In which range is the peak wavelength of a star that is much hotter than the Sun most likely to be? A) radio waves B) infrared radiation C) microwaves D) ultraviolet light

Answers

Answer 1
Answer:

The range in which the peak wavelength of a star that is much hotter than the Sun most likely to be ultraviolet light. Therefore, option (D) is correct.

What is peak wavelength of star?

The peak wavelength is the wavelength at which a radiation source emits the most energy or has the highest intensity. It is related to the temperature of the source through Wien's law, as hotter sources emit shorter wavelengths of radiation.

The peak wavelength of a star is related to its temperature through Wien's law. Wien's law states that the wavelength of the peak intensity of a blackbody radiation curve is inversely proportional to its temperature. Therefore, hotter stars have shorter peak wavelengths than cooler stars. Since ultraviolet light has shorter wavelengths than visible light, stars that are much hotter than the Sun would have their peak wavelength in the ultraviolet range. Thus, the correct option is D) ultraviolet light.

Learn more about stars, here:

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Answer 2
Answer:

Answer:

the correct answer is option D

Explanation:


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Please help me with this question:)

Which one is NOT a secondary consumerA.
herbivore
B.
lion
C.
carnivore
D.
ominvore

Answers

Answer:a

Explanation:

Answer:

a. herbivore i think

Explanation:

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Rocks that are formed from sediment that has been compressed over time and becomes solid are called ______________ rocks *1 point
igneous
metamorphic
sedimentary
Plzzzzzz help ME NEED IT BY TODAYYY

Answers

Answer:

Metamorphic, :b

Explanation:

Lol, hope this helps ;B

You have been reading for a while and want to rest your eyes and listen to the next section of your chapter. You have finish reading the assignment for the next quiz but want some extra review with flashbacks. You begin reading your E texts with blank letters against a white background but want to try changing the color mode to sepia instead. You have highlighted importing content, and added notes as you read.Now you want to compile and export these notes as a pdf study reference. You’ve highlighted important terms and ideas in your e text . Now you want to hide your highlights as you review for an exam.

Answers

To rest my eyes and listen to the next section of my chapter, I'll consider using text-to-speech functionality. After finishing the assignment for the next quiz, I'll review it with flashbacks to reinforce my understanding. Changing the color mode to sepia can be a soothing option for reading.

For compiling and exporting notes as a PDF study reference, I'd typically use note-taking or document management software. I'd also look for options to export highlights separately.

To hide the highlights during exam review, I'd check if there's a way to turn off the highlight display in my e-text software temporarily. If not, I may consider making a copy of the text without highlights for focused study.

Is there anything specific you'd like to know or discuss further about this?

Two species have homologous structures. What do these homologous structures show about the evolutionary relationship between the two species?

Answers

Two species have homologous structures. What do these homologous structures show about the evolutionary relationship between the two species? (3 points) The homologous structures show that the two species followed up the evolutionarypath up to the structure. They may have branched off right after that trait.

Final answer:

Homologous structures in two species indicate that they share a common ancestor. These structures, although they may serve different functions in adult organisms, have a similar form and the same embryonic origin. They provide key evidence for evolution and development of various species from common ancestors.

Explanation:

The presence of homologous structures in two different species often demonstrates an evolutionary relationship, indicating they share common ancestry. Homologous structures are those that have a similar form or function and share a similar embryonic origin, although they may appear different and perform different functions in the adult organisms. An example of this could be the bone structure in a human arm, cat leg, whale flipper, and bat wing which, despite serving different purposes, all have a similar arrangement of bones.

The presence of such structures suggests that these species have evolved from a common ancestor that had this structure. Over time, as the species evolved and adapted to their specific environments or lifestyles, these structures may have developed different functions. Therefore, homologous structures are key evidence for the theory of evolution and help in developing phylogenetic relationships. They help us understand how different species have evolved and diversified from common ancestral forms.

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The pericytes used in these experiments were probably in which phase of the cell cycle

Answers

Answer: Interphase

The pericytes are in the interphase of the cell cycle. This is the phase of the cell cyclebetween each cell division and is the phase in which the cell obtains nutrients,grows, reads its DNA, and conducts other normal cell functions including thearrest of the growth of the pericytes that were treated so that they would notdivide but continue to function normally.

Now that you have come up with an equation that describes the relationship between amounts of different nucleotide bases in DNA, can you use it to predict the amounts of all four nucleotide bases when you only know the amount of one type of base? Approximately 21% of the human genome is comprised of nucleotides containing C. Given this information, calculate the percentage of the human genome that is comprised of nucleotides containing G, T, and A. (a) _____% of the human genome is comprised of G.(b) _____% of the human genome is comprised of T.

(c) _____% of the human genome is comprised of A.

Enter your answer as three numbers separated by commas (example: 12, 26, 32).

Answers

Answer:

The correct answer will be- 21, 29, 29

Explanation:

In a DNA sequence, the nucleotide base pairs on one strand of DNA are  complementary to the base pair on other strand of DNA.

According to the Chargaff rule, Adenine binds Thymine and Cytosine binds Guanosine which shows that the amount of A will equal T and the amount of G will equal C.

Therefore, when the amount of C is 21%, then the amount of G will be 21%.

To find amount of AT= 100-GC

                              AT= 100-42

                                AT= 58%

So, AT/2= 29% each

Thus, A=T= 29%

          G=C=21%