There are 4 more girls in Mrs. Pitt's class than Mr. Brown's class.  Five girls moved from Mrs. Pitt's class to Mr. Brown's class.  Now there are twice as many girls in Mr. Brown's class as there are in Mrs. Pitt's.  How many girls were in Mr. Brown's class to begin with?

Two-fifths time a plus a over 2 equals a minus 2 will be a=20

Step-by-step explanation:

We have to find a, by first writing the verbal expression into an arithmetic form as,

Two fifths times a = (2/5)a

a over 2 = a/2

a minus 2 = a-2

(2/5)a + (a/2) = a-2

We have to take LCM on LHS as 10.

(2×2 /5×2)a + (a×5 /2×5) = a-2

(4a/10) + (5a/10) = a-2

Moving 10 to the other side, we will get,

4a+ 5a = 10(a-2)

9a = 10a -20

Grouping terms we will get,

10a - 9a = 20

a = 20

The solution is, the number is,  x < 12

What is number?

A number is a mathematical object used to count, measure, and label. The original examples are the natural numbers 1, 2, 3, 4, and so forth. Numbers can be represented in language with number words.

here, we have,

A number would be:- x

Less than is >

x < 12

Hence, the number is : x < 12

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Hi there!

In order to use the elimination method, you have to create one variable that has the same coefficient. This is to be able to eliminate one variable and have a one variable equation (which you can then solve).

In your case, we'll have the "x" have the same coefficient by multiplying the top equation by 4 and the bottom equation by 2 :

4( -2x + 3y = -4) → -8x + 12y = -16

2( 4x - 2y = 16) → 8x - 4y = 32

Now that both of your equation have a variable with the same coefficient, you need to choose rather you need to add or subtract the equations in order to get rid of the variable (in this case we want to get rid of the "x").

In your case, you want to add both equation together which will give you :

8y = 16

Now that you only have one variable, all you need to do now is solve the equation for "y" :

8y = 16

Divide each side of the equation by 8

y = 2 → Your answer

There you go! I really hope this helped, if there's anything just let me know! :)

If the given line's equation is y = 6, then it is a horizontal line. Therefore, the parallel line must also be horizontal, and pass through (3, 4). In order for the line to pass through (3, 4), the y needs to be at 4, so the equation of the parallel line would be y = 4.

Hope this helps! :)

Answer: 144

Step-by-step explanation:

Answer:

its 144 i just did the same question

Step-by-step explanation: