The charges on two metallic balls are 5.0 and 7.0 coulombs respectively. They are kept 1.2 meters apart. What is the force of interaction between the two?

Answers

Answer 1
Answer:

Answer: the correct answer is 8*10^-11


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An acorn with a mass of 0.0300 kilograms falls from a tree. What is its kinetic energy when it reaches a velocity of 5.00 m/s?
Which of the following best describes “the ability to do work”?a. forceb. massc. energyd. volume
Heterotrophs convert solar energy into chemical energy.a. Trueb. False
When starting a heavy train, why will train engineers sometimes back up, stop, and then proceed forward? (This technique is called "bunching slack.")

Statistics used to analyze sample data in order to make conclusions about a population are called __________ statistics.A.
nondirectional
B.
directional
C.
inferential
D.
descriptive

Answers

Option C. inferential statistics

Trying to reach conclusions that extend beyond immediate data alone. This is used also in making judgments of the probability that an observed difference between groups is a dependable one. Therefore, using this is to arrive an inferences from our data in a more general conditions.

the answer is c its the only one that seems right

Which change decreases the resistance of a pieceof copper wire?
(1) increasing the wire’s length
(2) increasing the wire’s resistivity
(3) decreasing the wire’s temperature
(4) decreasing the wire’s diameter

Answers

Explanation :

We know that the resistance of the wire is given by :

R=\rho (l)/(A)

Where

\rho is the resistivity

l is the length of the wire

A is the area of the wire.

Another factor on which the resistance of wire depends is temperature. It is given by :

R=R_(ref)[1+\alpha (T-T_(ref))]

So, it is clear that the resistance of the wire is directly proportional to the temperature. It we want to decrease the resistance of the piece, its temperature should be decreased.

So, the correct option is (3) " decreasing the wire’s temperature ".

Decreasing the wire’s temperature decreases the resistance of a piece of copper wire.

What is resistance?

Resistance is a type of opposition force due to which the flow of current is reduced in the material or wire. Resistance is the enemy of the flow of current.

The relation of resistance with length and thickness is given by ;

\rm R= (\rho L)/(A)

The value of resistance is directly propotional to length and inversly propotional to the area or thickness of the wire.

As the value of temperature increases, the value of resistance in the material is increasing. Length, temperature, and thickness are the factors that affect the resistance of a material.

Resistance of the wire is directly propotional to the temperature. On decreasing the temperature the resistance of the wire is also decreasing.

Hence decreasing the wire’s temperature decreases the resistance of a piece of copper wire.

To learn more about the resistance refer to the link;

brainly.com/question/20708652

In 1911, Ernest Rutherford and his assistants Geiger and Marsden conducted an experiment in which they scattered alpha particles (nuclei of helium atoms) from thin sheets of gold. An alpha particle, having charge 2e and mass 6.64 10-27 kg, is a product of certain radioactive decays. The results of the experiment led Rutherford to the idea that most of an atom's mass is in a very small nucleus, with electrons in orbit around it. Assume an alpha particle, initially very far from a stationary gold nucleus, is fired with a velocity of 1.50 107 m/s directly toward the nucleus (charge 79e). What is the smallest distance between the alpha particle and the nucleus before the alpha particle reverses direction?

Answers

Answer:

Explanation:

We shall apply conservation of mechanical energy

kinetic energy of alpha particle is converted into electric potential energy.

1/2 mv² = k q₁q₂/d , d is closest distance

d = 2kq₁q₂ / mv²

= 2 x 9 x 10⁹ x 79e x 2e / 4mv²

= 1422 x2x (1.6 x 10⁻¹⁹)² x 10⁹ /4x 1.67 x 10⁻²⁷ x (1.5 x 10⁷)²

= 3640.32 x 10⁻²⁹ /2x 3.7575 x 10⁻¹³

= 484.4 x 10⁻¹⁶

=48.4  x 10⁻¹⁵ m

A cat is being chased by a dog. Both are running in a straight line at constant speeds. The cat has a head start of 3.8 m. The dog is running with a speed of 8.9 m/s and catches the cat after 6.0 s. How fast did the cat run?

Answers

In 6 secs, the dog covers-
S=vt
8.9*6 = 53.4 m.
In the same time, the cat covers, 53.4-3.8 = 49.6 m.
Thus, speed of the cat, v= s/t, 
= 49.6/6 = 8.267 m/s

What are the primary differences between stars and planets

Answers

Stars don't have moons and planets do
stars aren't big enough to emit enough kight and heat meaning they cant cause nuclear reactions

If 2.0 x 10^-4 C charge passes a point in 5.0 x 10^-5 s, what is the rate of current flow?4.0 x 10^-1 A
1.0 x 10^2 A
1.0 x 10^-10 A
4.0 x 10^0 A

Answers

Current is defined as the rate of charge flowing a point every second. Having a current of 1 Ampere signifies 1 Coulomb is flowing in a circuit every second. It is measured by the use of an ammeter which is positioned in series to the component to be measured. The current in the problem is calculated as follows:

I = 2.0 x 10^-4 C / 5.0 x 10^-5 s
I = 4 A or 4.0 x 10^0 A

Answer:

Current is defined as the rate of charge flowing a point every second. Having a current of 1 Ampere signifies 1 Coulomb is flowing in a circuit every second. It is measured by the use of an ammeter which is positioned in series to the component to be measured. The current in the problem is calculated as follows:

Explanation: