Atoms of which types of elements tend to gain electrons? Atoms of which types of elements tend to lose electrons?
Answers
Final answer:
Nonmetals, such as those in groups 14 and 17, generally gain electrons becoming more stable anions. Metals, like those in group 1, typically lose electrons and form stable cations. An example is in ionic compounds where metal atoms like sodium lose electrons and nonmetal atoms like chlorine gain electrons.
Explanation:
In the context of elements and their atoms, nonmetals, which include elements from group 14 and group 17, tend to gain electrons. This gain in electrons forms negative ions, or anions, which fills their outermost electron shell, making them energetically more stable.
On the other hand, metals like those from group 1, tend to lose electrons. This event makes them energetically more stable by forming positive ions, or cations, and allowing them to achieve an electron configuration similar to noble gases.
For instance, to fill their outermost shells, elements donate or accept electrons. In ionic compound formation, metals like sodium (Na) lose electrons while nonmetals like chlorine (Cl) gain these electrons, achieving a stable configuration.
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(2) 3.82 d (4) 34.38 d
Answers
Answer : The correct option is, (2) 3.82 d
Solution : Given,
As we know that the radioactive decays follow first order kinetics.
So, the expression for rate law for first order kinetics is given by :
where,
k = rate constant
t = time taken for decay process = 11.46 days
a = initial amount of the reactant = 200 g
a - x = amount left after decay process = 25 g
Putting values in above equation, we get the value of rate constant.
Now we have to calculate the half life of a radioisotope.
Formula used :
Putting value of 'k' in this formula, we get the half life.
Therefore, the half-life of a radioisotope is, 3.820 d
2. 11.46/3=3.82
The answer is (2).
B. Monomer
C. Polymer
D. Organic
Answers
Answer:
c
Explanation:
(2) 200. K to 400. K (4) 200.°C to 400.°C
Answers
Answers
Answer:
The answer to your question is: 1, 2, 1, 2
Explanation:
1 Fe(s) + 2 Na⁺(aq) → 1 Fe²⁺(aq) + 2 Na(s)
Fe⁰ - 2e⁻ ⇒ Fe⁺² Oxidases
Na⁺ + 1 e⁻ ⇒ Na⁰ Reduces
1 x ( 1 Fe⁰ ⇒ 1 Fe⁺²) Interchange number of
2 x ( 2Na⁺ ⇒ 2 Na⁰ ) electrons
Final answer:
To balance the oxidation-reduction reaction Fe(s) + Na+(aq) → Fe2+(aq) + Na(s), follow these steps: balance atoms other than hydrogen and oxygen, balance hydrogen atoms, balance oxygen atoms, verify charges
Explanation:
To balance the oxidation-reduction reaction Fe(s) + Na+(aq) → Fe2+(aq) + Na(s), we need to balance the number of atoms for each element and the total charge on both sides of the reaction. Here's the step-by-step process:
- First, balance the atoms other than hydrogen and oxygen. There is only one atom of Fe on each side, so this is already balanced.
- Next, balance the hydrogen atoms. We have no hydrogen on the left side and one hydrogen on the right side, so we need to add a coefficient of 2 in front of Na(s): 2Na(s).
- Now, balance the oxygen atoms. We have no oxygen on the left side and one oxygen in Fe2+(aq), so we need to add a coefficient of 2 in front of Fe2+(aq): 2Fe2+(aq).
- Finally, verify that the charges are balanced. The charge on the left side is 1+ (from Na+) and the charge on the right side is 0 (from Na). To balance the charges, we need to add a coefficient of 2 in front of Na+: 2Na+(aq).
So, the balanced oxidation-reduction reaction is: Fe(s) + 2Na+(aq) → 2Fe2+(aq) + Na(s).
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(2) compound because the atoms of the elements are combined in a proportion that varies
(3) mixture because the atoms of the elements are combined in a fixed proportion
(4) mixture because the atoms of the elements are combined in a proportion that varies
Answers
Reason:
A chemical compound is a chemical substance composed of element (of same or different type) that are bonded in a fixed proportion. Depending upon the type of element, bond can be ionic or covalent. In present case, tetrachloromethane i.e. CCl4 has one 'C' atom that is covalently bonded to four 'Cl' atoms.