In the following reaction, how many grams of NaBr will produce 244 grams of NaNO3? Pb(NO3)2(aq) 2 NaBr(aq) PbBr2(s) 2 NaNO3(aq) The molar mass of NaBr is 102.9 grams and that of NaNO3 is 85 grams

Answers

Answer 1
Answer:

Answer : The mass of NaBr is, 295.323 grams

Solution :

First we have to calculate the moles of NaNO_3.

\text{Moles of }NaNO_3=\frac{\text{Mass of }NaNO_3}{\text{Molar mass of }NaNO_3}=(244g)/(85g/mole)=2.87moles

Now we have to calculate the moles of NaBr.

The balanced chemical reaction is,

Pb(NO_3)_2(aq)+2NaBr(aq)\rightarrow PbBr_2(s)+2NaNO_3(aq)

From the balanced reaction we conclude that

As, 2 moles of NaNO_3 react with 2 moles of NaBr

So, 2.87 moles of NaNO_3 react with 2.87 moles of NaBr

Now we have to calculate the mass of NaBr.

\text{Mass of }NaBr=\text{Moles of }NaBr* \text{Molar mass of }NaBr

\text{Mass of }NaBr=(2.87mole)* (102.9g/mole)=295.323g

Therefore, the mass mass of NaBr is, 295.323 grams


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Find a mole of 0.0960 g of H2SO4

Answers

Molar mass H₂SO₄ = 98.079 g/mol

1 mol -------- 98.079 g
? mole ------ 0.0960 g

moles = 0.0960 * 1 / 98.079

= 0.0960 / 98.079

= 9.788 x 10⁻⁴ moles

hope this helps!

Final answer:

The number of moles of 0.0960 grams of H2SO4 can be calculated using the formula: mole = mass / molecular weight. Given that the molecular weight of H2SO4 is 98.08 g/mol, we find that 0.0960 grams of H2SO4 is approximately 0.000978 moles.

Explanation:

The question is asking us to find a mole of 0.0960 g of H2SO4. In order to solve it, we need to know the molecular weight of H2SO4 (Sulfuric acid), which is approximately 98.08 g/mol.

This means that 1 mole of H2SO4 has a mass of 98.08 grams. We would now like to find out how many moles correspond to 0.0960 grams.

We use the equation: mole = mass / molecular weight, thus: mole = 0.0960 g / 98.08 g/mol = 0.000978 moles.

Therefore, 0.0960 grams of H2SO4 corresponds to approximately 0.000978 moles.

Learn more about Mole Calculation here:

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Answers

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