Write this mixed number 6 4/7 as an improper faction in simplest form

Answers

Answer 1
Answer: it is 46/7     you could multiply 6x7 and then add 4 =   46/7
Answer 2
Answer: 46/7. You do 7 times 6 and get 42. 42+4 is 46.
So 46/7 is the answer.
~JZ

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Use factoring. What is the solution of 2x² = 14x + 60? a. x = -15, x = 4 b. x = -10, x = 3 c. x = 15, x = 12 d. x = 10, x = -3
Evaluate 4a-bc if a=7 b=3 c= -2

Need help on this!!! 7 points!!!

Answers

Answer:

P= $226,863.29

Step-by-step explanation:

Compounded Continously means

P= P₀e^(rt)

plug in givens

P=(47000)e^(0.0926*17)

Use Calculator

and get P= $226,863.29

Answer:

$226,863.29

Step-by-step explanation:

P = $47,000

r = 0.0926

t = 17

A = 47,000(2.718)^((0.0926)(17))

A = $226,863.29

Y varies directly with X. if y = y when X= -4, find the constant of of proportionality

Answers

y = kx
6=k(-4)
6/-4 = k
-3/2 = k

Find all values of m so that the function y = e^mx
is a solution of the given differential equation. y' + 9y = 0

Answers

Hello,

y=e^(mx)
y'=m*e^(mx)

0=y'+9y=m*e^(mx)+9*e^(mx)
==> e^(mx)*(m+9)=0
This must be exact for every  value of ,so
m=-9



Its 10 3/5 miles from Alston to Barton and 12 1/2 miles from Barton to Chester. The distance from Alston to Durbin, via barton and Chester, is 35 miles how far is it from Chester to durbin

Answers

Answer:

It is  11(9)/(10)  miles far from Chester to Durbin.

Step-by-step explanation:

Given:

Its 10 3/5 miles from Alston to Barton and 12 1/2 miles from Barton to Chester. The distance from Alston to Durbin, via barton and Chester, is 35 miles.

Now, to find the distance from Chester to durbin.

Distance from Alston to Barton = 10(3)/(5) =(53)/(5) \ miles.

Distance from Barton to Chester = 12(1)/(2)\ miles =(25)/(2) \ miles.

As, given the distance from Alston to Durbin, via barton and Chester, is 35 miles.

Thus, the total distance = 35 miles.

So, we add the distance of Alston to Barton and Barton to Chester and get the distance from Alston to Chester:

(53)/(5) +(25)/(2)

=(106+125)/(10)

=(231)/(10) \ miles.

Distance from Alston to Chester  =(231)/(10) \ miles.

Now, to get the distance from Chester to durbin we subtract distance from Alston to Chester from the total distance:

35-(231)/(10) \n\n=(350-231)/(10) \n\n=(119)/(10) \n\n=11(9)/(10)\ miles.

Therefore, it is  11(9)/(10)  miles far from Chester to Durbin.

I need help with this

Answers

the answer for #2 is B it might be wrong

Both A and D are correct answers. In A the factor is 3 while in D the factor is 9.

The speed of a ship is given by d3, where d is the distance the ship travels in 3 hours. if the ship travels 48 miles in 3 hours, what is the speed of the ship?

Answers

Hello there! Thank you for asking your question here at Brainly! I will be assisting you today with answering this problem, and will teach you how to handle it on your own in the future.

First, let's take a look at our problem.
"The speed of a ship is given by D3, where D is the distance the ship travels in 3 hours. If the ship travels 48 miles in 3 hours, what is the speed of the ship?"

To solve for this, we need to understand the formula for speed.
The formula for speed is:
Speed = (Distance)/(Time)

Now that we have our formula, let's define our variables.

So, we have our distance, 48 miles, and our time, 3 hours.
Let's plug in these numbers to the formula.
Speed = (48)/(3)

Simplify the fraction to get the speed.
(48)/(3) = 16.

Your final equation is:
Speed = 16.

Our final answer is 16 mph.

I hope this helps!

Answer:

the answer is 16mph

Step-by-step explanation: