3x+4y=17 solve for y.

Answers

Answer 1

Answer: $3x+4y=17\ \ \ /-3x\n\n4y=17-3x\ \ \ \ /:4\n\ny=(17-3x)/(4)\n\ny=4.25-0.75x$

Answer 2

Answer: Isolate "y":

$3x+4y=17\n \n 4y=17-3x\n \n \boxed{y=(17-3x)/(4)}$

Related Questions

Find the quotient of 5/31 divided by 15/23. Reduce your answer to the lowest fraction
What is the value of x when 3x=54? A) x=18B) x=51C) x=57D) x=162
I need help really bad I'm gonna give 25 points who helps me
1) which expression is the GCF of the terms of the polynomial?16x^3+28^5y A)4x^3 B)4x^5y C)8x^5 D)112x^5y
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What is the distance between 12 7 and 3 7 !

Answers

Answer:

The answer is 15 units is the answer boom

Step-by-step explanation:

Answer:

Step-by-step explanation:

What are the domain and range of the relation {(–5, 5), (–3, 2), (0, 3), (3, 2)}?

Answers

domain is th set of number you input
range is the set of number you get from inputing the domain
normally domain is x and range is y
(x,y)

domain is all 1st number
range is all 2nd numbers

doman={-5,-3,0,3}
range={5,2,3} (if it repeats, don't list)

Multiply the Polynomial
(5a-b)(5a+8b)

Explain.

Answers

$(5a-b)(5a+8b)=(5a*5a)+(5a*8b)+(-b*5a)+(-b*8b)=$ $25a^2+40ab-5ab-8b^2=25a^2+25ab-8b^2$

(5a - b)(5a + 8b)
5a(5a + 8b) - b(5a + 8b)
5a(5a) + 5a(8b) - b(5a) - b(8b)
25a² + 40ab - 5ab - 8b²
25a² + 35ab - 8b²

PLEASE SOMEONE HELP ME!!!!!!!!

Answers

Answer:

The slope is -4

Step-by-step explanation:

To find the slope in this equation you first need to find the difference of y.

2 + (-4) = -2

-2 + (-4) = -6

so the difference of y is -4

Then you find the difference of x

0 + 1 = 1

1 + 1 = 2

So, the difference of x is 1

slope is rise over run (rise meaning the y-axis and run meaning the x-axis)

so the slope is -4/1

Identify whether these series are divergent or convergent geometric series and find the sum, if possible.

Answers

A geometric series:
$\sum^(\infty)_(i=1)=a_1 * r^(i-1)$
It's convergent if |r|<1.
It's divergent if |r|≥1.
The sum can be found if it's a convergent series; it's equal to $(a_1)/(1-r)$ .

3.
$\sum^(\infty)_(i=1) 12 ((3)/(5))^(i-1) \n \na_1=12 \nr=(3)/(5) \n \n|r|<1 \hbox{ so it's convergent} \n \n\sum^(\infty)_(i=1) 12 ((3)/(5))^(i-1)=(12)/(1-(3)/(5))=(12)/((5)/(5)-(3)/(5))=(12)/((2)/(5))=12 * (5)/(2)=6 * 5=30$

The answer is: This is a convergent geometric series. The sum is 30.

4.
$\sum^(\infty)_(i=1) 15(4)^(i-1) \n \n a_1=15 \n r=4 \n \n |r| \geq 1 \hbox{ so it's divergent}$

The answer is: This is a divergent geometric series. The sum cannot be found.

20% of my money is £2.55
What is 2/5 of it?

Answers

20% = 2.55
2/5 = 40% (2 ÷ 5 = 0.40) so 2.55 × 2 = 5.10
Happy to Help!

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