Your friend is asked to differentiate between evaporation and boiling.what questions could you ask to make him to know the difference between evaporation and boiling?physics question.
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Answer:
Boiling is the "rapid vaporization of liquid" when the liquid is heated at the point where the pressure of the vapor is equal to the pressure exerted by the atmosphere in the liquid.
So during the boiling, the vaporization of the water is also occurring but is a little bit more complex.
Some questions that you may ask your friend to differentiate those two phenomena are:
Which one is used to cook things like pasta? (boiling)
in which process, a liquid is transformed into a gas? (evaporation)
Which one includes the other? (boiling)
Final answer:
Evaporation and boiling are both phases changes, but they differ in the specifics of how and when they happen. These differences involve the temperature and location within the liquid where they occur, as well as the speed of the process.
Explanation:
To differentiate between evaporation and boiling, you could ask your friend these questions:
- Does the process occur at any temperature or only at a specific temperature (the boiling point)? (Evaporation can occur at any temperature while boiling only occurs at the boiling point.)
- Does the process occur throughout the liquid or only at the surface? (Boiling occurs throughout the liquid while evaporation happens only at the surface.)
- Is the process slow or fast? (Evaporation is a slow process while boiling is relatively quick.)
By asking these questions, your friend will be able to identify the key differences that separate evaporation from boiling.
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The angular velocity of the earth is
The satellite tangential velocity is the distance from the earth times the angular velocity, which is
For meters per second, we divide by the number of seconds in an hour, which is 3600:
Final answer:
The tangential velocity of a satellite, with the same angular velocity as the Earth and 5x10^7 m distance from Earth's center, is calculated to be approximately 3650 m/s.
Explanation:
The tangential velocity of a satellite is given by the formula v = rω, where 'v' is the tangential velocity, 'r' is the radius (distance from the center of the Earth to the satellite), and 'ω' is the angular velocity. The referenced satellite's angular velocity is the same as that of the Earth, which is approximately 7.292 x 10^-5 rad/s. Given r = 5x10^7 m (the satellite's distance from Earth), we input these values into the formula:
v = (5x10^7 m)(7.292 x 10^-5 rad/s)
Upon calculation, we find that the satellite's tangential velocity is approximately 3650 m/s.
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Stockholm, Copenhagen, Rome, or Madrid. There is no reason to expect a
different outcome in any other world capital.
Any questions comment or message me!
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The sled land is "25.531 m" far from the foot of the cliff.
According to the question,
The velocity of the top =
then,
→
→
→
→
Now,
The projectile motion in horizontal direction,
→
or,
→
Thus the above answer is the correct one.
Learn more:
0.5mv₀² = 0.5mv² + mgh
v = √[v₀² - 2gh]
= √[(22.5m/s)² - (2 x 9.80m/s² x 11.0m)]
= 17.0m/s
From the time independent kinematics equation, find the vertical component of the sleds final velocity (note that the vertical component of the sleds initial velocity is zero) :
v² = v₀² + 2gΔy
= 0 + 2(-9.80m/s²)(-11.0m)
= -14.7m/s (select the neg root, because motion is downward)
With this you can find the time vertically which is the same horizontally :
v = v₀ + gt
t = (v - v₀) / g
= (-14.7m/s - 0) / -9.80m/s²
= 1.50s
Now, the horizontal distance is :
Δx = (v₀ + v)t / 2
= (17.0m/s + 17.0m/s)1.50s / 2
= 25.5m
tell me if you need more help :)