MATHEMATICS HIGH SCHOOL

A man invests a certain amount of money at 2% interest and $800 more than that amount in another account at 4% interest. At the end of one year, he earned $92 in interest. How much money was invested in each account?A) $1,500 at 2%; $2,300 at 4%
B) $1,400 at 2%; $2,200 at 4%
C) $1,000 at 2%; $1,800 at 4%

Answers

Answer 1
Answer:

Answer: Option 'C' is correct.

Step-by-step explanation:

Since we have given that

Let the principal amount be 'x'.

First rate of interest = 2%

Second rate of interest = 4%

Number of years = 1

Amount of interest he earned = $92

According to question,

(x* 2)/(100)+((x+800)* 4)/(100)=92\n\n(2)/(100)(x+2(x+800))=92\n\nx+2x+1600=(92* 100)/(2)\n\n3x+1600=4600\n\n3x=4600-1600\n\n3x=3000\n\nx=(3000)/(x)\n\nx=\$1000

So, First investment of $1000 at 2% and Second investment of $1000+$800=$1800 at 4%.

Hence, Option 'C' is correct.
Answer 2
Answer: x the first account  interest = x/100*2 = 2x/100 
(x + 800)/100 * 4 =( 4x + 3200)/100 
2x/100 + (4x + 3200)/100 = 92
2x + 4x + 3200 = 9200 
6x = 6000
x = 1000
C is the answer

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Answers

The equation that models this relation is y = 70/x. So, option (D) is the correct answer.

What is constant of proportionality?

The constant of proportionality is the ratio of two proportional values at a constant value. Two variable values have a proportional relationship when either their ratio or their product gives a constant.

For the given situation,

The values are y = 10 and x = 7

y varies inversely with x.

⇒ y ∝ (1)/(x)

To remove proportionality we introduce a constant 'k'.

⇒ y=(k)/(x)

Substitute the values of x and y,

⇒ 10=(k)/(7)

⇒ k=70

Now substitute the value of k = 70 in y,

⇒ y = (70)/(x)

Hence we can conclude that the equation that models this relation is      y = 70/x. So, option (D) is the correct answer.

Learn more about constant of proportionality here

brainly.com/question/21328304

#SPJ2
So the answer would be d

Hope that helped!;)

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Answers

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Answers

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Answers

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Answers


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