A 220.0-mL sample of helium gas is in a cylinder with a movable piston at 105 kPa and 275 K. The piston is pushed in until the sample has a volume of 95.0 mL. The new temperature of the gas is 310. K. What is the new pressure of the sample?(1) 5l.1 kPa(2) 216 kPa(3) 243 kPa(4) 274 kPa

Answers

Answer 1

Answer: 4. This problem is really simple if you realize that you can use the combined gas law:

P1V1/T1 = P2V2/T2

Therefore, just substitute in and solve:

(105 kPa)(220.0 mL)/(275K) = ?kPa(95.0 mL)/(310 K)
Solve for ?
Answer is 274. kPa

Answer 2

Answer:

The new pressure of the sample of helium gas in a cylinder with a movable piston is 274 kPa.

Option 4)274 kPa is the correct answer.

What is Combined gas law?

Combinedgas law put together both Boyle's Law, Charles's Law, and Gay-Lussac's Law. It states that "the ratio of the product of volume and pressure and the absolute temperature of a gas is equal to a constant.

It is expressed as;

P₁V₁/T₁ = P₂V₂/T₂

Given the data in the question;

Initial volume V₁ = 220.0mL = 0.22L

Initial pressure P₁ = 105kPa = 1.03627atm

Initial temperature T₁ = 275K

Final volume V₂ = 95.0mL = 0.095L

Final temperature T₂ = 310K

Final pressure P₂ = ?

To calculate the new temperature of the gas, we substitute our given values into the equation above.

P₁V₁/T₁ = P₂V₂/T₂

P₁V₁T₂ = P₂V₂T₁

P₂ = (P₁V₁T₂) / V₂T₁

P₂ = ( 1.03627atm × 0.22L × 310K ) / ( 0.095L × 275K )

P₂ = 70.673614LatmK / 26.125LK

P₂ = 2.705atm

P₂ = (2.705 × 101.325)kPa

P₂ = 274 kPa

The new pressure of the sample of helium gas in a cylinder with a movable piston is 274 kPa.

Option 4)274 kPa is the correct answer.

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Compared to the mass and the penetrating power of an alpha particle, a beta particle has(1) less mass and greater penetrating power(2) less mass and less penetrating power
(3) more mass and greater penetrating power
(4) more mass and less penetrating power

Answers

Answer is (1) - less mass and greater penetrating power.

Alpha particle is a ₂⁴He nucleus while beta particles are electrons. Hence, the mass of alpha particle is greater than the mass of beta particle. But, the penetrating power is higher in beta particle than alpha particle. Alpha particles can be blocked by few papers but beta particles can go through those papers.

Answer: A beta particle has less mass and greater penetrating power.

Explanation:

Penetrating power is the power with which a particle travels or pass through a substance.

Since, it is known that mass of an alpha particle ( $^(4)_(2)He$ ) is more than the mass of a beta particle ( $^(0)_(-1)e$ ). So, a particle that holds less mass can move easily from one place to another.

Therefore, beta particle can move faster as it has only one electron as compared to 2 protons of an alpha particle. Hence, interaction of beta particles is less with the atoms or materials through which it passes.

Therefore, we can conclude that compared to the mass and the penetrating power of an alpha particle, a beta particle has less mass and greater penetrating power.

What is the name of the hydrocarbon CH3(CH2)6CH3?

Answers

The carbon atoms bind together to create the compound's framework. Therefore, the name of the hydrocarbon CH $_3$ (CH $_2$ ) $_6$ CH $_3$ is n-octane.

What is hydrocarbon?

Any member of a group of organic compounds comprised only of the atoms carbon (C) as well as hydrogen (H) (H). The carbon atoms bind together to create the compound's framework, as well as the hydrogen atoms connect to them in a variety of ways.

Petroleum as well as natural gas are mostly composed of hydrocarbons. They are used as fuels and lubricants, as well as raw materials to make polymers, fibers, rubbers, solvents, explosives, various industrial chemicals. The name of the hydrocarbon CH $_3$ (CH $_2$ ) $_6$ CH $_3$ is n-octane.

Therefore, the name of the hydrocarbon CH $_3$ (CH $_2$ ) $_6$ CH $_3$ is n-octane.

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Answer is: n-octane.

Octane is the straight-chain alkane (an acyclic saturated hydrocarbon) with eight carbon atoms.

Carbons in octane have sp3 hybridization (carbon’s 2s and three 2p orbitals combine into four identical sp3 orbitals).

Orbitals in sp3 hybridization have a tetrahedral arrangement and form single (sigma) bonds.

Burning octane fuel is very fast chemical reaction, it happens in immediately.

Main products of the combustion of fossil fuels are carbon(IV) oxide and water.

Chemical reaction: C₈H₁₈ + 25/2O₂ → 8CO₂ + 9H₂O; ΔH = -5500 kJ/mol.

Which of the following is not produced by nuclear decay?A) Alpha particles
B) Beta particles
C) Gamma rays
D) Delta particles

Answers

The answer is D. Delta particles.

Currently, there are three main types of nuclear decay: alpha decay, beta decay, and gamma decay. All three involve the emission of certain radioactive particles from the nuclear decay of an unstable atom. These particles are the alpha particles, beta particles, gamma rays, and conversion electrons.

Air tends to move from _____.a. the equator to the poles
b. conduction
c. cold air rising and warm air sinking
d. radiation

Answers

Answer:

cold air rising and warm air sinking

Explanation:

Convection is well known in nature. During convection, warm particles rise above the surface while cooler particles sink below. Hence a convection current is set up.

Air moves by convection. Hot air rises and moves toward and is then replaced with cooler air. A typical application of convection in nature is land and sea breeze.

i would say a. at the equator to the poles or maybe c. cold air rising and warm air sinking.

CaSO3 (s) → → → → CaO (s) + SO2 (g)

What mass of CaSO3 must have been present initially to produce 14.5 L of SO2 gas at a temperature of 12.5°C and a pressure of 1.10 atm?

Answers

Using the ideal gas law, the number of moles SO2 is equal to PV/RT, or pressure times volume divided by the gas constant and temperature. This is 14.5*1.1/((2.5+279.15)*.082), or 0.66 moles. Since one mole CaSO3 is consumed for every mole SO2 generated, 0.66 moles of CaSO3 are consumed. CaSO3 has a molar mass of 40+32+16*3=120 grams, so .66 moles of CaSO3 is equal to 80 grams, our final answer.

Convert 55 kilometers per hour into meters per second. Use the conversion factor 1 km = 1000 m.55 ______/ _____ ´ 1000 _____/1 ______ ´ 1 ______/60 ______
´ 1 _____/60 _____ = 15 _____