Which radioisotope has an atom that emits a particle with a mass number of 0 and a charge of +1?(1) 3H (3) 19Ne
(2) 16N (4) 239Pu

Answers

Answer 1

Answer:

The radioactive isotope of the element with unstable energy in the nucleus is called a radioisotope. Neon with atomic mass 19 particlehas charge +1 and mass 0.

What are the radioactive particles?

When a radioactive element undergoes decay they emit some types of particles like alpha, beta, or positron particles. The alpha particle has a +2 charge and a mass number of 4.

The beta particle has a -1 charge and a mass number of 0, while the positron has a particle charge of +1 and a mass number of 0.

In the decay of the Neon element, the positron is emitted can be shown as:

$\rm ^(19)_(10)Ne \rightarrow ^(19)_(9)F + ^(0)_(+1)\beta$

Therefore, option 3. $\rm ^(19)Ne$ atom emits positron particle.

Learn more about radioisotopes here:

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Answer 2

Answer:

Answer: The correct answer is option 3.

Explanation: There are three types of particles that are emitted when a radioisotope undergo decay process:

1. Alpha particle: This particle is emitted when a radioisotope undergoes alpha decay process. The charge on the particle is +2 and mass number is 4.

$_Z^A\textrm{X}\rightarrow _(Z-2)^(A-4)\textrm{Y}+_2^4\alpha$

2. Beta-particle: This particle is emitted when a radioisotope undergoes beta-minus decay process. The charge on the particle is -1 and mass number is 0.

$_Z^A\textrm{X}\rightarrow _(Z+1)^(A)\textrm{Y}+_(-1)^0\beta$

3. Positron particle: This particle is emitted when a radioisotope undergoes beta-plus decay process. The charge on the particle is +1 and mass number is 0.

$_Z^A\textrm{X}\rightarrow _(Z-1)^(A)\textrm{Y}+_(+1)^0\beta$

For the given options undergoing decay processes:

Option 1:

$_1^3\textrm{H}\rightarrow _(2)^(3)\textrm{He}+_(-1)^0\beta$

It emits beta-particle.

Option 2:

$_7^(16)\textrm{N}\rightarrow _(8)^(16)\textrm{O}+_(-1)^0\beta$

It emits beta-particle.

Option 3:

$_(10)^(19)\textrm{Ne}\rightarrow _(9)^(19)\textrm{F}+_(+1)^0\beta$

It emits positron-particle.

Option 4:

$_(94)^(239)\textrm{Pu}\rightarrow _(92)^(235)\textrm{U}+_2^4\alpha$

It emits alpha particle.

Hence, the correct option is Option 3.

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What is the difference between a cup of tea at 95°C, and a drop of tea at 95°C?

Answers

Answer:

See the explanation below

Explanation:

Both the cup of coffee and drop of coffee have the Same temperature of 95°C.

Although the difference is the cup of coffee has more heat contained in it than the drop of coffee. An explanation is when we heat a cup of coffee it will take more time to Attain in 95°C while the drop of coffee will take less time

Final answer:

The difference between a cup and a drop of tea at the same temperature is largely related to their different quantities, affecting the heat capacity and cooling rate. The cup has a higher heat capacity and cools down slower, while the drop cools down faster.

Explanation:

The difference between a cup of tea at 95°C and a drop of tea at 95°C is primarily a matter of quantity and its implications on heat capacity and cooling rate.

Both the cup and the drop of tea are at the same temperature, 95°C, however, the cup of tea contains a larger quantity or volume of tea. This means the cup of tea has a higher heat capacity.

What this signifies is that it would take more energy to change the temperature of the cup of tea than the drop of tea. Conversely, the drop of tea, having a lower heat capacity, will cool down faster than the cup. The larger volume and surface area of the cup of tea allows it to contain more heat and thus, lose heat slower than a drop.

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What is most likely true about ocean temperatures surrounding Australia, which is marked by the star in the following map?Map showing the Ocean Conveyor belt. A cold current runs west to east, south of Australia. The current then reverses course in the Pacific Ocean, so that a warm current flows east to west, north of Australia.

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A. The ocean temperatures north of Australia are lower than the ocean temperatures south of Australia
B. The ocean temperatures north of Australia are higher than the ocean temperatures south of Australia
C. The ocean temperatures north of Australia are the same as the ocean temperatures south of Australia.
D. The ocean temperatures north of Australia are sometimes higher and sometimes lower than the ocean temperatures south of Australia.

Answers

The answer that is most likely true about ocean temperatures surrounding Australia, which is marked by the star in the following map is that b) the ocean temperatures north of Australia are higher than the ocean temperatures south of Australia.

Answer:

B. The ocean temperatures north of Australia are higher than the ocean temperatures south of Australia

Explanation:

When are tides highest?

Answers

A neap tide is the highest tide there is, this is due to the position of the moon,since the moon and sometimes the earth are what cause the tides in the ocean.

How many mole ratios can be written for a chemical reaction involving 3 substances

Answers

Answer : 3 substance will have 3 mole ratios to be written for a chemical reaction.

Explanation : The mole ratio can be defined as the ratio between the amounts in moles of any two or more compounds involved in a chemical reaction.

It can be determined by comparing the coefficients the formulas of a balanced chemical equation. It is also known as the molar ratio or mole-to-mole ratio.

Hence, when 3 substances are involved in a chemical reaction 3 mole ratios can be written for it.

There can be three mole ratios that can be written involving three substances.It depends on the constant of your reactant to your product. It also depends on the asked mole ratio. But the maximum would be 3 mole ratios because you have 3 substances in your reaction.

