Determine the potential difference between two charged parallel plates that are 0.20 cm apart and have an electric field strength of 6.0 V/cm.

Answers

Answer 1

Answer: $V=Ed=0.20* 6=1.20$

Answer 2

Answer: V=E d
d=.20 cm
E=6 V/cm
V=.20×6
=1.2 V

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Why do paradigms change over time

Answers

Paradigms is a pattern or a model. They shift as a change in a way of thinking to another conclusion. After an amount of time they switch/shift into another pattern/position.

The work done by stretching a certain spring increases by 0.13x joules per centimeter (where x is the displacement, in centimeters, beyond the spring's natural length). How much work (in Joules) must be done in order to stretch the spring from x?

Answers

Answer:

$W = 0.06\cdot (x_(f)^(2)-x_(o)^(2))$

Explanation:

The work done by stretching the spring is:

$W = 0.13\int\limits^{x_(f)}_{x_(o)} x\, dx$

$W = 0.06\cdot (x_(f)^(2)-x_(o)^(2))$

If you have a mass of 55 kg and you are standing 3 meters away from your car, which has a mass of 1233 kg, how strong is the force of gravity between you and the car ?

Answers

Answer:

5.03×10¯⁷ N

Explanation:

From the question given above, the following data were obtained:

Mass of the person (M₁) = 55 Kg

Mass of the car (M₂) = 1234 Kg

Distance apart (r) = 3 m

Gravitational constant (G) = 6.673×10¯¹¹ Nm²/Kg²

Force (F) =?

The force between the person and his car can be obtained as follow:

F = GM₁M₂ / r²

F = 6.673×10¯¹¹ × 55 × 1234 / 3²

F = 6.673×10¯¹¹ × 67870/ 9

F = 5.03×10¯⁷ N

Thus, the force between the person and his car is 5.03×10¯⁷ N

Think about multiplying each speed by a factor to calculate kinetic energy at that speed.Is there a common factor that works for every speed? If so, what’s this factor?

Answers

Answer:

To calculate kinetic energy, you use the formula KE = 0.5 * m * v^2, where "m" is the mass and "v" is the speed. There isn't a common factor that works for every speed; the factor you use is 0.5. This formula is derived from the principles of classical mechanics and doesn't change with speed; it's a fundamental equation for calculating kinetic energy.

What 2 characteristics of stars are shown in an H-R diagram?

Answers

2 characteristics of stars are shown in an H-R diagram is Size and Color.

A sled with rider having a combined mass of 110 kg travels over the perfectly smooth icy hill shown in the accompanying figure. How far does the sled land from the foot of the cliff?

Answers

The sled land is "25.531 m" far from the foot of the cliff.

According to the question,

The velocity of the top = $V_t$

then,

→ $0.5 \ Vt^2-0.5 \ Vi^2 = -mgh$

→ $0.5 \ Vt^2 = 0.5 \ Vi^2- 9.8* 11$

→ $0.5 \ Vt^2 = 0.5 \ Vi^2- 107.8$

→ $=17.04 \ m/sec$

Now,

The projectile motion in horizontal direction,

→ $S_y = 11 = ut-0.5 \ gt^2$

$= 0-0.5* 9.8 \ t^2$

or,

→ $S_x = 17.04* 1.498$

$= 25.53 \ m$

Thus the above answer is the correct one.

Learn more:

brainly.com/question/13027204

Find the speed the sled has at the top of the hill from the law of conservation of mechanical energy. Equate the kinetic energy at the bottom of the hill to the kinetic plus potential energy at the top :

0.5mv₀² = 0.5mv² + mgh
v = √[v₀² - 2gh]
= √[(22.5m/s)² - (2 x 9.80m/s² x 11.0m)]
= 17.0m/s

From the time independent kinematics equation, find the vertical component of the sleds final velocity (note that the vertical component of the sleds initial velocity is zero) :

v² = v₀² + 2gΔy
= 0 + 2(-9.80m/s²)(-11.0m)
= -14.7m/s (select the neg root, because motion is downward)

With this you can find the time vertically which is the same horizontally :

v = v₀ + gt
t = (v - v₀) / g
= (-14.7m/s - 0) / -9.80m/s²
= 1.50s

Now, the horizontal distance is :

Δx = (v₀ + v)t / 2
= (17.0m/s + 17.0m/s)1.50s / 2
= 25.5m

tell me if you need more help :)

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