A man is carrying a trolley of mass 6kg and having K.E. of 40 J . Calculate its velocity with which he is running .

Answers

Answer 1

Answer: The formula to find kinetic energy is -

$K.E. = (1)/(2)*m* v^(2)$

Where,

$m = mass$

and

$v = velocity$

So, putting the values in the formula we get -

$40 = (1)/(2) *6*v^(2)$

$(40)/(3) = v^(2)$

$\sqrt (40)/(3) = 3.6514 m/s$

Answer 2

Answer: As we know that K.E = 1/2 mv² so
by arranging it
K.E ×2÷6 = v²
now by putting values
v²=13.33 m²/s²
so
v= 3.65 m/s....

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Which force causes a wagon to speed up as it rolls down a hill?

Answers

Answer: The correct answer is force of gravity.

Explanation:

Gravity is the force with which one body attracts the other body.

It goes down a hill with the increase in the kinetic energy. The kinetic energy is due to the motion of a wagon.

At the hill the gravity is lesser in comparison to the gravity on the surface of the earth.

When a wagon rolls down a hill it speeds up. Here, the earth attracts the wagon with the force of gravity. It accelerates down a hill with an acceleration due to gravity.

Gravity is the only one helping it.

When cleaning a storage battery you can use a solution of water and ammonia or solution of water and

Answers

Water and baking soda can be used, too.

You check the weather and find that the winds are coming are coming from the west at 15 miles per hour. This information describes wind's velocity, direction, acceleration, or speed?

Answers

Velocity
It is not showing acceleration, or changes in speed
It is showing direction, but not only that
It is showing speed, but not only that

It is showing speed and direction, which is Velocity

Answer:

velocity

Explanation:

2a. Abecomes
jeep starts from it the
starts from it the state of rest. If its
velocity 60m/s and its take 5 minute: what is the accelera
ution of the jeep
the distanced travelled by
the jeep:

Answers

$\bf \underline{ \underline{Given : }}$

Initial velocity,u = 0 m/s

Final velocity,v = 60 m/s

Time taken,t = 5 min = 5 × 60 sec = 300 seconds

$\bf \underline{ \underline{</p><p>To \: be \: calculated : }}$

Calculate the acceleration ( a ) and distance (s ) covered by the jeep.

$\bf \underline{ \underline{Solution : }}$

We will first calculate the acceleration of the jeep.

CASE 1 :

By Using first equation of motion ,

$\sf \: v = u + at$

$\sf \star \: Substituting \: the \: values...$

$\sf\rightarrow \: 60 = 0 + a * 300$

$\sf \rightarrow \: 60 = 300a$

$\sf \rightarrow \: 300a = 60$

$\sf \rightarrow \: a = \cancel (300)/(6)$

$\sf \rightarrow \: a = 50 \: m {s}^( - 2)$

Thus,the acceleration of the jeep is 50 m/s².

Now, Let us calculate the distance travelled by the jeep.

CASE 2 :

By Using third equation of motion ,

$\sf {v}^(2) = {u}^(2) + 2as$

$\sf \star \: Substituting \: the \: values...$

$\sf \rightarrow \: {60}^(2) = {0}^(2) + 2 * 50 * s$

$\sf \rightarrow \: 3600 = 100s$

$\sf \rightarrow \: 100s = 3600$

$\sf \rightarrow \: s = \cancel(3600)/(100)$

$\sf \rightarrow \: s = 36 \: m$

Thus,the distance covered by the jeep is 36 m .

Within a single fiber, the tension developed during a twitch depends upon the

Answers

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Help with number 32
Apparently the answer is 4 but I have no idea why

Answers

All you have to remember is that when the source is APPROACHING the observer,
the frequency seems HIGHER than what's actually leaving the source.

The siren is wailing at 1,000 Hz.

(1). 30.0 Hz . . . that's way lower

(2). 9.19 x 10² Hz = 919 Hz . . . that's lower

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(4). 1.10 x 10³ Hz = 1,100 Hz . . . that's the only choice that's higher than 1,000 Hz.

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