State the number of solutions for Matrix B. a. No Solution b. One Solution c. Infinitely Many Solutions

Answers

Answer:

C. Infinitely Many Solutions

Explanation:

No solution case : This is the case when all given variables are not equal to any constant, for example: there is one row of zeros in matrix e.g 0=3. matrix B don't have any zero row. So, Not True.

One Solution case: This is the case when all variables are independent variables like if they are equal to some constant. e.g x=1,y=2,z=4 , Matrix B have more than one variable in first row due to which it made equation look like x+y=-5. so matrix B can't have only one solution. So, Not True.

Infinitely Many Solutions case: when there is one or more variables which is not equal to any constant and acting as linearly dependent variable, then that matrix have infinite solutions. Matrix B have that variable which is linearly dependent as show in the attachment solution. So, True.

1. Quando absorvido pelos pulmões, o monóxido de carbono reduz a habilidade do sangue no transporte do oxigênio pelo corpo. Este fato ocorre devido à formação de um complexo com a hemoglobina do sangue, que é mais estável do que o complexo formado entre esta e o oxigênio.CO(g) + Hem.O2(aq) ⇌ O2(g) + Hem.CO (aq)

A constante de equilíbrio para a reação é de Kc = 210.

Um fumante está exposto a uma concentração de CO na ordem de 2,1 x 10-6 mol.L-1. Sabendo que a concentração de O2 no sangue é de 8,8 x 10-3 mol.L-1, podemos considerar corretas as afirmações:

I) 5% da hemoglobina do sangue está contaminado com o complexo de CO.
II) O valor elevado da constante de equilíbrio indica que a grande maioria das moléculas de hemoglobina está ligada às moléculas de CO.
III) A concentração de Hem.CO no equilíbrio é 210 vezes maior do que a concentração de Hem.O2.

I e III

I apenas

III apenas

I e II

II apenas

2. O ozônio é um gás atmosférico que se concentra na estratosfera e funciona como um escudo protegendo a Terra dos efeitos nocivos dos raios solares. Alguns compostos orgânicos à base de cloro podem chegar à estratosfera e, na presença da luz ultravioleta, sofrer quebra de algumas ligações, produzindo radicais cloro. Estes radicais reagem com o ozônio, provocando uma redução da concentração desse, o que pode ser representado pela sequência de reações no diagrama apresentado a seguir.

Etapa 1: Cl• + O3 → ClO• + O2

(sabendo que, O2 λu.v O• + O•)

Etapa 2: ClO• + O• → Cl• + O2

Com base no diagrama, podemos afirmar que:

I – A energia de ativação da reação não catalisada é de 17,1 kJ.
II – A reação envolvendo o radical cloro é mais lenta, pois ocorre em duas etapas.
III – A energia de ativação da etapa 1 é de 2,1 kJ.
IV – A etapa 2 deve ser mais lenta do que a 1.

Pela análise das equações químicas e do diagrama, podem-se considerar corretas apenas as afirmações:

II e III

I e II

II e IV

I e III

I e IV

3. A tabela a seguir apresenta os resultados de um experimento realizado por um aluno com comprimidos antiácidos efervescentes. Em cada sistema, o aluno utilizou a mesma quantidade de comprimidos efervescentes, os quais apresentavam a mesma massa, porém alguns estavam triturados e outros inteiros.

Ao analisar esses dados, quanto aos comprimidos que deveriam estar triturados e as velocidades de reação, o aluno concluiu que:

a velocidade de reação de I é maior do que em III, devido ao aumento da temperatura e da superfície de contato.

o comprimido usado no sistema II deve estar triturado, e o usado no sistema III deve estar inteiro, pois a velocidade em III é menor do que em IV.

devido ao aumento da superfície de contato e da temperatura, a velocidade de reação em II é maior do que em IV.

apenas no sistema IV o comprimido estava triturado e a velocidade de reação diminui com o aumento da temperatura do sistema.

os comprimidos utilizados em I e III devem estar triturados, pois a velocidade da reação é maior nesses sistemas quando comparadas aos outros dois.

4. Os óxidos de nitrogênio são encontrados na natureza com diferentes combinações, sendo que N2O, NO e NO2 são os que se apresentam em quantidades significativas. O NO pode ser formado por processos de combustão, e uma possível causa pode ser a reação do nitrogênio com o oxigênio na atmosfera, que poderia ser expressa por:

N2(g) + O2(g) ⇌ 2NO ΔH = + 180,8kJ

A presença de NO na atmosfera pode contribuir para o smog fotoquímico. É como se um forte nevoeiro envolvesse a cidade. Este fenômeno decorre do fato de as reações dos óxidos presentes na atmosfera serem ativadas pela ação da luz, das quais a principal é a dissociação do dióxido de nitrogênio: NO2(g) → NO(g) + O (g).

Em Los Angeles, quando este fenômeno foi observado pela primeira vez, a concentração de NO atingiu um pico de 1,7x10-8 mol.L-1.

Supondo que para o sistema em equilíbrio N2(g) + O2(g) ⇌ 2NO ΔH = + 180,8kJ, cuja constante de equilíbrio é da ordem de Kc = 1 x 10-30 e as concentrações de N2 e O2, em mol.L-1, sejam respectivamente, 0,040 e 0,010 mol.L-1 a 25°C, podemos afirmar que:

Teremos uma alta concentração de NO contribuindo para a formação do smog fotoquímico.

O aumento da pressão atmosférica favorece a formação do smog fotoquímico.

[NO] = 2 x 10-17 mol.L-1 e Los Angeles não apresentariam o fenômeno do smog fotoquímico.

O aumento da temperatura evitaria a formação do smog fotoquímico.

Nessa condição, ocorre uma diminuição significativa da concentração de O2 no ar.