The focal length is the distance from the midline of the lens to the _____.image
object
focal point
2F position

Answers

Answer 1

Answer:

The focal length is the distance from the mid-line of the lens to the Focal Point.

Focal point lies at a distance which is half the radius of curvature of the lens. hence focal length is also given by the formula

f = R/2

where f = focal length

R = radius of the focal length

hence the correct choice is focal point.

Answer 2

Answer:

Answer:

FOCAL POINT

Explanation:

JUST TOOK TEST

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The sound wave produced can best be described as a ?

Answers

the sound wave produced can be described As a longitudinal wave of constant frequency

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When preparing for a rocket launch, the mission control center uses the phrase "T minus" before liftoff. ...T minus 3, T minus 2, T minus 1, ... After the rocket has launched, "T plus" is used while the rocket is in flight. ...T plus 1, T plus 2, T plus 3, ... When does the rocket launch? What does "T" represent?

Answers

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Answers

Answer:0.015 m

Explanation:

Given

distance between two slits(d)=0.050 mm

Distance between slit and screen=2.5 m

Wavelength $(\lambda )=600 nm$

and distance between First order and second order $=(D\lambda )/(2d)$

$=(2.5* 600* 10^(-9))/(2* 5* 10^(-5))$

$=15* 10^(-3)$

=0.015 m

A subway train starts from rest at a station and accelerates uniformly at 1.8m/s^2 for 15 sec. then it runs at a constant speed for the next 35 sec. before decelerating at 2.0m/s^2 until it comes to rest at the next station. FIND THE DISTANCE between the stations and the AVERAGE SPEED of the train.(please show step by step and the formula that is used. Thank you!)

Answers

This looks so scary just because there are so many parts to it.
Take them one at a time:

First piece:
From rest, accelerates 1.8 m/s² for 15 sec.
Speed at the end of the 15 sec = 1.8 x 15 = 27 m/s
Distance covered = (average speed) x (time) = (13.5) x (15) = 202.5 meters

Middle piece:
Starts this piece at 27 m/s.
Runs at constant speed for 35 sec.
Covers (27 x 35) = 945 meters
Finishes this piece (15 + 35) = 50 seconds after leaving the first station
Finishes this piece (202.5 + 945) = 1147.5 meters from the first station.

Last piece:
Starts this piece 50 seconds after leaving the first station,
1147.5 meters from it, still moving at 27 m/s.
Decelerates at 2.0 m/s² .
--> It takes 27/2.0 = 13.5 seconds to come to a stop.
--> Distance covered during this piece = (average speed) x (time)
= (13.5 m/s) x (13.5 sec) = 182.25 meters
Finishes this piece (50 + 13.5) = 63.5 seconds after leaving the first station
Finishes this piece (1147.5 + 182.25) = 1,329.75 m from the first station

Distance between the stations (along the track) = 1,329.75 meters.

Average speed = (total distance) / (total time) = 1,329.75 / 63.5 = 20.941 m/s.

I sure hope I didn't make any stupid arithmetic blunders here,
because I really don't feel like going back and checking it.
Let me know, and I'll fix them.

What is force of inertia?????????

Answers

The force of inertia is the property common to all bodies that remain in their state, either at rest or in motion, unless some external cause is introduced to make them alter this state.

What is the acceleration of a 0.30 kilogram ball that is hit with a force of 25 N?

Answers

In order to calculate the acceleration on the ball, we use Newton's second law of motion, F = ma. Here, F is the resultant force, m is the mass of the body and a is the acceleration of the body. Therefore, a = F/m. a = 25 / 0.3 = 83 m/s^2.I hope that my answer is helpful! Let me know if you need something more :)

Answer : Acceleration will be $83.3 m/s^(2)$