A whole pie is divided into twelve equal pieces.at what angle is each pie cut?

Answers

Answer 1

Answer: $A\ whole\ pie\ is\ 360^o\n\nAn\ angle\ each\ pie\ cut\ is\ 360^o:12=30^o$

Answer 2

Answer: It's simple. If there are 360 degrees in a circle, and you're dividing that into 12 pieces, just divide 360 by 12 and get 30 degrees

Related Questions

Find two rational numbers between -1 and 0
Which graph correctly solves the system of equations below?y = 2x2 − 3 y = −x2 one quadratic graph opening down and one quadratic graph opening up. They intersect at 1, negative 1 and negative 1, negative 1. one quadratic graph opening up and one quadratic graph opening down. They intersect at 0, negative 3. two quadratic graphs opening up. They intersect at 0, negative 3. quadratic graph opening up and quadratic graph opening down. They intersect at 1, 2 and negative 1, 2
Add these mixed numbers 4 4/7+3 2/7
A healthy human heart beats about 1,533,000 times in a year. A sparrow's heart beats about 241,776,000 times in a year. About how many times faster does the sparrow's heart beat compared to the human heart? Estimate using a single digit times a power of 10.
What does p equal in this equation and how: -p-7p=6(-2p+10)-(12-2p)

Rewrite the fraction in simplest form.
24/36

Answers

24:2 = 12, 12:2 = 6, 6:3= 2
36:2 = 18, 18:2 = 9, 9:3= 3
So the answer is 2/3
make sure you divide the top and bottom number with the same number :D

X and y intercepts of -3x+4y=-36

Answers

X intercept is 12
Y intercept is 9.
To find answer just cover up the one you don't want.
For x it would be -3x=-36
For y it would be 4y=-36

The movie theatre has 250 seats. 225 seats were sold for the current showing . What percent of the seats are empty?

Answers

all you do is divide like this 225/250=0.9 and 0.9 is 90% so your answer is 90% hope i am the brainliest i need it to move up to the next rank

250-225=25 seats empty. Place what you want/total=(25/250)x100=0.1x100=10% of the seats are empty.

Two cars leave Denver at the same time and travel in opposite directions. One car travels 10 mi/h faster than the other car. The cars are 500 mi apart in 5 h. How fast is each car traveling?

Answers

The speed of one car is 'S'. The speed of the other car is (S + 10).

In 5 hours, the first car travels (5S) miles, and the other car travels 5(S + 10) miles.

Since they're going in opposite directions, the distance between them at any time
is the sum of the distance that each one has traveled.

500 = (5S) + 5(S + 10)

500 = 5S + 5S + 50

500 = 10S + 50

Subtract 50 from each side:

450 = 10S

Divide each side by 10

S = 45

S + 10 = 55

Let one car travel at x mph

The other car travels at x+10 mph

Their combined speed is 2x+10 mph.

Distance = 500

time = 500 /2x+10 =5

10x+50=500

10x= 450

x=45 speed of one car

The other car travels at 45+10 = 55 mph

During cooking, chicken loses 10% of its weight due to water loss. In order to obtain 1,170 grams of cooked chicken, how many grams of uncooked chicken must be used?

Answers

Answer:

117 grams

Step-by-step explanation:

So this is a oddly phrased question but I believe I understand it. You need to find 10 percent of 1170 grams and that it 117. And for you information I did use calculator to prevent error so don't worry about that.

Cory has 15 die-cast cars in his collection. Each year his collection increases by 20%. Roger has 40 cars in his collection. Each year he collects 1 additional car.Part A: Write functions to represent Cory and Roger's collections throughout the years.
Part B: How many cars does Cory have after 6 years? How many does Roger have after the same number of years?
Part C: After approximately how many years is the number of cars that Cory and Roger have the same? Justify your answer mathematically.

Answers

Part A:
For Roger: $y=x+40$
For Cory: $y=15 (1.2)^(x)$
where y is the total number of cars each boy collects over the year, x as the number of years passed.

Part B:
For Roger: 46
For Cory: 44.79~ 45 cars

Part C:
Here, we are trying to find the number of years (x) where Cory and Roger have the same number of cars.
By equating Roger and Cory's functions, we can solve for x
$x+40=15 (1.2)^(x)$ .
Since we cannot solve the value of x directly, we use trial and error to estimate the year.
When x=1
$41 \neq 18 \n$
When x=2
$42 \neq 21.6$
When x=3
$43 \neq 25.92$
When x=4
$44 \neq 31.10$
When x=5
45=/=37.3
When x=6
46=/=44.8
When x=7
47=/=53.7

The years that pass by before Cory and Roger have nearly the same number of cars is 6.

Answer:

Step-by-step explanation:

Part A:

For Roger:

For Cory:

where y is the total number of cars each boy collects over the year, x as the number of years passed.

Part B:

For Roger: 46

For Cory: 44.79~ 45 cars

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