automobiles. In this case it pelroduces small and erect image of faroff objects.

It is used in spectacles using for hypermetropia.

It is used in microscopes and telescopes.

Our eye also have a convex lens which forms images on retina.

Microscope lenses , glasses for people who can't see faraway as well and microwave lenses which reflect electromagnetic radiation. Oh and curved mirrors.

Why do trains use steel wheels rather than rubber tires? A) Steel wheels provide more grip, making it easier to stop a train.B) Rubber tires don't provide enough friction to allow the train to move.
C) Steel wheels increase friction, thus making it easier to move the load.
D) Steel wheels reduce friction, thus requiring less force to move the load.

Answers

D) steel wheels reduce friction, thus requiring less force to move the load. Friction between rubber and steel would be greater than steel and steel. Friction creates heat, which represents a loss of energy (which has to come from somewhere else - likely from the kinetic energy of the train)

Steel wheels reduce friction, thus requiring less force to move the load.

What is the mass of a bowling ball if it has a weight of 80N?

Answers

Answer:

8.1577297 kilograms

Explanation:

because its only 80N when your talking about different metric but if you wanted to know it in killograms there is your answer I hope this helps and can you please make me brainliest :)))

8.1577297 Kilograms :)

A graduated plank of length 90cm sits on a knife edge at 40cm mark. When a load of 50g is placed at 20cm, find the mass that will balance the plank at 70cm length.