What is the answer 3.5r=3(4+.5r)?

Answers

Answer 1

Answer: $3.5r=3(4+0.5r)\n\n3.5r=3*4+3*0.5r\n\n3.5r=12+1.5r\ \ \ \ \ |substract\ 1.5r\ from\ both\ sides\n\n2r=12\ \ \ \ \ \ |divide\ both\ sides\ by\ 2\n\nr=6$

Answer 2

Answer: The 'answer' is the number that 'r' must be in order to make the equation a true statement. There's only one number that can do it. Here's how to find it:

Copy the equation: 3.5r = 3(4 + .5r)

Expand the right side: 3.5r = 12 + 1.5r

Subtract 1.5r from each side: 2r = 12

Divide each side by 2 : r = 6

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Craig has £13.40 he sees this offer in a restaurant :main courses £8.90 each.Buy one main course and get the second half price. Can he afford to buy two main courses?Show your working
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On Novenber 4, your bank statement shows a balance of $2,253.18. Your checkbook shows a balance of $2,324.34. If there are outstanding checks in the amounts of $105.50 and $158.10, deposits in transit amount to $605.27, account earnings of $68.51 and there is a service charge of $5.00. Determine the Adjusted Checkbook Balance and the Adjusted Statement Balance.

Answers

Answer:

The final answer is "$2387.85 and $2594.85".

Step-by-step explanation:

Given values:

The bank statement balance= $2,253.18

The checkbook balance = $2,324.34

outstanding check amounts= $105.50 and $158.10

transit amount= $605.27

account earnin(credits)= $68.51

service charge= $5.00

Adjusted Checkbook Balance =?

Adjusted Statement Balance=?

Adjusted the Checkbook Balance:

checkbook balance = $2,324.34

$\text{total checkbook balance = checkbook balance+ credits}\n$

$= \$ 2,324.34+ \$ 68.51\n\n= \$ 2392.85$

$\text{ Adjust check book balance= total checkbook balance - servicec charge}$

$= \$2392.85 - \$5.00\n\n= \$ 2387.85$

Adjusted the Statement Balance:

bank statement balance= $2,253.18

$\text{total Statement balance = bank Statement balance+ transit amount}\n$

$= \$ 2,253.18+ \$ 605.27\n\n= $ 2,858.45$

$\text{outstanding check amounts = $105.50+ $158.10}$

$= \$263.60$

$\text{ Adjust statement balance= total statement balance - outstanding check amount }$ $= \$ 2,858.45 - \$263.60\n\n= $ 2,594.85$

Find the area and perimeter of an isosceles trapezoid with a 60° base angles and bases 9 and 13.

Answers

The area and perimeter of an isosceles trapezoid with a 60° base angles and bases 9 and 13 is 38.105 squared units and 24 units respectively.

What is area and perimeter of the isosceles trapezoid?

The area of the isosceles trapezoid is the space occupied by it. It can be find out using the following formula,

$A=(a+b)/(2)* h$

Permiter of the isosceles trapezoid is the total length of the boundary by which it is enclosed. It can given as,

$P=a+b+2c$

Here (a,b) are the base side (c) is the side of leg and (h) is the height.

The image of the given isosceles trapezoid is attached below. Let the value of leg is x units. Thus using right angle property the cos theta is,

$\cos60=(2)/(x)\nx=1$

And the height of this trapezoid is,

$\tan60(h)/(2)\nh=3.46$

Thus the area of the solid is,

$A=(9+13)/(2)* 3.46\nA=38.105\rm\; units^2$

The perimeter of the solid is,

$P=9+13+2*1\nP=24\rm\; units$

Thus, the area and perimeter of an isosceles trapezoid with a 60° base angles and bases 9 and 13 is 38.105 squared units and 24 units respectively.

Learn more about the area of the isosceles trapezoid here;

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The trapezoid has two right triangles each with one side of length (13-9)2 = 4/2 = 2.

The other side of each right triangle is such that tan 60° = Heigth / 2

Then height = 2*tan60°.

The area of the trapezoid is height * (base 1 + base 2)/2

Then area = 2*tan (60°) * (13+9)/2 = 38.11

I am confused on numbers 25 and 29, the instructions are at the top.

Answers

#25 is fairly simple. Plug in -4 and 3 into the equation, and the extraneous root will be the one that does not work.
$√(12-(-4)) = √(16) = \frac{+}{}4$
Extraneous root in this case is positive four since +4≠-4
$√(12-3) = √(9) = \frac{+}{}3$
In this case it's negative 3, since -3≠3

#29 can be turned into a quadratic equation.
$x= √(2x+3)$
Square both sides to get
$x^(2)=2x+3$
Then bring the 2x+3 to the other side, setting the quadratic equal to zero.
$x^(2)-2x-3=0$
Factor to find that it's equivalent to
(x-3)(x+1)=0
Therefore x is equal to positive 3 and negative 1. Plug both back into the original equation. Whichever does not work is the extraneous root, and the answer is the one that does.
$x= √(2x+3)$
$3= √(2(3)+3)$
$3= √(9)$
Extraneous root would be negative 3.

$-1= √(2(-1)+3)$
$-1= √(1)$
Extraneous root would be positive 1.

Your answers are positive 3 and negative 1.
Extraneous roots are negative 3 and positive 1.

a spherical fountain il has a radius of 1.5 feet. find the volume of the fountain to the nearest tenth of a cubic foot

Answers

The volume of a sphere is given by the formula V = (4/3)πr^3, where r is the radius of the sphere.

Substituting the given value of r = 1.5 feet, we get:

V = (4/3)π(1.5)^3

V ≈ 14.1 cubic feet (rounded to the nearest tenth)

Therefore, the volume of the spherical fountain is approximately 14.1 cubic feet.

Lines l and m are intersected by transversal t and l || m. Select all of the angles that are congruent to 25

Answers

Answer:

A. <1

D. <4

F. <8

Step-by-step explanation:

Given that lines l and m that are crossed by transversal t, the following angles are congruent to <5:

<8 = <5 (vertical angles)

<1 = <5 (corresponding angles)

<4 = <5 (alternate interior angles)

Therefore, the angles that are congruent to <5 are labelled <8, <1, and <4.

Final answer:

The angles congruent to a given angle in a set of parallel lines intersected by a transversal are the corresponding angle, the alternate interior angle, and the alternate exterior angle on the other side of the transversal.

Explanation:

In geometry, when two lines are parallel (l || m) and intersected by a transversal (t), the angles that are formed have certain relationships. Here, if one angle measures 25 degrees, then the angles congruent (equal in measure) to this angle are: the corresponding angle on the other side of the transversal, the alternate interior angle on the other side of the transversal, and the alternate exterior angle on the other side of the transversal. This is because parallel lines cut by a transversal create corresponding angles, alternate interior angles, and alternate exterior angles that are all congruent.

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Which polynomial is prime?x2 – 36

x2 + 16

x2 – 7x + 12

x2 – x – 20

Answers

x2+16 is the prime polynomial.
x2+16 is the only polynomial that couldn't be factored out anymore

x2-36 --> (x-6)(x+6)
x2-7x+12 --> (x-3)(x-4)
x2-x-20 --> (x+5)(x-4)

Answer:

x^2+16

Step-by-step explanation:

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