Please Help! I've been waiting for a while!!How many solutions does the equation have?
5x + 3 = 2(x + 3) - 3(2 - 2x)

Answers

Answer 1

Answer: first distribute
a(b+c)=ab+ac so
2(x+3)=2x+6
-3(2-2x)=-6+6x
5x+3=2x+6-6+6x
add like terms
5x+3=2x+6x+6-6
5x+3=8x+0
subtract 5x from both sides
3=3x
divide both sides by 3
1=x

there are 1 solutions

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Fill in the blank to make the expression a perfect square.
v^2 - 18v + ?

Answers

Answer: (v - 9)^2 - 81

Step-by-step explanation: Use the formula (b/2)^2 in order to create a new term to complete the square.

Hope this helps! :) ~Zane

The radical form plz someone help

Answers

Answer:

it cannot be converted to radical form

Step-by-step explanation:

Brandon found that a solution of x = 1 was extraneous for his function. What would be a possible denominator in Brandon's function?2x + 4

x2 + 3x + 9

3x - 11

x2 + 3x - 4

Answers

An extraneous solution is obtained when the simplified version of the function drives to a value thas does not belong to the domain of the complete function.

So, if x = 1 is an extraneous solution, it does not belong to the original domain.

if when you replace x = 1 in the expression of the denominator it results in 0, then it is an extraneous solution, because you cannot accept it as a valid solution.

Then we must check which of the expressions listed in the options drive to that possibility.

The promising choice is x^2 + 3x - 4.

Inded, If you substitute x = 1, you get (1)2 + 3(1) - 4 = 1 + 3 - 4 = 4 - 4 = 0.

And the answer is x^2 + 3x - 4.

Answer:

x^2+3x-4

Step-by-step explanation:

What is the domain of the function f (x) x-5/x^2-9

Answers

means the number you can use
remember we can't divide by zero
domain is x^2-9
set to zero to find values we can't use
x^2-9=0
x^2=9
x=+/-3

domain=all real numbers except -3 and 3

On a coordinate plane, 3 lines are shown. Line a has points (negative 3, 3) and (3, negative 3). Line b has points (negative 3, negative 2) and (2, 3). Line c is parallel to line b. If line b is perpendicular to line a, and line c is perpendicular to line a, what is the slope of line c? mc =

Answers

Answer:

The slope of line c is 1

Step-by-step explanation:

The given information are;

The coordinates of the points on the line a are; (-3, 3) and (3, -3)

The coordinates of the points on the line b are; (-3, -2) and (2, 3)

Line c ║ line b

Line b ⊥ line a

Line c ⊥ line a

Therefore, we have

The slope, $m_c$ of line c is equal to the slope, $m_b$ , of line b Definition of parallel lines (The slopes of parallel lines are equal)

$m_c$ = $m_b$

Therefore, the slope, m, of the line b is given as follows;

$Slope, \, m =(y_(2)-y_(1))/(x_(2)-x_(1))$

Where, for line b, (x₁, y₁) = (-3, -2) and (x₂, y₂) = (2, 3), we have;

$Slope, \, m_b =(3-(-2))/(2-(-3)) = (3 + 2)/(2 + 3) = 1$

From $m_c$ = $m_b$ = 1, the slope of line c = 1.

Since line b is perpendicular to line a, and line c is perpendicular to line a, the slope of line c is equal to 1.

How to determine the slope of a line?

In Mathematics and Geometry, the slope of any straight line can be determined by using the following mathematical equation;

Slope (m) = (Change in y-axis, Δy)/(Change in x-axis, Δx)

Slope (m) = (y₂ - y₁)/(x₂ - x₁)

Based on the information provided above, we can logically deduce the following;

Line c parallel line b
Line b is perpendicular line a.
Line c is perpendicular line a.

Therefore, the slope of line "c" can be calculated as follows;

Slope (m) = (3 - (-2))/(2 - (-3))

Slope (m) = (3 + 2)/(2 + 3)

Slope (m) = 5/5

Slope (m) = 1

Read more on slope here: brainly.com/question/28143558

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The area, A, of a square is equivalent to the square of its side lengths. choose more than one!1::: A = (6)(6) square units
2::: A = s2 square units
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4::: A = (x+x) square units
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