(B) centrifuging the solution
(C) osmosis of the solution
(D) electrolysis of the solution
(E) filtration of the solution
B) KBr
C) CH3CH2OH
D) HCl
E) C6H6
How is this determined?
The percentage of nitrogen in nitrous oxide or N₂O is 63.64% and percent of oxygen is 36.36 %.
It is the percent of each element which exists in a compound. It is calculated in three methods:
1) percent w/w
2) percent v/v
3) percent w/v
Percent w/w is the percent composition wherein both the components are solids.Percent v/v is percent composition wherein the 2 substances are liquid and percent w/v is percent composition where one substance is solid and one is in liquid form.
The percent composition of all substances is equal to 100%.The percent composition of nitrogen in nitrous oxide is calculated as follows:
molar mass of nitrous oxide=44 g
molar mass of nitrogen =14 g
As nitrous oxide has 2 nitrogen ,therefore 14×2=28
To find percent composition,
molar mass of nitrogen in nitrous oxide/molar mass of nitrous oxide×100
∴28/44×100=63.64%
Thus, percent of nitrogen in N₂O is 63.64%.
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Answer:
63.64% Nitrogen
36.36 Oxygen
B. liquids.
C. solids.
D. fluids.
E. none of the above
Convection is the transfer of heat in a fluid (which can be a liquid or gas) through the movement of its particles. A fluid near a heat source will get heated, causing it to rise and exchange place with the cooler, denser fluid.
Energy transfer by convection is primarily restricted to both liquids and gases, which are both classified as fluids. Hence, the correct answer is D. Fluids.
Convection refers to heat transfer in a gas or liquid by the circulation of currents from one region to another. This happens when a fluid near a heat source gets heated, its particles move faster and spread apart, causing the fluid to become less dense. As a result, the warmer, less dense fluid rises, and the cooler, denser fluid sinks. The continuous movement of fluid in this way creates what we call a convection current, which results in the transfer of energy.
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b. False
this is a true statement
When 3.0 moles of hydrogen peroxide decompose at 1.0 atm and 23°C, approximately 36.78 liters of oxygen gas are produced according to the ideal gas law.
To find the volume of oxygen gas produced when 3.0 moles of hydrogen peroxide decompose at a pressure of 1.0 atm and a temperature of 23°C, you can use the ideal gas law:
PV = nRT
Where:
- P is the pressure (1.0 atm).
- V is the volume (what we want to find).
- n is the number of moles of gas (1.5 moles of O2 since 1 mole of O2 is produced for every 2 moles of H2O2).
- R is the ideal gas constant (approximately 0.0821 L.atm/mol.K).
- T is the temperature in Kelvin (23°C needs to be converted to Kelvin, which is 296.15 K).
First, calculate the number of moles of O2 produced:
n = 3.0 moles of H2O2 * (1 mole of O2 / 2 moles of H2O2) = 1.5 moles of O2
Now, plug in the values into the ideal gas law and solve for V:
1.0 atm * V = 1.5 moles * 0.0821 L·atm/mol·K * 296.15 K
Now, calculate the volume:
V = (1.5 moles * 0.0821 L·atm/mol·K * 296.15 K) / 1.0 atm
Calculate the volume:
V ≈ 36.78 L
So, the volume of oxygen gas produced when 3.0 moles of hydrogen peroxide decompose at 1.0 atm and 23°C is approximately 36.78 liters.
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