How many moles are represented by 118g of cobalt? Cobalt had an atomic mass of 58.93amu

Answers

Answer 1

Answer:

2.0 moles are represented by 118g of cobalt.

What are moles?

A mole is defined as 6.02214076 × $10^(23)$ of some chemical unit, be it atoms, molecules, ions, or others. The mole is a convenient unit to use because of the great number of atoms, molecules, or others in any substance.

$Moles = (mass)/(molar \;mass)$

$Moles = (118g )/(58.93amu)$

Moles = 2.0023757 = 2.0moles

Hence, 2.0 moles are represented by 118g of cobalt.

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Answer 2

Answer: n=m/M
n=118/58.93=2
Answer: 2 moles

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How many molecules are in 10 moles of Hydrogen?

Answers

Answer:3.2

Mass:32

Molecular weight: 10

Moles: 3.2

Write the balanced equation for the reaction that occurs when methanol, CH3OH (I) is burned in air. What is the coefficient of methanol in the balanced equation? (A) 1 (B) 3 (C) 2 (D) 4 (E) 3/2

Answers

Answer:

Explanation:

Methanol is an organic compound which burns with oxygen to produce carbon dioxide and water.

$2CH_3OH_((l))+3O_2_((g))\rightarrow 2CO_2_((g))+4H_2O_((g))$

Multiply coefficients times subscripts for each element in the formula, We get that there are 2 number of atoms of the carbon, 8 number of atoms of the hydrogen, and 8 number of atoms of the oxygen on both sides of equation. Hence, it is balanced.

The coefficient of methanol from the balanced reaction is 2.

What are the two parts of an atom?the nucleus and the proton cloud
the neutron and the electron cloud
O the neutron and the proton cloud
O the nucleus and the electron cloud

Answers

Answer:

the nucleus and electron cloud is the correct option

calculate the mass required to prepare 2.5 L of 1.0 M NaOH solution. Given that the molar mass for NaOH is 40 g/mol.

Answers

Answer:

$100\; \rm g$ of ${\rm NaOH}\; (s)$ would be required.

Explanation:

The quantity of solute in a solution of concentration $c$ and volume $V$ would be $n = c \cdot V$ .

It is given that volume $V = 2.5\; \rm L$ for the solution in this question. It is also given that the concentration of the $\rm NaOH$ solute in this solution is $c = 1.0\; \rm M$ , which is the equivalent to $c = 1.0\; \rm mol \cdot L^(-1)$ .

Apply the equation $n = c \cdot V$ to find the quantity of $\rm NaOH$ in this solution:

$\begin{aligned}n &= c \cdot V \n &= 1.0\; \rm mol \cdot L^(-1) * 2.5\; \rm L \n &= 2.5\; \rm mol\end{aligned}$ .

Multiply the quantity $n$ of $\rm NaOH$ in this solution with the formula mass $M$ of ${\rm NaOH}\!$ to find the corresponding mass:

$\begin{aligned}m &= n \cdot M \n &= 2.5\; \rm mol * 40\; \rm g \cdot mol^(-1) \n &= 100\; \rm g\end{aligned}$ .

Thus, this solution would contain $100\; \rm g$ of ${\rm NaOH}$ .

It would thus take $100\; \rm g$ of ${\rm NaOH}$ to prepare this solution.

Answer:

The required mass to prepare 2.5 L of 1.0 M NaOH solution is 100 g

Explanation:

We do this by preparing the equation:

Mass = concentration (mol/L) x volume (L) x Molar mass

Mass = 1.0 M x 2.5 L x 40 g/mol

Mass = 100 g

Which terms are used to identify pure substances?(1) an element and a mixture
(2) an element and a compound
(3) a solution and a mixture
(4) a solution and a compound

Answers

Answer is: (2) an element and a compound.

Pure substance is made of only one type of atom (element) or only one type of molecule (compound), mixtures and solutions are made from two or more types of pure substances.

Elements (for example copper, iron, sulfur) and compounds (water, sodium chloride) have definite and constant composition with distinct chemical properties.

Pure substances can be separated chemically, not physically, that is difference between pure substances and mixtures.

Find the product.
(n + 8)(n - 2)
n2- 6n - 16
n2+ 6n - 16
n2- 6n + 16