Ice does not need to melt into liquid water before it can return to the atmosphere as water vapor.Please select the best answer from the choices provided
T
F

Answers

Answer 1
Answer:

Answer: The given statement is true.

Explanation:

When solid state of water changes directly into vapor state then this process is known as sublimation.

For example, when dry ice is placed at room temperature then it converts into vapor state without undergoing liquid state.

Also when we apply very high pressure or temperature at the solid state of water, it will change directly into vapor state.

Therefore, the statement ice does not need to melt into liquid water before it can return to the atmosphere as water vapor is true.

Answer 2
Answer: True! 
Because if it has a high pressure, it can skip the liquid phase. The process is called sublimation

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Answer: D

Explanation:

Answer: High temperatures and location in high latitudes

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Is T2R an Atom or a Molecule?​

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Answer:

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What is the IUPAC name for the compound FeS?(1) iron(II) sulfate (3) iron(II) sulfide
(2) iron(III) sulfate (4) iron(III) sulfide

Answers

The correct answer is option 3. The IUPAC name is Iron(II) sulfide. It is the less stable amorphous form.  When this is powdered, it is pyrophoric or it ignites spontaneously in air. It readily reacts with hydrochloric acid producing hydrogen sulfide.

The IUPAC name for the compound FeS is "iron(II) sulfide." Therefore, option 3 is correct.

The IUPAC (International Union of Pure and Applied Chemistry) name is a systematic way of naming chemical compounds.

The compound FeS consists of iron (Fe) and sulfur (S) atoms. In FeS, iron has a +2 oxidation state, and sulfur has a -2 oxidation state.

According to the IUPAC nomenclature rules for naming inorganic compounds, the cation (iron) is named first, followed by the anion (sulfide).

To indicate the oxidation state of iron, the Roman numeral II is used in parentheses after the name "iron." The resulting name is "iron(II) sulfide."

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One hundred students were surveyed about who they would vote for. What isthe best way to display the results? Explain your answer.

Answers

Hey hope this helps ⬇️

Which nuclear decay emission consists of energy, only?(1) alpha particle (3) gamma radiation
(2) beta particle (4) positron

Answers

Answer:  (3) gamma radiation

Explanation:

An isotope can decay in 4 process:

1.) Alpha decay: In this process, alpha particles is emitted when a heavier nuclei decays into lighter nuclei. The alpha particle released has a charge of +2 units.

_Z^A\textrm{X}\rightarrow _(Z-2)^(A-4)+_2^4\alpha

2.)Beta-decay: In this process, a neutron gets converted into a proton and an electron releasing a beta-particle. The beta particle released carries a charge of -1 units.

_Z^A\textrm{X}\rightarrow _(Z+1)^A\textrm{Y}+_(-1)^0\beta

3.) Gamma ray emission: in this process, an unstable nuclei gives off excess energy by a spontaneous electromagnetic process and releases \gamma -radiations. These radiations does not carry any charge and are electrically neutral.

_Z^A\textrm{X}^*\rightarrow _Z^A\textrm{X}+_0^0\gamma

4.) Positron decay: In this process, a proton gets converted to neutron and an electron neutrino and releases positron particles. This particle carries a charge of +1 units.

_Z^A\textrm{X}\rightarrow _(Z-1)^A\textrm{Y}+_(+1)^0e

In the question, it is given that when an isotope decays, it emits only energy. It is released when an isotope undergoes gamma decay and therefore, the correct answer is gamma radiation.

(3) gamma radiationIt is Electromagnetic energy only

Which step would help a student find the molecular formula of a compound from the empirical formula?

Answers

First, you need to be given the gram formula mass of this molecular or related conditions that can calculate this. Then you need the empirical formula and calculate the gram formula mass of empirical formula. Then use them to get the ratio. Finally you can get the molecular formula.

Final answer:

To find the molecular formula from the empirical formula, first calculate the empirical formula mass. Then, divide the molecular or molar mass by the empirical formula mass to find the number of empirical formula units per molecule. Finally, multiply the subscript of each element in the empirical formula by this number to get the molecular formula.

Explanation:

The process of finding the molecular formula from the empirical formula involves a few steps. First, you need to determine the empirical formula of a compound, which is the simplest positive integer ratio of atoms present in a compound. After you have the empirical formula, you can calculate the empirical formula mass by summing up the average atomic masses of all the atoms in the empirical formula.

Next, compare the compound's molecular or molar mass (which you should know or have been given) to the empirical formula mass. This comparison is done by dividing the molecular or molar mass by the empirical formula mass. This will give you the number of empirical formula units, denoted as n, per molecule of the compound.

The final step is to take the empirical formula and multiply the subscript of each element in it by n. This will give you the molecular formula of the compound.

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