Please help asap! question attached in file below

Answers

Answer 1

Answer:
All the angles around a point on one side of a line add up to 180°.

A). Look at the angles at point-D, above the line.
   You've got 40° and you've got a right angle ... 90°.
   Those two angles add up to (40° + 90°) = 130°.
   How much more is needed to make 180° ?
   (180° - 130°) = 50°. That's angle 'x'.

B). Look at the angles at point-C, below the line.
   You've got 55°.
   How much more is needed to make 180° ?
   (180° - 55°) = 125°. That's angle 'y'.

Answer 2

Answer: The answer is C.

m∠x = 50°
m∠y = 125°

m∠x + 40° = 90°
   x + 40 = 90
   - 40 - 40
   x = 50°

m∠y + 55° = 180°
   y + 55 = 180
   - 55    - 55
   y = 125°

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Marley drives to work every day and passes two independently operated traffic lights. The probability that both lights are red is 0.35. The probability that the first light is red is 0.48. What is the probability that the second light is red, given that the first light is red?a)0.13 b)0.35 c)0.48 d)0.73

Can someone help me in this trig question, please? thanks A person is on the outer edge of a carousel with a radius of 20 feet that is rotating counterclockwise around a point that is centered at the origin. What is the exact value of the position of the rider after the carousel rotates 5pi/12

Answers

The exact value of the position of the rider after the carousel rotates 5π/12 is 5 (-√2 + √6), 5(√2 + √6).

The position

Since the position of the carousel is (x, y) = (20cosθ, 20sinθ) and we need to find the position when θ = 5π/12 = 5π/12 × 180 = 75°

So, substituting the value of θ into the positions, we have

(20cos75°, 20sin75°)

The value of 20cos75°

20cos75° = 20cos(45 + 30)

Using the compound angle formula

cos(A + B) = cosAcosB - sinAsinB

With A = 45 and B = 30

cos(45 + 30) = cos45cos30 - sin45sin30

= 1/√2 × √3/2 - 1/√2 × 1/2

= 1/2√2(√3 - 1)

= 1/2√2(√3 - 1) × √2/√2

= √2(√3 - 1)/4

= (√6 - √2)/4

= (-√2 + √6)/4

So, 20cos75° = 20 × (-√2 + √6)/4

= 5 (-√2 + √6)

The value of 20sin75°

20sin75° = sin(45 + 30)

Using the compound angle formula

sin(A + B) = sinAcosB + cosAsinB

With A = 45 and B = 30

sin(45 + 30) = sin45cos30 + cos45sin30

= 1/√2 × √3/2 + 1/√2 × 1/2

= 1/2√2(√3 + 1)

= 1/2√2(√3 + 1) × √2/√2

= √2(√3 + 1)/4

= (√6 + √2)/4

= (√2 + √6)/4

So, 20sin75° = 20 × (√2 + √6)/4

= 5(√2 + √6)

Thus, (20cos75°, 20sin75°) = 5 (-√2 + √6), 5(√2 + √6).

So, the exact value of the position of the rider after the carousel rotates 5π/12 is 5 (-√2 + √6), 5(√2 + √6).

Learn more about position here:

brainly.com/question/11001232

$\bf \textit{the position of the rider is clearly }20cos\left( (5\pi )/(12) \right)~~,~~20sin\left( (5\pi )/(12) \right)\n\n-------------------------------\n\n\cfrac{5}{12}\implies \cfrac{2+3}{12}\implies \cfrac{2}{12}+\cfrac{3}{12}\implies \cfrac{1}{6}+\cfrac{1}{4}\n\n\n\textit{therefore then }\qquad \cfrac{5\pi }{12}\implies \cfrac{1\pi }{6}+\cfrac{1\pi }{4}\implies \cfrac{\pi }{6}+\cfrac{\pi }{4}\n\n-------------------------------$

$\bf \textit{Sum and Difference Identities}\n\nsin(\alpha + \beta)=sin(\alpha)cos(\beta) + cos(\alpha)sin(\beta)\n\ncos(\alpha + \beta)= cos(\alpha)cos(\beta)- sin(\alpha)sin(\beta)\n\n-------------------------------\n\ncos\left( (\pi )/(6)+(\pi )/(4) \right)=cos\left( (\pi )/(6)\right)cos\left((\pi )/(4) \right)-sin\left( (\pi )/(6)\right)sin\left((\pi )/(4) \right)$

