Malina has to bowl four games in her league. She bowled a 149, 162, and a 152 in her first three games. She wants to have an average score of 154. What score does she need in her fourth game?a.152

b.153

c.154

d.155

Answers

Answer 1
Answer:

Answer: Option 'B' is correct.

Step-by-step explanation:

Since we have given that

Number of games she bowl = 4

Score of her in first three games are

149, 162, 152.

Her average score = 154

Let the score in her fourth game be 'x'.

As we know the formula for "Average ":

Average=\frac{\text{Sum of all observation}}{\text{Total number of observations}}\n\n\n154=(149+162+152+x)/(4)\n\n\n154* 4=463+x\n\n\n616=463=x\n\n\n616-463=x\n\n\n153=x

Hence, Her score in fourth game is 153.

Therefore, Option 'B' is correct.

Answer 2
Answer: (149+162+152+X)/4=154
149+162+152+X=616
X=616-149-162-152=616-314-149=302-149=153
She needs a score of 153.

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Answers


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Answers

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Answers

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Answers

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Step-by-step explanation:

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Answers

The greatestcommonfactor of 18 and 35 is 1.

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An expression contains one or more terms with addition, subtraction, multiplication, and division.

We always combine the liketerms in an expression when we simplify.

We also keep all the like terms on one side of the expression if we are dealing with two sides of an expression.

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1 + 3x + 4y = 7 is an expression.

3 + 4 is an expression.

2 x 4 + 6 x 7 – 9 is an expression.

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We have,

The greatestcommonfactor of 18 and 35.

Now,

See all the factors of 18.

= 1, 2, 3, 6,  9, and 18.

See all the factors of 35.
= 1, 5, 7, and 35.

We see that,

The greatestcommonfactor is 1.

Thus,

The greatestcommonfactor of 18 and 35 is 1.

Learn more about expressions here:

brainly.com/question/3118662

#SPJ5

We found the factors and prime factorization of 18 and 35. The biggest common factor number is the GCF number. So the greatest common factor 18 and 35 is 1.