PHYSICS MIDDLE SCHOOL

If you can see the conductor in a lamp should you use it or not?

Answers

Answer 1
Answer: No because it's conducting heat and when it does that it means it's hot so you would burn yourself. 
Answer 2
Answer: Seeing does not matters . What matters is that can you be in direct contact woth the conductor or not (if there is a glass or plastic chamber or not).

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A car is strapped to a rocket (combined mass = 661 kg), and its kinetic energy is 66,120 J.At this time, the rocket runs out of fuel and turns off, and the car deploys a parachute to slow down, and the parachute performs 36,733 J of work on the car.What is the final speed of the car after this work is performed?
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How is continental lithosphere different from oceanic lithosphere

Answers

Continental lithosphere is thicker and less dense than oceanic
lithosphere. Continental crust is primarily composed of
granitic rock while oceanic crust is composed
primarily of basaltic rock.

The chemical formula for water, H2O, means that each water molecule contains

Answers

2 hydrogen molecules and one oxygen molecule

What is a bright, star like object in the galaxy core

Answers

the sun is a bright star 
sun   idk :00000000000000000

What comprises a team in basketball

Answers

teams in basketball are of 5 players, but often many subs
The players are set up around the key, 2 forwards, usually taller guys, either side of the net close to the end of the court, 2 guards, either side of the net but closer to the centre of the court than the forwards, and a centre, in the key a lot of the time, using lots of physical contact

A sample contains 100 g of a radioactive isotope. How much radioactiveisotope will remain in the sample after 2 half-lives? OA. 50 g
OB. 25 g
OC. 75 g
OD. 100 g

Answers

Answer:

B. 25 g

Explanation:

Given:

The initial mass of radioactive isotope is, m_0=100\ g

There is exponential decay of the isotope with time.

Half life means the time in which the given mass reduces by half. For every half life, the mass reduces by half of the previous mass.

So, for the first half life, the mass that remains is given as:

m_1=(m_0)/(2)=(100)/(2)=50\ g

Now, for the second half life, the mass 50 g is again reduced to half.

So, the mass that remains after 2 half-lives is given as:

m_2=(m_1)/(2)=(50)/(2)=25\ g

Therefore, the radioactive isotope that will remain in the sample after 2 half-lives is 25 g.

Answer:

its 12.5 g for anyone else who had different options

Explanation:

HELP ASAP REAL ANSWERS PLEASE You push a box across the floor with a force of 30 N. You push it 15 meters in 8 seconds. How much work did you do? How much power did you use?

Answers

When you lift a box up off the floor, you must exert a force at least equal to the weight of the box. If you lift the box at constant speed, you "do work" on the box that would be equal to the force you exert (the weight of the box) times the height through which you lifted the box. If you exert a force of 50 Newtons on the box and lift it 1 meter high, then you did (50 N)x(1 m) or 50 N-m of work on the object. 1 Newton-meter is called a Joule (J), pronounced "jewel." In lifting the 50 N box upward 1 meter at constant speed, you would do 50 Joules of work on the box. That means your body used 50 J of energy to lift the box.

and here is the Equation for Work: Work = Force x distance, or W = F d.

When you lift a box up off the floor, you must exert a force at least equal to the weight of the box. If you lift the box at constant speed, you "do work" on the box that would be equal to the force you exert (the weight of the box) times the height through which you lifted the box. If you exert a force of 50 Newtons on the box and lift it 1 meter high, then you did (50 N)x(1 m) or 50 N-m of work on the object. 1 Newton-meter is called a Joule (J), pronounced "jewel." In lifting the 50 N box upward 1 meter at constant speed, you would do 50 Joules of work on the box. That means your body used 50 J of energy to lift the box.

and here is the Equation for Work: Work = Force x distance, or W = F d.
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