What are the kinds of formulas to remember in 8th grade?

Answers

Answer 1

Answer: The best formulas to remember from the 8th grade are the ones
that have been introduced in 8th grade math class, and which have
been used to solve the math homework assigned in 8th grade.
This sneaky trick works every time, and most kids never think of it..

Answer 2

Answer: you should better know formula of circumference and areas of circle. rectangle . triangle etc also for speed, velocity ... also some important conversions...

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ilia earns $15 for each job he completes as a handyman alongside his uncle. he calculates his total job expenses for supplies to be $s. write an expression to show the amount of money ilia will have after 20 jobs.

Answers

If you are asking how much money would he have after 20 jobs while earning 15$ for each, here is the answer and explanation.

llia will have 300$ after 20 jobs. If he gets 15$ for each job then 1 is 15$, 2 is 30$, and so on. So we multiply 20 jobs x 15$ and that gives us 300$. I Hope this helps

Multiplii si submultipli Voltului

Answers

Answer:

Multiples and Submultiples of Volts.

Multiples and submultiples are prefixes and sufixes which are used to express a higher or lower number of a magnitude.

From least to greatest.

Multiples are: deka, hecto, kilo, mega, giga, tera, peta, exa, zetta, yotta.

Submultiples are: deci, centi, mili, micro, nano, pico, femto, atto, zepto, yokto.

Multiples of volts are:

dekavolts: $10V$

hectovolts: $10^(2) V$

kilovolts: $10^(3) V$

megavolts: $10^(6)V$

gigavolts: $10^(9)V$

teravolts: $10^(12)V$

petavolts: $10^(15) V$

exavolts: $10^(18)V$

zettavolts: $10^(21)V$

yottavolts: $10^(24) V$

Submultiples of volts are:

decivolts: $10^(-1)V$

centivolts: $10^(-2)V$

milivolts: $10^(-3) V$

microvolts: $10^(-6)V$

nanovolts: $10^(-9) V$

picovolts: $10^(-12)V$

femtovolts: $10^(-15)V$

attovolts: $10^(-18)V$

zeptovolts: $10^(-21)V$

yoktovolts: $10^(-24)V$ .

MV =MegaVolt   (1 MV = 1000000 V)
KV = KiloVolt   (1 KV = 1000 V)
V = Volt   (1V = 1 V)   :))
mV   = miliVolt (1V = 1000 mV)
μV = microVolt (1V) = 1000000 μV

- Trevon invested $1.500 in an account with an interest rate of 4.25%. If he plans to retire in 18 1/2 years, how much total will be in theaccount?

Answers

Answer:

I=PRT is the formula

Step-by-step explanation:

Principal is $1,500. The interest rate is 4.25% and the time is 18.5 years.

That's all i know good luck

Jenna flips to pennies 105 times how many times can she expect both coins to come up heads

Answers

53 because there is only 2 sides of a penny so 105 divided by 2 is 52.5

Half heads. Half tails. Now I just have to get more characters but the first two sentences were the answers.

Shelley compared the number of oak trees to the number of maple trees. she counted 9 maple trees to every 5 oak trees in the beginning of the year. at the end of the year,the new ratio of the number of maple tree to the number of oak trees is 3:11. at the end of the year,there were 132 oak trees . how many more maple tree were then in the beginning of the year than the end of the year? explain

Answers

so at the end of the year maple:oak=3:11 and there were 132 oak so 132=11 units 132/11=12 so there were 3 times 12 maple trees at the end or 36 so 36:132
assuming the units stay the same (1 unit=12) in the biginning of the year there were 108 maple trees
108-36= 72
there were 72 more

Plot the zeros of the polynomial y = x4 + 3x3 − 27x2 + 13x + 42

Answers

Answer:

See explanation

Step-by-step explanation:

Consider the polynomial $y=x^4+3x^3-27x^2+13x+42$ 4th power polynomial function has at most 4 zeros.

Integer zeros can be only among the divisors of 42:

$\pm1, \ \pm 2,\ \pm 3,\ \pm 6,\ \pm 7,\ \pm 14,\ \pm 21,\ \pm 42$

Check them:

$y(1)=1^4+3\cdot 1^3-27\cdot 1^2+13\cdot 1+42=1+3-27+13+42=32\neq 0\n \ny(-1)=(-1)^4+3\cdot (-1)^3-27\cdot (-1)^2+13\cdot (-1)+42=1-3-27-13+42=0\n \ny(2)=2^4+3\cdot 2^3-27\cdot 2^2+13\cdot 2+42=16+24-108+26+42=0\n \ny(3)=3^4+3\cdot 3^3-27\cdot 3^2+13\cdot 3+42=81+81-243+39+42= 0\n \ny(-7)=(-7)^4+3\cdot (-7)^3-27\cdot (-7)^2+13\cdot (-7)+42=2,401-1,029-1,323-91+42= 0$

Thus,

$y=(x+7)(x+1)(x-2)(x-3)$

Zeros are plotted in attached diagram.

Answer:

The remainder is 0, so -1 is a zero of the polynomial and x + 1 is another factor: (x − 2)(x + 1)(x2 + 4x − 21). Now factor the remaining polynomial using normal means. The fully factored form is (x − 2)(x + 1)(x + 7)(x − 3), so the zeros of the polynomial are x = 2, -1, -7 and 3.

Step-by-step explanation:

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