Explain how you can tell 31\33 is in simplest form

Answers

Answer 1
Answer: because the factors of 33 are 11 and 3
31 doesn't have a factor of 11 or 3 so it is simplest form

also, 31 is prime so it can't be factored

Related Questions

4(x+1)-ax=x+5 solve for x
WHAT IS THE ANSWER TO 0.16PSQUARED-0.0025
the perimeter of a square is 56 cm. what is the approximate length of its diagonal? 10.6 cm 14.0 cm 15.0 cm 19.8 cm
4. Solve the quadratic by factoring, isolating x^2, or using the quadratic formula:a. 2x^2 – 7x = 4b. 81x^4 – 1c. 2x^2 – 32 = 0d. X^2 – 7x + 12
What are the leading coef 18w+4-w^(9)

The perimeter of a parallelogram is 46in. If the length of one side is 14in., what is the length of a side adjacent to it?

Answers

Adjacent means connected to so you are looking for the width.

Perimeter = 2(length) + 2(width)
P = 2l + 2w

46 = 2l + 2w
l = 14

46 = 2(14) + 2w
46 = 28 + 2w
18 = 2w
9 = w

Width: 9 inches

Helloooo any help :( ?

Answers

Answer:

1/2p+2=3 1/2

Step-by-step explanation:

Answer:

\frac12p+2 = 3\frac12

Step-by-step explanation:

The time he spends is the sum of the mandatory 2 hours and p times the half hour per puzzle. It has to end up to 3 1/2, so that's how you get the equation.

Of course, you can solve it as

p = (1\frac12)/(\frac12) = 3

A football team loses 2 yards every 5 minutes. How many yards did the team lose after 15 minutes?

Answers

Answer:

6 yards

Step-by-step explanation:

Kay builds a 1/6 scale model of a train. The actual train is 42 1/2 feet long. How long is the model

Answers

 7 1/12 feet long..
42 1/2 * 1/6 = 7 1/12

Carlos had to manage his inventory of veggies. He had to balance the number of carrots, c, with the number of tomatoes, t. 4c - 6t = 6 2c + 2t = 8. How many tomatoes should he have?

Answers

carlos should have 1 tomato
if you solve the 2nd equation for c and plug it in you get 1

MULTIPLE CHOICE, PLS HELP!!θ lies in Quadrant II .

sinθ=4/7

What is the exact value of cosθ in simplified form?

Answers

We know that : Sin²θ + Cos²θ = 1

Given : Sinθ \bf{= (4)/(7)}

\bf{\implies ((4)/(7))^2 + Cos^2(\theta) = 1}

\bf{\implies Cos^2(\theta) = 1 - (16)/(49)}

\bf{\implies Cos^2(\theta) =((49 - 16)/(49))}

\bf{\implies Cos^2(\theta) =((33)/(49))}

\bf{\implies Cos(\theta) = (\pm)((√(33))/(7))}

Given : θ lies in Quadrant II

We know that : Cosθ is Negative in Quadrant II

\bf{\implies Cos(\theta) = (-)((√(33))/(7))}

Option 3 is the Answer