$\bf cos\left( (\pi )/(6)+(\pi )/(4) \right)=\cfrac{√(3)}{2}\cdot \cfrac{√(2)}{2}-\cfrac{1}{2}\cdot \cfrac{√(2)}{2}\implies \cfrac{√(6)}{4}-\cfrac{√(2)}{4}\implies \boxed{\cfrac{√(6)-√(2)}{4}}\n\n\nsin\left( (\pi )/(6)+(\pi )/(4) \right)=sin\left( (\pi )/(6)\right)cos\left( (\pi )/(4) \right)+cos\left( (\pi )/(6)\right)sin\left((\pi )/(4) \right)$

$\bf sin\left( (\pi )/(6)+(\pi )/(4) \right)=\cfrac{1}{2}\cdot \cfrac{√(2)}{2}+\cfrac{√(3)}{2}\cdot \cfrac{√(2)}{2}\implies \cfrac{√(2)}{4}+\cfrac{√(6)}{4}\implies \boxed{\cfrac{√(2)+√(6)}{4}}\n\n-------------------------------\n\n20\left( \cfrac{√(6)-√(2)}{4} \right)\implies 5(-√(2)+√(6))\n\n\n20\left( \cfrac{√(2)+√(6)}{4} \right)\implies 5(√(2)+√(6))$

Driving at a constant speed, Reggie travels 300 kilometers in 1 hour. What is Reggie’s speed in kilometers per hour?

Answers

It is given in the question that Driving at a constant speed, Reggie travels 300 kilometers in 1 hour.

So here distance is 300 kilometers and time is 1 hour .

The formula of speed is

$speed = (distance)/(time)$

Substituting the given values of distance and time, we will get

$speed = \ frac{300}{1} km/hour$

So when distance is 300 km and time is 1 hour, so speed is 300 km/hour and that's the answer .

Answer: 300 kilometers per hour

Step-by-step explanation:

Given : Driving at a constant speed, Reggie travels 300 kilometers in 1 hour.

Now, the formula to find speed is given by:-

$\text{Speed}=\frac{\text{distance}}{\text{time}}$

i.e. Reggie’s speed in kilometers per hour = $(300)/(1)$

i.e. Reggie’s speed in kilometers per hour = $300$

Hence, Reggie’s speed is 300 kilometers per hour.

The ordered pair (2, 36) is a solution for which equation(s)? Check all that apply. A. y = (x + 4)2
B. y = 7x2 + 2
C. y = (3x)2
D. y = 2x2

Answers

plug it into each equation and see if both sides are equal:
A. 36 = (2+4)^2 -> 36 = 36 works
B. 36 = 7(2)^2 +2 -> 36 = 30 doesn't work
C. 36 = (3(2))^2 -> 36 = 36 works
D. 36 = 2(2)^2 -> 36 = 8 doesn't work

What is the sum of 17 and a difference of 3?

Answers

I think you meant: Which TWO NUMBERS are the sum of 17 and have a difference of 3?

Well, it's simple: Guess and check.
The two numbers must be bigger than 3 and smaller than 17. Hmm...

So, you can conclude 10 and 7, b/c 10+7 is 17 and 10-7 is 3.

Two welders working together can complete a job in 6 h. One of the welders, working alone, can complete the task in 15 h. How long would it take the second welder, working alone, to complete the task?

Answers

ur asking a bunch of these kind of rate problems xD
$6 ( (1)/(15) + (1)/(x) )=1$
In 6 hrs, the welder who does 1/15 of the job in 1 hr and the welder who does 1/x in 1 hr, complete the job (6 hrs.)
$(1)/(15) + (1)/(x) = (1)/(6)$
Multiply 30 on both sides to cancel out the fractions and we get:
$2 + (30)/(x) =5$
Solving for x:
30/x=3
3x=30
x=10
The second welder would take 10 hours.

How do u write 6/20 in percentage form?

Answers

6/20
= (6*5) / (20*5)
= 30/100
= 30%

6/20 in percentage form is 30%.

Solve:-

6/20

Change to decimal:-

6 ÷ 20 = 0.3

Change to percent:-

0.3 × 100 = 30
30%

So, 6/20 in percentage form is 30%.