A chemist dilutes a 1.0 mL sample of 2.0 M KNO3 by adding water to it. If the concentration of the solution that is obtained is 0.0080 M, what is its volume?Use: Mi Vi = Mf Vf
A.) 125 mL
B.) 250 mL
C.) 500 mL
D.) 2,000 mL
Answers
Vi = 1.0 mL
Mf = 0.0080 M
Vf = ?
Mi * Vi = Mf* Vf
2.0 * 1.0 = 0.0080 * Vf
2 = 0.0080* Vf
Vf = 2 / 0.0080
Vf = 250 mL
answer b
hope this helps!.
Answer: Option (B) is the correct answer.
Explanation:
The given data is as follows.
= 2.0 M,
= 1.0 ml
= 0.008 M,
= ?
Therefore, calculate the volume of given solution as follows.
=
Now, putting the given values into the above formula as follows.
=
=
= 250 ml
Therefore, volume of the solution obtained is 250 ml.
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The pH of a 0.027 M KOH solution is 12.4 and since KOH is a strong base it will dissociate completely in the solution
How do we calculate?
KOH is a strong base, so it will dissociate completely in solution to form potassium ions and hydroxide ions. The concentration of hydroxide ions will be equal to the concentration of KOH, which is 0.027 M.
The pH of a solution can be calculated using the following equation:
pH = -log[H+]
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The concentration of hydrogen ions in a basic solution is very low, so we can use the approximation that:
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POH = - log [ OH⁻]
POH = - log [ 0.027 ]
POH = 1.56
PH + POH = 14
PH + 1.56 = 14
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hope this helps!
Answers
When forming the ion Cr3+, the new electronic configuration will be 1s2 2s2 2p6 3s2 3p6 3d3. We can see that 3 electrons are removed from the valence shell following the order of the highest energy orbitals to lower energy.
b. The valence electrons stay in a single orbital.
c. The valence electrons break free of the crystals.
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Answers
Answer: THE answer is A
Explanation: took the exam
Answers
Answer:2.50 moles of magnesium will consume approximately 182.30 grams of hydrochloric acid in the given reaction.
Explanation:To find out how many grams of hydrochloric acid (HCl) are consumed when 2.50 moles of magnesium (Mg) react with it, you can use stoichiometry and the balanced chemical equation:
Mg(s) + 2HCl(aq) -> MgCl2(aq) + H2(g)
From the balanced equation, you can see that 1 mole of magnesium (Mg) reacts with 2 moles of hydrochloric acid (HCl).
Now, let's use this information to calculate the moles of HCl required to react with 2.50 moles of Mg:
Moles of HCl = (2.50 moles Mg) * (2 moles HCl / 1 mole Mg)
Moles of HCl = 2.50 moles * 2
Moles of HCl = 5.00 moles
Now that we know we need 5.00 moles of HCl, we can calculate the grams of HCl needed using the molar mass of HCl:
The molar mass of HCl is the sum of the atomic masses of hydrogen (H) and chlorine (Cl):
Molar mass of HCl = 1.01 g/mol (for hydrogen) + 35.45 g/mol (for chlorine)
Molar mass of HCl = 36.46 g/mol
Now, calculate the grams of HCl:
Grams of HCl = (5.00 moles) * (36.46 g/mol)
Grams of HCl = 182.30 grams
So, 2.50 moles of magnesium will consume approximately 182.30 grams of hydrochloric acid in the given reaction.
Answers
The chemical formula for glycerol is HOCH2-CH(OH)-CH2OH while that of water is H-OH. The intermolecular forces in both water and glycerol are the strong H-bonds. However, since there are 3 OH groups/ glycerol molecule vs the one -OH group in water enables glycerol to form more H-bonds when compared to water.
The stronger attractive forces in glycerol causes an increase in its boiling point.
Answer: Glycerol has more attractive forces as compared to water.
Explanation:
Boiling point is the temperature at which vapor pressure of the liquid becomes equal to atmospheric pressure.
Boiling point depends on the strength of inter molecular forces.
The molecules of glycerol are more strongly bonded through hydrogen bonds as there are three OH groups.
But in water , only on e OH group is present and thus extent of hydrogen bonding is less.
Thus we can conclude that glycerol has more attractive forces as compared to water.
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Answers
The correct pair of compounds that are isomers is CH₃COCH₃ and CH₃CH₂CHO and the correct option is option 4.
Isomers are compounds that have the same molecular formula but different structural arrangements or connectivity of atoms.
Among the given options, the pair of compounds that are isomers is CH₃COCH₃ (acetone) and CH₃CH₃CHO (propanal). Both compounds have the molecular formula C₃H₆O, but they differ in their structural arrangement.
Acetone is a ketone, with a carbonyl group located in the middle of the carbon chain, while propanal is an aldehyde, with the carbonyl group located at the end of the carbon chain.
These structural differences result in distinct chemical properties and reactivities of the compounds.
Thus, the ideal selection is option 4.
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