If an object has a mass of 50 kg and is accelerating at 2m/s/s, what is the force it will exert?

Answers

Answer 1
Answer: the formula you're looking for is Force = mass * acceleration. this means the force = 50 * 2, which is 100N

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According to this equation, F=ma, how much force is needed to accelerate an 82-kg runner at 7.5m/s2?A.
615 N

B.
10.9 N

C.
615 m/s

D.
10.9 m/s

Answers

You multiply the mass by the acceleration 82*7.5=615; that's what I would do
c is the  answer for it

WHAT IS THE IMPORTANCE OF THE TROPIC OF CANCER AND TROPIC OF CAPRICORN

Answers

The tropic of cancer and tropic of capricorn has inportance in geographical studies. They help to divide the oceans. They help to classify different countries ( as lying in and around of either of the zones). On classifying, we can also predict weather or atmospheric pressure over the country ( with respect to tropic of cancer or tropic of capricorn). Thus, it has important role in geography. 
they help the divide the world and describe the difference in weather patterns

A 2.0 kg guinea pig runs at a speed of 1.0 m/s what is the guinea pigs kinetic energy

Answers

The kinetic energy (KE) is calculated using the formula KE = 1/2 * m * v^2, resulting in a kinetic energy of 1.0 Joule for a 2.0 kg guinea pig moving at a speed of 1.0 m/s.

The kinetic energy (KE) of an object in motion is determined by the formula: KE = 1/2 * m * v^2, where m is the mass and v is the velocity. For the guinea pig in question, with a mass (m) of 2.0 kg and a velocity (v) of 1.0 m/s, the calculation is as follows:

KE = 1/2 * 2.0 kg * (1.0 m/s)^2

KE = 1/2 * 2.0 kg * 1.0 m^2/s^2

KE = 1.0 kg * 1.0 m^2/s^2

KE = 1.0 Joule

Therefore, the kinetic energy of the 2.0 kg guinea pig running at a speed of 1.0 m/s is 1.0 Joule.

The kinetic energy for the above data is 1.0000 J.

What is a bright, star like object in the galaxy core

Answers

the sun is a bright star 
sun   idk :00000000000000000

The density of mercury is 13.5 g/cm3g
/
c
m
3
.
Part A
Part complete
What is this value in kilograms per cubic meter?
1.35×104
kg/m3
k
g
/
m
3

Answers

If the density of mercury is 13.5 g/cm³ in the gram per centimeter cube unit, then the density of the mercury would be 1.35×10⁴ in the kilograms per cubic meter

What is density?

It can be defined as the mass of any object or body per unit volume of the particular object or body. Generally, it is expressed as in gram per cm³ or kilogram per meter³.

By using the above formula for density

ρ = mass / volume

As given in the problem If the density of mercury is 13.5 g/cm³ in the gram per centimeter cube unit then we have to convert its value into kilograms per cubic meter.

1000 grams  = 1 kilogram

1 gram = 1/1000 kilograms

           =1×10⁻³ kilograms

10⁶ cubic centimeter = 1 cubic meter

1  cubic centimeter = 1/10⁶  cubic meter

                                = 1× 10⁻⁶ cubic meter

Given the density of the mercury  13.5 g/cm³

13.5 g/cm³ =  13.5 ×10⁻³ kilograms / 1× 10⁻⁶ cubic meter

                   = 1.35×10⁴ kilograms / cubic meter

Thus, we converted the density of mercury is 13.5 g/cm³ into 1.35×10⁴ kilograms / cubic meter

To learn more about density from here, refer to the link;

brainly.com/question/15164682

#SPJ2

Answer:

DO IY.T

Explanation:

A flashlight has a resistance of 30 Q and is connectedby a wire to a 90 V source of voltage. What is the
current in the flashlight?

Answers

Answer:

3 A

Explanation:

The relationship between voltage, current and resistance in a conductor is expressed by Ohm's law, which states that:

V=RI

where:

V is the potential difference across the conductor

R is the resistance of the conductor

I is the current flowing through it

In this problem, for this flashlight we have:

V = 90 V is the potential difference

R=30 \Omega is the resistance of the flashlight

Solving for I, we find the current:

I=(V)/(R)=(90)/(30)=3 A