Find the sum of the first 8 terms of the sequence. Show all work for full credit.1, -3, -7, -11, ...

Answers

Answer 1

Answer: $1, -3, -7, -11, ...\ \ \ \ \rightarrow\ \ \ the\ arithmetic\ sequence\n\nthe\ difference\ of\ the\ sequence\ is\ \ \ \ d=-3-1=-4\n\nthe\ sum:\ \ \ \ S_n= \frac{\big{2\cdot a_1+(n-1)\cdot d}}{\big{2}} \cdot n\n\n\nS_8= \frac{\big{2\cdot1+(8-1)\cdot(-4)}}{\big{2}} \cdot8=(2-28)\cdot4=-26\cdot4=-104\n\nAns.\ The\ sum\ is\ -104.$

Answer 2

Answer:

1 - 4 = -3. -3 - 4 = -11.

subtract by -4 until you have 8 numbers.

then add al the numbers together.

1+-3+-7+-11+-15+-19+-23+-27 = -104

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HELPPPP PLEASE I'M BEGGING HERE GUYS Solve for x: 3x + 5 = 20
Compare using <, >, or =. 1/2 ___ 5/10 < > =

The lengths of the sides of a triangle are 7. and 10. If the length of the longest side of a similar triangle is 25. what is the length of the shortest side of this triangle?

Answers

Answer: 17.5

Step-by-step explanation:

7:10 = x:25

times both sides by 25

25(7/10) =x

than solve for x

X = 25 × (7/10)

X = 17.5

What is 5m² when m = 6?

Answers

5 * 6^2
5 * 36
180

Answer: 180

The inverse of the function f(x) = x + 10 is shown.h(x) = 2x –

What is the missing value?

Answers

we have

$f(x) = (1)/(2)x + 10$

Step $1$

Let

y=f(x)

$y = (1)/(2)x + 10$

Exchange the variable x for y and variable y for x

$x = (1)/(2)y + 10$

Clear variable y

Multiply by $2$ both sides

$2x = y + 20$

$y = 2x-20$

Let

$f(x)^(-1) =y$

$f(x)^(-1)=2x-20$

therefore

the answer is

the inverse of the function is $f(x)^(-1)=2x-20$

the missing value is $20$

Answer:

The Given function is

y= x + 10

To find the inverse of function , we use the following procedure

x=y-10

Now, replace x by y and y by x, we get the inverse of function

y=x -10 , is the inverse of the function, y=x+10.

As, it is given that inverse of f(x) is h(x)

Also, h(x)= 2 x - k-------(1)

Inverse of f(x)=x+10 is ,y= x-10, that is 2 y=2 x- 20------(2)

Comparing 1 and 2, gives

h(x)=2 y

-k=-20

k=20

Given segment AB, explain how to construct a square with sides of length AB.

Answers

The square can be constructed by making perpendicular on vertex A and B. Then cut an arcs and obtain the points C and D and construct perpendicular on point C and D and get ABCD is required square.

Further Explanation:

Square is a 4 sided close figure.

Square has all sides equal and all angles are of .

The all sides of the square are perpendicular to each other.

Given:

A line segment AB.

Construction:

Steps involve in constructing a square from a line segment AB are as follows.

1. Draw a line segment AB.

2. Construct perpendicular AX at point A and then construct another perpendicular BY at point B.

3. Cut an arc on perpendicular line from A at point C that is equal to the length equal to side AB

4. Cut an arc on perpendicular line from B at point D that is equal to the length equal to side AB

5. Construct perpendicular at point C and then construct another perpendicular at point D.

6. The perpendicular intersects each other at point C and D.

The required square is ABCD is shown in figure attached.

Kindly refer to the image attached.

Learn more:

1. Learn more about inverse of the function brainly.com/question/1632445.

2. Learn more about equation of circle brainly.com/question/1506955.

3. Learn more about range and domain of the function brainly.com/question/3412497

Answer details:

Grade: Middle School

Subject: Mathematics

Chapter: Construction

Keywords: square, perpendicular, , intersect, construct, line, line segment, point, right angle, sides, close figure, arc, length.

1. Extend the segment AB twice left and twice right. Let the point that lies left be D and the point that lies right be C. Then AD=AB=BC.

2. Draw the circles with center at points D and B and congruent radii that are greater than AB. Denote two points of their intersection as E and F.

3. Combine points E and F. The segment EF is perpendicular to the segment AB and passes through the point A.

4. Draw the circles with center at points C and A and congruent radii that are greater than AB. Denote two points of their intersection as K and L.

5. Combine points K and L. The segment KL is perpendicular to the segment AB and passes through the point B.

6. Postpone on the segment EF point X such that AX=AB and on the segment KL point Y, such that BY=AB and X and Y lie for the same side.

7. Combine points X and Y. ABYX is required square.

-9y-6+7y=16
What is the answer for this?

Answers

-9y - 6 + 7y = 16
-9y + 7y - 6 = 16
      -2y - 6 = 16
   + 6   + 6
   -2y = 22
      -2    -2
   y = -11

Triangle ABC has side lengths 18,24, and 30. Do the side lengths form a Pythagorean triple? Yes or No?

Answers

Answer: Yes, the side lengths form a pythagorean triple.

Step-by-step explanation: Given that the side lengths of triangle ABC are as follows :

$AB=18,~~BC=24,~~CA=30.$

We are to check whether the side lengths form a pythagorean triple or not.

For making a pythagorean triple, the side lengths must satisfy the following :

$AB^2+BC^2=CA^2.$

We have

$AB^2=18^2=324,\n\nBC^2=24^2=576,\n\nCA^2=30^2=900.$

So,

$AB^2+BC^2=324+576=900=CA^2.$

Thus, the side lengths will form a pythagorean triple.

yes, the equation is a^2+b^2=c^2 so if u take 18^2+24^ it equals 900 so to test that you take 30^2 which is = to 900 also so yes

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